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1 CS 140 Lecture 3 Combinational Logic Professor CK Cheng CSE Dept. UC San Diego.

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Presentation on theme: "1 CS 140 Lecture 3 Combinational Logic Professor CK Cheng CSE Dept. UC San Diego."— Presentation transcript:

1 1 CS 140 Lecture 3 Combinational Logic Professor CK Cheng CSE Dept. UC San Diego

2 2 1.Specification 2.Implementation 3.K-maps Part I Combinational Logic.

3 3 Literals x i or x i ’ Product Termx 2 x 1 ’x 0 Sum Termx 2 + x 1 ’ + x 0 Minterm of n variables: A product of n literals in which every variable appears exactly once. Maxterm of n variables: A sum of n literals in which every variable appears exactly once. Definitions

4 4 Implementation Specification  Schematic Diagram Net list, Switching expression Obj min cost  Search in solution space (max performance) Cost: wires, gates  Literals, product terms, sum terms We want to minimize # of terms, # of literals

5 5 Implementation (Optimization) IDABf(A,B)minterm 0000 1011A’B 2101AB’ 3111AB An example of 2-variable function f(A,B)

6 6 Function can be represented by sum of minterms: f(A,B) = A’B+AB’+AB This is not optimal however! We want to minimize the number of literals and terms. We factor out common terms – A’B+AB’+AB= A’B+AB’+AB+AB =(A’+A)B+A(B’+B)=B+A Hence, we have f(A,B) = A+B

7 7 K-Map: Truth Table in 2 Dimensions A = 0 A = 1 B = 0 B = 1 0 2 1 3 0 1 1 A’B AB’ AB f(A,B) = A + B

8 8 IDABf(A,B)minterm 0000 1011A’B 2100 3111AB Another Example f(A,B)=A’B+AB=(A’+A)B=B

9 9 On the K-map: A = 0 A= 1 B= 0 B = 1 0 2 1 3 0 1 A’B AB f(A,B)=B

10 10 IDABf(A,B)Maxterm 0000A+B 1011 2100A’+B 3111 Using Maxterms f(A,B)=(A+B)(A’+B)=(AA’)+B=0+B=B

11 11 Two Variable K-maps Id a b f (a, b) 0 0 0 f (0, 0) 1 0 1 f (0, 1) 2 1 0 f (1, 0) 3 1 1 f (1, 1) # possible 2-variable functions: For 2 variables as inputs, we have 4=2 2 entries. Each entry can be 0 or 1. Thus we have 16=2 4 possible functions. f(a,b) abab

12 12 Two-Input Logic Gates

13 13 More Two-Input Logic Gates

14 Representation of k-Variable Func. Boolean Expression Truth Table Cube K Map Binary Decision Diagram 14 (0,1,1,1)(0,1,1,0) (0,0,0,0)(0,0,0,1)(1,0,0,1) (1,1,1,1) (1,1,0,1) (1,0,0,0) (0,0,1,0) (1,1,1,0) (0,0,1,1) (1,0,1,1) (0,1,0,1) (1,0,1,0) A cube of 4 variables: (A,B,C,D) D C B A

15 15 Three-Variable K-Map Id a b c f (a,b,c) 0 0 0 0 1 1 0 0 1 0 2 0 1 0 1 3 0 1 1 0 4 1 0 0 1 5 1 0 1 0 6 1 1 0 1 7 1 1 1 0

16 16 Corresponding K-map 0 2 6 4 1 3 7 5 b = 1 c = 1 a = 1 1 1 1 1 0 0 0 0 (0,0) (0,1) (1,1) (1,0) c = 0 Gray code f(a,b,c) = c’

17 17 Karnaugh Maps (K-Maps) Boolean expressions can be minimized by combining terms K-maps minimize equations graphically

18 18 Circle 1’s in adjacent squares In the Boolean expression, include only the literals whose true K-map y(A,B)=A’B’C’+A’B’C= A’B’(C’+C)=A’B’

19 19 Another 3-Input example Id a b c f (a,b,c) 0 0 0 0 0 1 0 0 1 0 2 0 1 0 1 3 0 1 1 0 4 1 0 0 1 5 1 0 1 1 6 1 1 0 - 7 1 1 1 1

20 20 Corresponding K-map 0 2 6 4 1 3 7 5 b = 1 c = 1 a = 1 0 1 - 1 0 0 1 1 (0,0) (0,1) (1,1) (1,0) c = 0 f(a,b,c) = a + bc’

21 21 Yet another example Id a b c f (a,b,c,d) 0 0 0 0 1 1 0 0 1 1 2 0 1 0 - 3 0 1 1 0 4 1 0 0 1 5 1 0 1 1 6 1 1 0 0 7 1 1 1 0

22 22 Corresponding K-map 0 2 6 4 1 3 7 5 b = 1 c = 1 a = 1 1 - 0 1 1 0 0 1 (0,0) (0,1) (1,1) (1,0) c = 0 f(a,b,c) = b’

23 23 4-input K-map

24 24 4-input K-map

25 25 4-input K-map

26 26 K-maps with Don’t Cares

27 27 K-maps with Don’t Cares

28 28 K-maps with Don’t Cares


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