1. Coordination Chemistry Bonding in transition-metal complexes

2. Summary of key points on isomerism

3. Crystal field theory: an electrostatic model The metal ion will be positive and therefore attract the negatively charged ligands But there are electrons in the metal orbitals, which will experience repulsions with the negatively charged ligands

4. Ligand/d orbital interactions Orbitals point at ligands (maximum repulsion) Orbitals point between ligands (less repulsion)

5. The two effects of the crystal field

6. oo 3/5  o 2/5  o  o is the crystal field splitting t 2g egeg E(t 2g ) = -0.4  o x 3 = -1.2  o E(e g ) = +0.6  o x 2 = +1.2  o Splitting of d orbitals in an octahedral field

7. Ligand effect of splitting Strong field Weak field The spectrochemical series,  0 depends on ligand CO, CN - > phen > NO 2 - > en > NH 3 > NCS - > H 2 O > F - > RCO 2 - > OH - > Cl - > Br - > I -

8. Effect of metal ion on splitting Strong field Weak field  increases with increasing formal charge on the metal ion, ligands closer  increases on going down the periodic table, more diffuse orbitals

9.  o ≈ M ∑ n l L l x 10 3 cm -1 Predicts value of  (cm -1 ) n l is # of ligands L l The splitting constant must depend on both the ligand and the metal. Observe that ML 4 expected to have smaller splitting than ML 6

10. d1d1 d2d2 d3d3 d4d4 Placing electrons in d orbitals (strong vs weak field) Strong field Weak field So, what is going on here!!

11. d4d4 Strong field = Low spin (2 unpaired) Weak field = High spin (4 unpaired)  <  o  >  o When the 4 th electron is assigned it will either go into the higher energy e g orbital at an energy cost of  0 or be paired at an energy cost of , the pairing energy.  0, Pairing Energy!!. Strong field Weak field

12. Pairing Energy,  The pairing energy, , is made up of two parts.  c : Coulombic repulsion energy caused by having two electrons in same orbital. Destabilizing energy contribution of  c for each doubly occupied orbital.  e : Exchange stabilizing energy for each pair of electrons having the same spin and same energy. Stabilizing contribution of  e for each pair having same spin and same energy  = sum of all  c and  e interactions How do we get these interactions?

13. Placing electrons in d orbitals 1 u.e.5 u.e. d5d5 0 u.e.4 u.e. d6d6 1 u.e.3 u.e. d7d7 2 u.e. d8d8 1 u.e. d9d9 0 u.e. d 10 High Low

14. Detail working out…. 1 u.e.5 u.e. d5d5 High Field Low Field (Low Spin) (High Spin) What are the energy terms for both high spin and low spin? High Field Coulombic Part = 2  c Exchange part = for 3  e For 1  e  = 2  c + 4  e Low Field Coulombic Part = 0 Exchange part = for 3  e + P e  = 4  e High Field – Low Field = -2  0 +2  e LFSE = 5 * (-2/5  0 ) = -2  0 LFSE = 3*(-2/5  0 ) + 2 (3/5  0 ) = 0 When  0 is larger than  e the high field, the result is negative and high field (low spin) is favored.

15. Positive favors high spin. Neg favors low spin.

16. Interpretation of Enthalpy of Hydration of hexahydrate using LFSE d 0 d 1 d 2 d 3 d 4 d 5 d 6 d 7 d 8 d 9 d 10 LFSE (in  0).0.4.8 1.2.6.0.4.8 1.2.6.0

17. Splitting of d orbitals in a tetrahedral field t2t2 e tt  t = 4/9  o Always weak field (high spin)

18. Magnetic properties of metal complexes Diamagnetic complexes very small repulsive interaction with external magnetic field no unpaired electrons Paramagnetic complexes attractive interaction with external magnetic field some unpaired electrons

19. Measured magnetic moments include contributions from both spin and orbital spin. In the first transition series complexes the orbital contribution is small and usually ignored.

20. Coordination Chemistry: Molecular orbitals for metal complexes

21. The symmetry of metal orbitals in an octahedral environment A 1g T 1u

22. T 2g EgEg The symmetry of metal orbitals in an octahedral environment

23. s

24. Metal-ligand  interactions in an octahedral environment Six ligand orbitals of  symmetry approaching the metal ion along the x,y,z axes We can build 6 group orbitals of  symmetry as before and work out the reducible representation

25. s If you are given , you know by now how to get the irreducible representations  = A 1g + T 1u + E g

26. s Now we just match the orbital symmetries

27. 6  ligands x 2e each 12  bonding e “ligand character” “d 0 -d 10 electrons” non bonding anti bonding “metal character”

28. Introducing π-bonding 2 orbitals of π-symmetry on each ligand We can build 12 group orbitals of π-symmetry

29.  π = T 1g + T 2g + T 1u + T 2u

30. Anti-bonding LUMO(π) The CN- ligand

31. Some schematic diagrams showing how p bonding occurs with a ligand having a d orbital (P), a  * orbital, and a vacant p orbital.

