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-Pressure System- Frequency Response Cory Richardson Dennis To Jamison Linden 6/27/2015, UTC, ENGR-329.

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Presentation on theme: "-Pressure System- Frequency Response Cory Richardson Dennis To Jamison Linden 6/27/2015, UTC, ENGR-329."— Presentation transcript:

1 -Pressure System- Frequency Response Cory Richardson Dennis To Jamison Linden 6/27/2015, UTC, ENGR-329

2 Contents  Background Description, SSOC, Step Response  Frequency Response Experiments  Modeling Approach  Comparison of Experimental Results with Model Data  Conclusions

3 Background - System Figure 1. Schematic diagram of the Dunlap Plant Spray-Paint Booths

4 Background - Block Diagram Figure 2. Block diagram of paint booth system

5 Background - SSOC Operating Range for Output Operating Range for Input

6 Background – Step Response

7 Background – Step Response Results  Experimental results K = 0.1 – 0.3 (cm-H 2 O/%) t 0 = 0.5 s  = 1.7 s  Model results K = 0.1 – 0.3 (cm-H 2 O/%) t 0 = 0.48 s  = 1.75 s

8 Frequency Response – Description

9 Frequency Response - Example c (1.45) T (25.3) m (15) t (-1.8)

10 Frequency Response – Bode Plots K= 0.1 cm-H 2 O/% 2 nd Order

11 Frequency Response – Bode Plots f u =0.85 Hz

12 Frequency Response – Bode Plots fu=0.85 AR=.055

13 Frequency Response – Bode Plots f u =0.85 Hz

14 Frequency Response – Bode Plots K= 0.21 cm-H 2 O/% 2 nd Order fu=0.85 AR=.015

15 Frequency Response – Bode Plots f u =0.85 Hz

16 Frequency Response – Bode Plots K= 0.35 cm-H 2 O/% 2 nd Orderfu=0.85 AR=.024

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22 Modeling Approach  Approximate FOPDT Model Amplitude Ratio Equation: Phase Angle Equation:

23 Modeling Approach – Bode Plots

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32 Results Comparison  Experimental Results: K = 0.1 – 0.35(cm-H 2 0/%) t 0 = 0.6 s  = 1.7 s 2 nd Order system Ultimate Frequency = 0.85 Hz Ultimate Controller Gain = 18.2 – 55.6 (%/cm-H 2 O)

33 Results Comparison  Model Results: K = 0.1 – 0.35 (cm-H 2 O/%) t 0 = 0.85 s  = 1.7 s

34 Conclusions - System  2 nd order system  f u = 0.85 Hz  From the model: K = 0.1 – 0.35 (cm-H 2 O/%) t 0 = 0.85 s  = 1.7 s  K cu = 18.2 – 55.6 (%/cm-H 2 O)


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