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Damped and Forced SHM Physics 202 Professor Lee Carkner Lecture 5
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If the amplitude of a linear oscillator is doubled, what happens to the period? a)Quartered b)Halved c)Stays the same d)Doubled e)Quadrupled
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If the amplitude of a linear oscillator is doubled, what happens to the spring constant? a)Quartered b)Halved c)Stays the same d)Doubled e)Quadrupled
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If the amplitude of a linear oscillator is doubled, what happens to the total energy? a)Quartered b)Halved c)Stays the same d)Doubled e)Quadrupled
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If the amplitude of a linear oscillator is doubled, what happens to the maximum velocity? a)Quartered b)Halved c)Stays the same d)Doubled e)Quadrupled
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If the amplitude of a linear oscillator is doubled, what happens to the maximum acceleration? a)Quartered b)Halved c)Stays the same d)Doubled e)Quadrupled
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If you have a pendulum of fixed mass and length and you increase the length of the path the mass travels, what happens to the period? a)Increase b)Decrease c)Stays the same
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If you have a pendulum of fixed mass and length and you increase the length of the path the mass travels, what happens to the maximum velocity? a)Increase b)Decrease c)Stays the same
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If you have a pendulum of fixed mass and length and you increase the length of the path the mass travels, what happens to the maximum acceleration? a)Increase b)Decrease c)Stays the same
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The pendulum for a clock has a weight that can be adjusted up or down on the pendulum shaft. If your clock runs slow, what should you do? a)Move weight up b)Move weight down c)You can’t fix the clock by moving the weight
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PAL #4 Pendulums The initial kinetic energy is just the kinetic energy of the bullet ½mv 2 = (0.5)(0.01 kg)(500 m/s) 2 = The initial velocity of the block comes from the kinetic energy KE = ½mv 2 v = (2KE/m) ½ = ([(2)(1250)]/(5)) ½ = Amplitude =x m, can get from total energy Initial KE = max KE = total E = ½kx m x m =(2E/k) ½ = ([(2)(1250)]/(5000)) ½ = Equation of motion = x(t) = x m cos( t) k = m 2 = (k/m) ½ = [(5000/(5)] ½ = 31.6 rad/s
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Uniform Circular Motion Simple harmonic motion is uniform circular motion seen edge on Consider a particle moving in a circle with the origin at the center The projection of the displacement, velocity and acceleration onto the edge-on circle are described by the SMH equations
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UCM and SHM
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Uniform Circular Motion and SHM x-axis y-axis xmxm angle = t+ Particle moving in circle of radius x m viewed edge-on: cos ( t+ )=x/x m x=x m cos ( t+ ) x(t)=x m cos ( t+ ) Particle at time t
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Observing the Moons of Jupiter He discovered the 4 inner moons of Jupiter He (and we) saw the orbit edge-on
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Galileo’s Sketches
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Apparent Motion of Callisto
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Application: Planet Detection The planet cannot be seen directly, but the velocity of the star can be measured The plot of velocity versus time is a sine curve (v=- x m sin( t+ )) from which we can get the period
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Orbits of a Star+Planet System Star Planet Center of Mass V star V planet
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Light Curve of 51 Peg
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Damped SHM Consider a system of SHM where friction is present The damping force is usually proportional to the velocity If the damping force is represented by F d = -bv Then, x = x m cos( t+ ) e (-bt/2m) e (-bt/2m) is called the damping factor and tells you by what factor the amplitude has dropped for a given time or: x’ m = x m e (-bt/2m)
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Energy and Frequency The energy of the system is: E = ½kx m 2 e (-bt/m) The period will change as well: ’ = [(k/m) - (b 2 /4m 2 )] ½
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Exponential Damping
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Damped Systems Most damping comes from 2 sources: Air resistance Example: Energy dissipation Example: Lost energy usually goes into heat
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Damping
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Forced Oscillations If you apply an additional force to a SHM system you create forced oscillations If this force is applied periodically then you have 2 frequencies for the system d = the frequency of the driving force The amplitude of the motion will increase the fastest when = d
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Resonance Resonance occurs when you apply maximum driving force at the point where the system is experiencing maximum natural force Example: pushing a swing when it is all the way up All structures have natural frequencies
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Next Time Read: 16.1-16.5 Homework: Ch 15, P: 95, Ch 16, P: 1, 2, 6
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Summary: Simple Harmonic Motion x=x m cos( t+ ) v=- x m sin( t+ ) a=- 2 x m cos( t+ ) =2 /T=2 f F=-kx =(k/m) ½ T=2 (m/k) ½ U=½kx 2 K=½mv 2 E=U+K=½kx m 2
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Summary: Types of SHM Mass-spring T=2 (m/k) ½ Simple Pendulum T=2 (L/g) ½ Physical Pendulum T=2 (I/mgh) ½ Torsion Pendulum T=2 (I/ ) ½
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Summary: UCM, Damping and Resonance A particle moving with uniform circular motion exhibits simple harmonic motion when viewed edge-on The energy and amplitude of damped SHM falls off exponentially x = x undamped e (-bt/2m) For driven oscillations resonance occurs when = d
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