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Problem Day 2 CH343 Bruce A. Hathaway
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Compound #1: IR sp 2 C-H, sp 3 C-H, C=O, benzene C=C, possible monsubstituted benzene
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MS Even MW, so assume 0 N’s; no apparent Cl or Br
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Compound #1: Carbon NMR C=O; 4 benzene C’s; 3 sp 3 C’s
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Proton NMR
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Compound #2: IR NH 2 stretches; sp 3 C-H stretches, N-H bend
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MS Odd MW is probably 1 N; no apparent Cl or Br
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Compound #2: Carbon NMR Three types of carbons, all sp 3
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Proton NMR
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Compound #3: IR OH stretch; sp C-H stretch, sp 3 C-H stretches, CΞC stretch, C-O stretch
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MS No apparent Cl or Br; even MW is probably no N
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Compound #3: Carbon NMR CΞC; sp 3 C-O, sp 3 C
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Proton NMR
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