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Today Today: Begin Chapter 3 Reading: –Covered 2.1-2.5 from Chapter 2 –Please read Chapter 3 –Suggested Problems: 3.2, 3.9, 3.12, 3.20, 3.23, 3.24, 3R5,

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Presentation on theme: "Today Today: Begin Chapter 3 Reading: –Covered 2.1-2.5 from Chapter 2 –Please read Chapter 3 –Suggested Problems: 3.2, 3.9, 3.12, 3.20, 3.23, 3.24, 3R5,"— Presentation transcript:

1 Today Today: Begin Chapter 3 Reading: –Covered 2.1-2.5 from Chapter 2 –Please read Chapter 3 –Suggested Problems: 3.2, 3.9, 3.12, 3.20, 3.23, 3.24, 3R5, 3R9

2 Example Have 50 men, each 26 years old Have 50 women, each 28 years old What is the average age of the 100 people?

3 Example Have 500 men, each 26 years old Have 50 women, each 28 years old What is the average age of the 100 people?

4 Example Recall the game show, Let’s Make a Deal A contestant had won $9,000 in prizes, and was offered to exchange the gifts for whatever lay behind one of three doors Behind one door was a $20,000 prize and behind the others were $5,000 and $2,000 prizes, respectively Should the contestant make the exchange?

5 Expectation (The Mean) If X is a discrete random variable with probability mass function f(x), the expected value (or mean value) is Provided the sum is absolutely convergent (if there are infinitely many values x 1,x 2,… ) Idea, the mean is the weighted average of the possible values of X

6 Example Recall the game show, Let’s Make a Deal A contestant had won $9,000 in prizes, and was offered to exchange the gifts for whatever lay behind one of three doors Behind one door was a $20,000 prize and behind the others were $5,000 and $2,000 prizes, respectively Should the contestant make the exchange?

7 Example (True Story) When Derek was a graduate student in Vancouver, parking was $9.00/day If you parked illegally, the ticket was $10.00 Derek discovered that he got a ticket about 50% of the time Which is the better strategy: –Pay $9.00/day –Park illegally

8 Properties of Expectation For random variables X and Y, –E(c)=c, where c is a constant –E(cX)=cE(X), where c is a constant –E(X+Y) = E(X) + E(Y) –E(aX+bY+c) = aE(X) + bE(Y)+c, where a,b, and c are constants

9 Example Two dice are rolled – one red and one green Let X be the outcome of the red die and Y be the outcome of the green die Find E(X+Y)

10 Conditional Mean Conditional distributions also have means The mean will be conditional on the value of another random variable The conditional mean of Y give X=x is

11 Example Three digits are picked at random, without replacement, from 1,2, …, 8 Let Y denote the largest digit and X denote the smallest Find the probability function for Y Find E(Y) Find probability function for Y given X=3 Find E(Y|X=3)

12 Expected Value of a Function After observing a random variable, often interested in some function of the random variable The mean value of a function, g, of a random variable X is:

13 Example (3.1) Consider a random variable X, with probability function f below: Find E(X 2 ) x01234 f(x).1.3.1.2

14 Example (3.10) Recall the game show, Let’s Make a Deal A contestant had won $9,000 in prizes, and was offered to exchange the gifts for whatever lay behind one of three doors Behind one door was a $20,000 prize and behind the others were $5,000 and $2,000 prizes, respectively Suppose that the contestant owes a murderous loan shark $9000, due the next day Can use a utility function to help express thenotion of expectation in this situation

15 Expected Values and Joint Distributions Some useful relations: How do we get these?

16 Expected Values and Joint Distributions When random variables X and Y are independent, How did we get this?


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