32. 6  ligands x 2e each 12  bonding e “ligand character” “d 0 -d 10 electrons” non bonding anti bonding “metal character” ML 6  -only bonding The bonding orbitals, essentially the ligand lone pairs, will not be worked with further.

33. t 2g egeg ML 6  -only ML 6  + π Stabilization (empty π-orbitals on ligands) oo ’o’o  o has increased π-bonding may be introduced as a perturbation of the t 2g /e g set: Case 1 (CN -, CO, C 2 H 4 ) empty π-orbitals on the ligands M  L π-bonding (π-back bonding) t 2g (π) t 2g (π*) egeg

34. t 2g egeg ML 6  -only ML 6  + π π-bonding may be introduced as a perturbation of the t 2g /e g set. Case 2 (Cl -, F - ) filled π-orbitals on the ligands L  M π-bonding (filled π-orbitals) Stabilization Destabilization t 2g (π) t 2g (π*) egeg  ’o oo  o has decreased

35. Strong field / low spinWeak field / high spin Putting it all on one diagram.

36. Spectrochemical Series Purely  ligands:  en > NH 3 (order of proton basicity)  donating which decreases splitting and causes high spin:  : H 2 O > F > RCO 2 > OH > Cl > Br > I (also proton basicity) Adding in water, hydroxide and carboxylate  : H 2 O > F > RCO 2 > OH > Cl > Br > I  accepting ligands increase splitting and may be low spin  : CO, CN -, > phenanthroline > NO 2 - > NCS -

37. Merging to get spectrochemical series CO, CN - > phen > en > NH 3 > NCS - > H 2 O > F - > RCO 2 - > OH - > Cl - > Br - > I - Strong field,  acceptors large  low spin  only Weak field,  donors small  high spin

38. Turning to Square Planar Complexes Most convenient to use a local coordinate system on each ligand with y pointing in towards the metal. p y to be used for  bonding. z being perpendicular to the molecular plane. p z to be used for  bonding perpendicular to the plane,  . x lying in the molecular plane. p x to be used for  bonding in the molecular plane,  |.

39. ML 4 square planar complexes ligand group orbitals and matching metal orbitals

40. ML 4 square planar complexes MO diagram  -only bonding  - bonding

41. A crystal-field aproach: from octahedral to tetrahedral Less repulsions along the axes where ligands are missing

42. A crystal-field aproach: from octahedral to tetrahedral A correction to preserve center of gravity

43. The Jahn-Teller effect Jahn-Teller theorem: “there cannot be unequal occupation of orbitals with identical energy” Molecules will distort to eliminate the degeneracy

45. Angular Overlap Method An attempt to systematize the interactions for all geometries. The various complexes may be fashioned out of the ligands above Linear: 1,6 Trigonal: 2,11,12 T-shape: 1,3,5 Tetrahedral: 7,8,9,10 Square planar: 2,3,4,5 Trigonal bipyramid: 1,2,6,11,12 Square pyramid: 1,2,3,4,5 Octahedral: 1,2,3,4,5,6

46. Cont’d All  interactions with the ligands are stabilizing to the ligands and destabilizing to the d orbitals. The interaction of a ligand with a d orbital depends on their orientation with respect to each other, estimated by their overlap which can be calculated. The total destabilization of a d orbital comes from all the interactions with the set of ligands. For any particular complex geometry we can obtain the overlaps of a particular d orbital with all the various ligands and thus the destabilization.

47. ligand dz2dz2 d x 2 -y 2 d xy d xz d yz 11 e  0000 2¼¾000 3¼¾000 4¼¾000 5¼¾000 610000 7001/3 800 900 10001/3 11¼3/169/1600 121/43/169/1600 Thus, for example a d x 2 - y 2 orbital is destabilized by (3/4 +6/16) e  = 18/16 e  in a trigonal bipyramid complex due to  interaction. The d xy, equivalent by symmetry, is destabilized by the same amount. The d z 2 is destabililzed by 11/4 e .