1. Kinetic Model of Gases Section 1.9, 1.11

2. Assumptions A gas consists of molecules in ceaseless random motion The size of the molecules is negligible in the sense that their diameters are much smaller than the average distance traveled between collisions The molecules do not interact, except during collisions

3. Pressure of a gas M molecular weight; V volume c root-mean-square speed (rms speed)

4. Speed of gases r.m.s. speed mean speed

5. Average speed of gas molecules Effect of Molecular Weight Temperature Effect

6. Kinetic Energy of Molecules E k = 3/2 RT E k kinetic energy; T temperature; R gas constant The average kinetic energy per molecule k B Boltzmann constant = R/6.02  10 23

7. Partial Pressure Dalton ’ s Law The total pressure observed for a mixture of gases is equal to the sum of the pressures that each individual component gas would exert P total = P 1 +P 2 +P 3 +…+P J P J = x J P total P total total pressure; P J partial pressure of component J;  J molar fraction of component J.

8. Diffusion & Effusion Diffusion Molecule of different substances mingle with each other. Effusion Escape of a gas through a small hole.

9. Diffusion & Effusion Rates of diffusion and effusion of gases increase with increasing temperature. For effusion the rate decreases with increasing molar mass.

10. Diffusion & Effusion Graham ’ s Law At a given pressure and temperature, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

11. Diffusion & Effusion The rate at which hydrogen and carbon dioxide effuse under the same conditions of pressure and temperature are in the ratio

12. Diffusion & Effusion Separation of uranium-235 from uranium-238, in the form of volatile solids UF 6 http://www.columbia.edu/itc/chemistry/chem-c1403/text_chapters/nukes.html http://www.uic.com.au/uicchem.htm http://www.uilondon.org/index.htm

13. Effusion as a separation technique Use porous membranes to separate light gases from heavy ones average speed of gas molecules depends on the masses of their molecules heavy molecules in a mixture move slower on average than light ones gases made of light molecules diffuse through pores in membranes faster than heavy molecules Differences from dialysis membrane is permeable, not semipermeable: all gas molecules in the mixture can pass through it size of molecules isn't usually important: pores in membrane are much larger than gas molecules...molecular velocity (and so, molecular mass) is the basis for separation, not size Examples separating helium from oxygen separating uranium isotopes as volatile UF 6

14. Molecular Collisions C = 平均自由路徑 / 飛行時間 = / [1/ z] =  z  R   N A  p  Z   N A  c p  RT : 平均自由路徑 ; Z : 碰狀頻率 collision frequency  : 碰狀截面積 ;  =  d 2 p : 壓力 ; T: 溫度 ; N A : 亞佛加厥常數

15. Molecule Collisions  1/p 平均路徑隨壓力減少而增加  分子之碰狀截面積越大  平均自由路徑隨之減短 z  p 碰撞頻率隨壓力增加而增大 z  c    分子量越大的分子其碰撞頻率會低於分 子量小的分子

16. Maxwell distribution of speeds The Maxwell distribution of speeds f = F (s)  S F (s) = 4  [m / 2  k B T] (3/2) s 2 e -(ms 2 /2k B T) f : 運動速率在某個範圍內的分子之比例 s: 分子運動速率 speed;   s : 速率的範圍 interval of speed  K B : Boltzmann Constant

17. Maxwell distribution of speeds 當設定的速率範圍增大時, 所含蓋的分子比例也隨之增加 f = F (s)  S F (s) = 4  [m/ 2  k B T] (3/2) s 2 e -(ms 2 /2k B T) f  Sf  S

18. Maxwell distribution of speeds s 2 當速率值趨向極小質 s 2 趨於 0. 這表示具有極低 運動速率分子所佔的比力是非常小的. f = F (s)  S F (s) = 4  [m / 2  k B T] (3/2) s 2 e -(ms 2 /2k B T)

19. Maxwell distribution of speeds e -x (x =ms 2 /2k B T) 這是一個 " 衰減 " 函數. 當速率 (s) 非常大的時候指數值就 相當小. 也就是說具有極高運動速率的氣體分子比例是非 常小的. 分子量 (M) 越大, 指數值就越小. 大分子具有高運動速率 的比例較小. 溫度 (T) 升高, 指數值越大. 溫度越高具有較快運動速率的 分子比例也越大. f = F (s)  S F (s) = 4  [m / 2  k B T] (3/2) s 2 e -(ms 2 /2k B T)

20. Maxwell distribution of speeds 4  [m / 2  k B T] (3/2) 使分子比例的呈現在 0 與 1 之間 f = F (s)  S F (s) = 4  [m / 2  k B T] (3/2) s 2 e -(ms 2 /2k B T)

21. Maxwell distribution of speeds

22. Distribution of Translational Energy Maxwell-Boltzmann Distribution Law  kinetic energy  mu   f = F (  )  F (  ) = 2  / (  k B T) (3/2)  1/2 e -(  /k B T)