1. Solve for the unknown:

2. Answer:

3. Describe part 3 in the graph below. Include details about time, speed, direction and distance.

4. Answer Emily drove 10 km in 20 minutes at 0.5 km/minute away from home.

5. Compare direct and partial variation.

6. Answer Both direct and partial variation are a straight line when graphed, but direct variation starts at (0,0) and partial variation does not start at (0,0).

7. Write an equation to represent this situation. Let M be the amount of money earned, and let b be the number of bags of leaves raked.

8. Answer M = 5b + 10

9. Write an equation to represent this situation: Katrina noticed fraudulent activity in her bank account. Her account originally had $400 in it, but the balance has gone down by $25 each week. Let B be the balance in the account and let w be the number of weeks.

10. Answer B = -25w + 400

11. Using the equation from the last question, if there is only $225 left in the account, how many days has the fraudulent activity been going on for?

12. Answer Therefore if $225 remains, then the fraudulent activity has been going on for 7 weeks.

13. Calculate the slope of the line on the graph:

14. Answer

15. Calculate the slope of the line joining the following points: A (1,-4) and B (6,6)

16. Answer

17. Does the table below represent a linear or non-linear relation? Explain your answer. xy -210 08 25 41

18. Answer The table represents a non-linear relation. Although the pattern in the x’s is constant, the first differences (differences in the y- values) are not constant.

19. Determine the initial value, the rate of change, and equation to represent the situation below. Let M be the money raised, and let d be the length of the charity campaign in days. Number of DaysMoney Raised 050 5150 10250 15350 20450 25550

20. Answer Initial value: $50 Rate of Change: $20/day M = 20d + 50