Presentation is loading. Please wait.

Presentation is loading. Please wait.

Some problems using C and H 2 D NMR. A compound has a molecular weight of 114 mass units and is know only to contain C, H, and O. What are the possible.

Published by Modified over 9 years ago

Similar presentations

Presentation on theme: "Some problems using C and H 2 D NMR. A compound has a molecular weight of 114 mass units and is know only to contain C, H, and O. What are the possible."— Presentation transcript:

1 Some problems using C and H 2 D NMR

2 A compound has a molecular weight of 114 mass units and is know only to contain C, H, and O. What are the possible formulas?

3 114/13 = 8.769;13*0.769 = 10;C 8 H 18 ; C 7 H 14 O; C 6 H 10 O 2... 1.carbon count 2.carbonyl group

4 C 7 H 14 O proton count CH 3 (CH 2 ) 3 COCH 2 CH 3 CH 3 CH 2 CH 2 CH 2 COCH 2 CH 3

5 A compound has a molecular weight of 102 mass units and is know only to contain C, H, and O. What are the possible formulas? 102/13 =7.846;13*0.846 = 11;C 7 H 18 ; C 6 H 14 O; C 5 H 10 O 2...

6

7 C 6 H 14 O (CH 3 ) 2 CH 2 CH 2 CHOHCH 3 (CH 3 ) 2 CHCH 2 CHOHCH 3

8 C=O 1721 cm -1 The compound has a molecular weight of 178. What is its structure?

9 178/13 = 13.692.692*13 = 9 C 13 H 22 C 12 H 18 O C 11 H 14 O 2 Carbon count = proton count = 14 11

10 PhCO 2 (CH 2 ) 3 CH 3 5 2 2 2 3

11 The following spectra refer to a compound with a molecular weight of 86 containing C,H and O.

12 86/13 = 6.615; 0.615*13 =8 C 6 H 14 ; C 5 H 10 O; C 4 H 6 O 2...

13 7 H 2 C=CH-CH(CH 3 )-CH 2 OH

14 Assign the correct structure A or B to the H NMR spectrum given below B 1 3

Download ppt "Some problems using C and H 2 D NMR. A compound has a molecular weight of 114 mass units and is know only to contain C, H, and O. What are the possible."

Similar presentations

Electromagnetic Spectrum. 5.7 X 10 5 9.5 X 10 3 1.7 X 10 3 4.8 X 10 2 9.5 X 10 -3 1.27210 -4 Electromagnetic Spectrum (Kcal/mol)

Electromagnetic Spectrum. 5.7 X X X X X Electromagnetic Spectrum (Kcal/mol)
Learning Objectives: To understand what is meant by the term, ‘relative molecular mass’

Learning Objectives: To understand what is meant by the term, ‘relative molecular mass’
Calculate the Empirical Formula for a compound with the following composition: 46.16% carbon; 53.84% nitrogen 1)Change % to grams (if needed) 2)Convert.

Calculate the Empirical Formula for a compound with the following composition: 46.16% carbon; 53.84% nitrogen 1)Change % to grams (if needed) 2)Convert.
Nuclear Magnetic Resonance (NMR) Spectroscopy

Nuclear Magnetic Resonance (NMR) Spectroscopy
Problem Day 1 Answers CH343 Bruce A. Hathaway. Problem 1: Carbon NMR Seven types of Carbons: 4 benzene carbons and 3 sp 3 carbons.

Problem Day 1 Answers CH343 Bruce A. Hathaway. Problem 1: Carbon NMR Seven types of Carbons: 4 benzene carbons and 3 sp 3 carbons.
Nuclear Magnetic Resonance Spectrometry Chap 19. Identification of Compounds with NMR Can be used organics, organometallics, and biochemical molecules.

Nuclear Magnetic Resonance Spectrometry Chap 19. Identification of Compounds with NMR Can be used organics, organometallics, and biochemical molecules.
Problem Day 2 CH343 Bruce A. Hathaway. Compound #1: IR sp 2 C-H, sp 3 C-H, C=O, benzene C=C, possible monsubstituted benzene.

Problem Day 2 CH343 Bruce A. Hathaway. Compound #1: IR sp 2 C-H, sp 3 C-H, C=O, benzene C=C, possible monsubstituted benzene.
The molecular formula is C 5 H 8. What is the structure?

The molecular formula is C 5 H 8. What is the structure?
60,200,000,000,000,000,000,000. 6.02 x 10 23.

60,200,000,000,000,000,000, x
Chemistry Notes Empirical & Molecular Formulas. Empirical Formula The empirical formula gives you the lowest, whole number ratio of elements in the compound.

Chemistry Notes Empirical & Molecular Formulas. Empirical Formula The empirical formula gives you the lowest, whole number ratio of elements in the compound.
C13 NMR 1H 13C 15N 19F Common nuclei which have a magnetic moment:

C13 NMR 1H 13C 15N 19F Common nuclei which have a magnetic moment:
1 CHEM 212 – NMR Spectroscopy Spring 2014. 2 Spectral Analysis – 1 H NMRNMR Spectroscopy NMR Spectral Analysis – Introductory 1 H NMR 1.NMR is rarely.

1 CHEM 212 – NMR Spectroscopy Spring Spectral Analysis – 1 H NMRNMR Spectroscopy NMR Spectral Analysis – Introductory 1 H NMR 1.NMR is rarely.
1)  A compound gives a mass spectrum with peaks at m/z = 77 (40%), 112 (100%), 114 (33%), and essentially no other peaks. Identify the compound. First,

1)  A compound gives a mass spectrum with peaks at m/z = 77 (40%), 112 (100%), 114 (33%), and essentially no other peaks. Identify the compound. First,
WM4 Instrumental analysis. The 3 key instrumental techniques How do we know that salicylic acid contains – OH and –COOH groups? Mass spectroscopy (m.s.).

WM4 Instrumental analysis. The 3 key instrumental techniques How do we know that salicylic acid contains – OH and –COOH groups? Mass spectroscopy (m.s.).
Chemical Symbols and Formulas

Chemical Symbols and Formulas
(slides can be accessed here)

(slides can be accessed here)
Chemical Shift. Carbon-13 Spectra How many C-13 signals? Which signals are further upfield? Can the compounds be differentiated?

Chemical Shift. Carbon-13 Spectra How many C-13 signals? Which signals are further upfield? Can the compounds be differentiated?
1) Draw a structure consistent with the following data:

1) Draw a structure consistent with the following data:
Aim: How can we calculate percent composition of a compound? Do Now: 1.Take out a calculator and reference tables. 2.What is the gram formula mass of C.

Aim: How can we calculate percent composition of a compound? Do Now: 1.Take out a calculator and reference tables. 2.What is the gram formula mass of C.
Mass Spectroscopy Mass spectroscopy is a powerful tool in organic chemistry that can be used to provide information about the molecular formula and structural.

Mass Spectroscopy Mass spectroscopy is a powerful tool in organic chemistry that can be used to provide information about the molecular formula and structural.

Similar presentations

Ads by Google