1. August 30, 2004Sylke Boyd, Phys 1061 Tree 1 Tree 2 Tree 3 Tree 4 Tree 5 Tree 6 Tree 7 Tree 0 t = 0 s t = 1 s Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 t = 2 s t = 3 s t = 4 s t = 6 s

2. August 30, 2004Sylke Boyd, Phys 1061 Tree 1 Tree 2 Tree 3 Tree 4 Tree 5 Tree 6 Tree 7 Tree 0 t = 0 s t = 1 s Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 t = 2 s t = 3 s t = 4 s

3. August 30, 2004Sylke Boyd, Phys 1061 Position (tree) Time (s) 1 2 3 4 5 6 1 3 5

4. August 30, 2004Sylke Boyd, Phys 1061 Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 What curve do you expect for a biker who decelerates? acceleration Constant speed deceleration

5. August 30, 2004Sylke Boyd, Phys 1061 Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 What is this biker doing? Standing still at the 4 th tree Slope = 0 v=0 a=0 Tree 1 Tree 2 Tree 3 Tree 4 Tree 5 Tree 6 Tree 7 Tree 0

6. August 30, 2004Sylke Boyd, Phys 1061 Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 What is this biker doing? Coming back to tree 0 Slope = -4trs/6 s v=-0.7 trs/s a=0 Tree 1 Tree 2 Tree 3 Tree 4 Tree 5 Tree 6 Tree 7 Tree 0

7. August 30, 2004Sylke Boyd, Phys 1061 Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 What is this biker doing? Tree 1 Tree 2 Tree 3 Tree 4 Tree 5 Tree 6 Tree 7 Tree 0 He is decelerating, reversing direction, and increasing his speed again.

8. August 30, 2004Sylke Boyd, Phys 1061 Position (tree) Time (s) 1 2 3 4 5 6 1 3 5 How should the graph look for two bikers coming toward each other at constant speeds? Tree 1 Tree 2 Tree 3 Tree 4 Tree 5 Tree 6 Tree 7 Tree 0