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Joule-Thomson Expansion Physics 313 Professor Lee Carkner Lecture 21
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Exercise #20 Maxwell’s Relations Use Maxwell’s relation to find ( s/ P) T ( s/ P) T = - ( v/dT) P P(v-b) = RT ( v/dT) P = R/P Verify relation Find s for T = 250 C and P = 200 and 400 kPa Find v for P = 300 kPa and T = 200 and 300 C (7.3789-7.7086/400-200) = - (0.8753-0.7163/300-200)
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Phase Transition Processes Some substances will easily undergo phase transitions at standard pressure Many more materials only become liquid or solid at very low temperatures how are these temperatures achieved?
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Joule-Thompson Expansion Force a fluid through a narrow plug by maintaining unequal pressures Can be achieved by a pump circulating fluid through a pipe with an expansion valve in the middle
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Throttling and Enthalpy Apply first law: U = U f -U i = W + Q W = -(P f V f - P i V i ) H i = H f For continuous throttling h = enthalpy per mole (specific enthalpy)
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Isenthalpic Curve If a throttling process is performed, P i, T i and P f, T f can be recorded The plot of P i, T i and all of the P f,T f ’s is called the isenthalpic curve A series of isenthalpic curves can be produced for a substance
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Inversion Curve Each curve has two regions T f >T i T f < T i = (dT/dP) h
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Effects of Throttling For a given initial point, the final temperature depends on the final point on the isenthalpic curve For > 0 For < 0 Throttling can either heat or cool a fluid
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Joule-Thomson Coefficient An expression for can be derived from dh and the second T ds equation The slope of an isenthalpic line can be found if you know c P, T, v and how the volume changes with temperature at that point
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Liquefying Gasses In order to cool a gas, its temperature must start below the maximum inversion temperature T M.I. is near room temperature for many gasses Some gasses have to be pre-cooled
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Heat Exchanger How is gas liquefied? Run at high pressure (P i ) through a heat exchanger Cold gas runs back through the heat exchanger cooling the incoming gas May be pre-cooled before cycle begins
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Enthalpy and Liquefaction If fraction y of the gas is liquefied and fraction 1-y is returned, what is enthalpy balance? y = (h f - h i ) / (h f - h L ) To increase amount of gas liquefied, need to decrease h i Initial point should start on the inversion curve to maximize efficiency
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TS Diagram A TS diagram can be produced showing isobars and isenthalps Can see that T drops most rapidly at low T and low h
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Applications Advantage is a large drop in T with P at low temperature Often used as the last stage of a cooling process
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