1. Model: I(total ions) = I(H+) + I(HCl+) = A(t) P m I(H+) = A(H+) P n I(H+)/(I(H+)+I(HCl+)) = (A(H+)/A(t)) P (n-m) = A(H+,t) P (n-m) ln(I(H+)/(I(H+)+I(HCl+))) = (n-m) ln(P) + ln(A) HCl, F<-<-X, (1,0), J = 6, mass analysis: agust, www....hcl/HCl,agust07-/HClFJ6model-210807ak.ppt

2. pnt we04awe06awe09awe13a 29844092022,653331,63051327 29806391446,752685,62934728 29811091485,952699,629396H+ 29833791848,753166,630139 29843392003,953329,93046231 30503,532 30691437 30087092719,253727,529609,5438 29955691075,450176,822874 27409371352304435132,5HCl+ 26472555268,717501,6-4797,5 28757574992,134539,76087 29672486730,146695,419527,5443 29894990090,250727,225864444 29844092022,653331,630513bgr.(H+) 30087092719,253727,530691bgr.(HCl+) -817-1305,2-1444,7-2717,5I(H+) -83598-86806,7-92281,3-110540I(HCl+) 0,0096780,0148130,0154140,023994I(H+)/(I(H+)+I(HCl+)) -4,63786-4,21225-4,17247-3,72995ln(ratio) 0,0350,060,090,13power (after autotracker) -3,35241-2,81341-2,40795-2,04022ln(P)

3. Coefficient values ± one standard deviation a (inters ) = -2.5046 ± 0.341 b(slope) = 0.63445 ± 0.127 ln(I(H+)/(I(H+)+I(HCl+))) ln(P)

4. Coefficient values ± one standard deviation a = -2.3137 ± 0.128 b = 0.68718 ± 0.0459 ln(I(H+)/(I(H+)+I(HCl+))) ln(P)

5. Coefficient values ± one standard deviation a = -1.9907 ± Inf b = 0.78963 ± Inf ln(I(H+)/(I(H+)+I(HCl+))) ln(P)

6. Summary: ln(P) ln(I(H+)/(I(H+)+I(HCl+))) (n-m) = 0.79 (n-m) = 0.69 (n-m) = 0.63

7. Conclusion: Slope is resonably close to the value 1, i.e. (n-m) = 1 as to be expected for the case n = 4 and m = 3