1. # shows 0 volts for each channel screen menu, calcs & info menu buttons cursor control cursor triggering control usual channel controls measure autoset

2. B B B B B outside =0 uniform magnetic field inside Ideal Solenoid

3. B IN Use Ampere’s Law to Find Magnetic Field Amperian Loop L N solenoid loops enclosed, each with current I. where n is “loop density” N/L of solenoid. (Explain each step in your report.)

4. voltage t Cause and Effect in a Solenoid: Ampere’s Law to Faraday’s Law V R =RI R =RI L B ampere LL The current in the solenoid creates a magnetic field inside the solenoid due to Ampere’s Law. The changing magnetic field inside the solenoid causes a back EMF (voltage) due to Faraday’s Law. Notice that d I /dt causes a phase shift.

5. Direction of current inside the resistor ? NS V (velocity) R B Inside the solenoid:

6. ReceiverTransmitter Oscillating voltage received is measurable. Oscillating transmitting magnetic fields. Oscillating transmitting voltage. Transmitting magnetic fields reach inside coils.

7. voltage t The LRC Circuit - AC Driven VLVL VCVC VRVR

8. voltage t The LRC Circuit - AC Driven: Source from Addition VLVL VCVC VRVR V source

9. A BC

10. 0.1  F 50 mH 100 

11. I amplitude f drive f resonance I amplitude f drive f resonance Large RSmall R

12. V R (t) V S (t) V R (t) V S (t) out of phase in phase 45 o

13. System: Charged hollow sphere with inner radius a and outer radius b. Charges: nonuniform charge distribution in between (so not a conductor): Problem solving strategy: 1) Draw non-physical Gaussian sphere at distance r where you want to find E r. 2) Use Gauss’s law to write equation for E r in terms of other parameters. 3) Solve for E r. In this case solve in 3 places, inside hollow region (r I ), inside charged region (r 2 ) and outside (r 3 ). rIrI r2r2 r3r3 Problem: The electric field is a radial vector field due to the symmetry of the system. Find the electric field magnitude in the radial direction at every distance from the origin. Required vector calculus knowledge:

14. System: Charged infinite cylinder with radius a. Charges: Nonuniform charge distribution inside cylinder (so not a conductor): rIrI r2r2 Problem: The electric field is a radial vector field due to the symmetry of the system. Find the electric field magnitude in the radial direction at every distance from the origin. Required vector calculus knowledge: Try solving over a finite height z o : Problem solving strategy: 1) Draw non-physical Gaussian cylinder at distance r where you want to find E r. 2) Use Gauss’s law to write equation for E r in terms of other parameters including an arbitrary height z o. 3) Solve for E r. In this case solve in 2 places, inside region (r I ), and outside (r 2 ). You will need to have the arbitrary height z o cancel in the end.

15. zozo Another view of drawing a Gaussian cylinder of radius r and finite length z o around an infinite cylinder of charge (this one outside). r

16. System: Charged infinite slab of width w in x-y direction. Charges: Uniform slab of charge density  : Problem: The electric field is a vector field pointing perpendicular to the plane of the slab due to the symmetry of the system. Find the electric field magnitude in the perpendicular direction at a given distance from the middle of the slab. Required vector calculus knowledge: Try solving over a finite box x o and y o : Problem solving strategy: 1) Draw non-physical Gaussian rectangular prism from center of slab to height z where you want to find E z. 2) Use Gauss’s law to write equation for E z in terms of other parameters including arbitrary length and width x o and y o. 3) Solve for E r. In this case solve in 2 places, inside region (z I ), and outside (z 2 ). You will need to have the arbitrary x o and y o cancel in the end. Set z=0 in middle of slab. z2z2 xoxo yoyo z1z1 xoxo yoyo

17. VV R BULB Three representations of the same circuit: BATTERY +

18. +

19. 3 V a b c d a b c d

20. 1.5 V A.B. C.

21. 1.5 V A.B. C. 1.5 V D. 1.5 V

22. A.B. C. 1.5 V D. 1.5 V V V + - + - V + - V + - V + - E.

24. BATTERY + + + 3 V

25. Voltage V DC Measuring the voltage drop across a light bulb (DMM in parallel): V R BATTERY +

26. Amperes mA Measuring the voltage drop across a light bulb (DMM in series): A R BATTERY +

27. Ohms (  )  Measuring the resistance of a light bulb (component disconnected): R

28. BATTERY + V 1.5 Circuit Position 0

29. BATTERY + V 1.5 Circuit Position 0

30. BATTERY + V 1.5 Circuit Position

32. Thumb points to North Right-hand-wrap rule for finding direction of magnetic poles created by moving charges (current). N S Wrap fingers in direction of current. q If charge is negative, reverse poles.

34. N S

35. N S N S

36. S S

37. S MAGNETIC N MAGNETIC N S

38. + + + + + ++ + + + + + ++ Excess positive charge on the surface of a sphere. - - - Excess negative charge on the surface of a cube. - - - - - - - - - - - - - - - - -- - - - -- - - - - - - - (None of the excess charges rest inside the objects, they always repel each other to the surface.) Ex.1.Ex.2.

39. + + + + + + + Macroscopic charge separation across a neutral conductor in the presence of an electric field. - Negatively charged object creates an electric field. + - - - - - - - - - - - - -

40. Microscopic charge separation across a neutral conductor in the presence of an electric field. + Positively charged object creates an electric field at surface of material. + - MAGNIFY insulator/dielectric material rotate + - + -

41. Electrons deposited on the surface of a balloon by rubbing it against your hair do not spread out. - - - -- - -- -