1. ES 202 Fluid and Thermal Systems Lecture 17: More on properties and phases (1/21/2003)

2. Lecture 17ES 202 Fluid & Thermal Systems2 Assignments Homework: –5-61, 5-93 in Cengel & Turner Reading assignment –3-7, 3-9, 3-10 in Cengel & Turner

3. Lecture 17ES 202 Fluid & Thermal Systems3 Announcements Comments on Quiz 2 –Study harder!! –All questions are in the lecture notes. –Any problem with homework?? Just talk to me.

4. Lecture 17ES 202 Fluid & Thermal Systems4 Road Map of Lecture 17 Continue exercise on property table (water) Common procedure in phase determination –saturation table More on Compressed Liquid Approximation Practice with data interpolation –linear –bi-linear Special models –constant pressure process –constant volume process

5. Lecture 17ES 202 Fluid & Thermal Systems5 What is the common starting point? Review question: In the procedure of phase determination of a substance, what is the common starting point? –the saturation table It serves as a reference region which helps you to decide if you are in –compressed (subcooled) liquid region –two-phase region –superheated vapor region If the substance is in the two-phase region, the knowledge of quality (mass fraction of vapor in the mixture) is critical in completely identifying the state of the mixture.

6. Lecture 17ES 202 Fluid & Thermal Systems6 More on Compressed Liquid Approximation As introduced yesterday, the compressed liquid approximation can be expressed as: It can be interpreted as weak dependency of most properties on pressure in the compressed liquid region. Hence, most properties can be approximated by their saturated liquid values at the specified temperature. (weak function of T)

7. Lecture 17ES 202 Fluid & Thermal Systems7 Compressed Liquid Approximation on Phase Diagrams exact state approximate state constant temperature line P-v diagram Constant pressure line exact state approximate state T-v diagram

8. Lecture 17ES 202 Fluid & Thermal Systems8 Data Interpolation The property tables only tabulate discrete values for pressure or temperature as the independent property. If you are interested in values which do not fall on the tabulated data points, interpolation within the “sandwich” interval will be necessary. Since the property tables report data at small intervals, linear interpolation should be adequate for most purposes. –Example: specify T (not tabulated) and x in two-phase region If both independent, intensive thermodynamic properties do not fall on the tabulated data points, bi-linear interpolation is necessary to completely specify the thermodynamic states. –Example: specify P and T in superheated vapor region (both not tabulated)

9. Lecture 17ES 202 Fluid & Thermal Systems9 Exercise with interpolation

10. Lecture 17ES 202 Fluid & Thermal Systems10 Constant Pressure Process Imagine a heating process in a cylinder with a constant weight as a lid (closed system; control mass) Since pressure is constant, you only need one more independent, intensive property to specify the state. Trace the process on –P-v diagram –T-v diagram Constant pressure line heating mixture of liquid and vapor } liquid

11. Lecture 17ES 202 Fluid & Thermal Systems11 Constant Volume Process Imagine a heating process in a rigid enclosure (closed system; control mass) Since volume is constant, specific volume is constant throughout the process. Trace the process on a –P-v diagram –T-v diagram heating mixture of liquid and vapor } liquid vapor Constant specific volume line Constant specific volume line