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Lecture 7UofH - COSC 3340 - Dr. Verma 1 COSC 3340: Introduction to Theory of Computation University of Houston Dr. Verma Lecture 7
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UofH - COSC 3340 - Dr. Verma 2 Are all languages regular? Ans: No. How do we know this? – Ans: Cardinality arguments. Let C(DFA) = {M | M is a DFA}. – C(DFA) is a countable set. Why? Let AL = { L | L is a subset of *}. – AL is uncountable.
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Lecture 7UofH - COSC 3340 - Dr. Verma 3 Cardinality Def: A set is countable if it is (i) finite or (ii) countably infinite. Def: A set S is countable infinite if there is a bijection from N to S. – Note: Instead of N to S we can also say S to N. N = {0, 1, 2, 3,...} -- the set of natural numbers. Def: A set that is not countable is uncountable. – Or, any infinite set with no bijection from N to itself.
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Lecture 7UofH - COSC 3340 - Dr. Verma 4 Examples 1. The set of chairs in this classroom is finite. 2. The set of even numbers is countably infinite. 3. The set of all subsets of N is uncountable. – Notation: 2 N
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Lecture 7UofH - COSC 3340 - Dr. Verma 5 Exercises What is the cardinality of? 1. Z - the set of integers. 2. N X N = {(a,b) | a, b in N}. 3. R - the set of real numbers.
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Lecture 7UofH - COSC 3340 - Dr. Verma 6 Pumping Lemma First technique to show that specific given languages are not regular. Cardinality arguments show existence of languages that are not regular. There is a big difference between the two!
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Lecture 7UofH - COSC 3340 - Dr. Verma 7 Statement of Pumping Lemma If A is a regular language, then there is a number p (the pumping length) where, if s is any string in A of length at least p, then s may be divided into three pieces, s = xyz, satisfying the following conditions: 1. for each i 0, xy i z A, 2. |y| > 0, and 3. |xy| p.
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Lecture 7UofH - COSC 3340 - Dr. Verma 8 Proof of pumping lemma Idea: If a string w of length m is accepted by a DFA with n states, and n < m, then there is a cycle (repeated state) on the directed path from s to a final state labeled w. – Recall: directed path is denoted by *(s,w). – Uses: Pigeon-hole principle
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Lecture 7UofH - COSC 3340 - Dr. Verma 9 Pigeon-hole principle 4 pigeons 3 pigeonholes
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Lecture 7UofH - COSC 3340 - Dr. Verma 10 Pigeon-hole principle (contd.) A pigeonhole must have two pigeons
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Lecture 7UofH - COSC 3340 - Dr. Verma 11 Pigeon-hole principle (contd.)........... pigeonholes
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Lecture 7UofH - COSC 3340 - Dr. Verma 12 Details of Proof of Pumping Lemma. Consider L - any infinite regular language. 1. L regular there is a DFA M with L(M) = L. 2. Let DFA have p states (say). 3. Let w in L be of length more than p. Why does w exist? Ans: because L is infinite. 4. *(s,w) = f (some final state) must be *(s, w = xyz) = *(q,yz) = *(q,z) = f 5. So xy n z in L for n = 0, 1, 2, 3,.... since *(s, xy n z) = *(q, y n z) = *(q, y {n-1} z) =... = *(q,z) = f.
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Lecture 7UofH - COSC 3340 - Dr. Verma 13 Describing the pumping lemma Take an infinite regular language DFA that accepts states
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Lecture 7UofH - COSC 3340 - Dr. Verma 14 Describing the pumping lemma (contd.) Take string with There is a walk with label:.........
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Lecture 7UofH - COSC 3340 - Dr. Verma 15 Describing the pumping lemma (contd.) If string has length number of states Then, from the pigeonhole principle: A state is repeated in the walk......
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Lecture 7UofH - COSC 3340 - Dr. Verma 16 Describing the pumping lemma (contd.) Write......
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Lecture 7UofH - COSC 3340 - Dr. Verma 17 Describing the pumping lemma (contd.) Observations :lengthnumber of states length......
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Lecture 7UofH - COSC 3340 - Dr. Verma 18 Describing the pumping lemma (contd.) The string is acceptedObservation:......
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Lecture 7UofH - COSC 3340 - Dr. Verma 19 Describing the pumping lemma (contd.)...... The string is accepted Observation:
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Lecture 7UofH - COSC 3340 - Dr. Verma 20 Describing the pumping lemma (contd.)...... The string is accepted Observation:
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Lecture 7UofH - COSC 3340 - Dr. Verma 21 Describing the pumping lemma (contd.)...... The string is accepted In General:
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Lecture 7UofH - COSC 3340 - Dr. Verma 22 Some Applications of Pumping Lemma The following languages are not regular. 1. {a n b n | n 0 }. 2. {w = w R | w in {a,b}* } (language of palindromes). 3. {ww R | w in {a,b}*}. 4. {a {n 2 } | n 0}.
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Lecture 7UofH - COSC 3340 - Dr. Verma 23 Tips of the trade -- Do not forget! Closure properties can be used effectively for: (1) shortening cumbersome Pumping lemma arguments. Example: {w in {a, b}* | w has equal a's and b's}. (2) for showing that certain languages are regular. Example: {w in {a, b}* | w begins with a and w contains a b}.
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Lecture 7UofH - COSC 3340 - Dr. Verma 24 References Pigeonhole Principle & Pumping Lema Description – www.cs.rpi.edu/courses/fall00/modcomp3/class8.ppt Author: Costas Busch, Rensselaer Polytechnic Institute, NY
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