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CPS110: Implementing threads/locks on a uni-processor Landon Cox
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Recall, thread interactions 1.Threads can access shared data Use locks, monitors, and semaphores What we’ve done so far 2.Threads also share hardware CPU (uni-processor) Memory
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Private vs global thread state What state is private to each thread? Code (like lines of a play) PC (where actor is in his/her script) Stack, SP (actor’s mindset) What state is shared? Global variables, heap (props on set)
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Thread control block (TCB) Running thread’s private data is on CPU Non-running thread’s private state is in TCB Thread control block (TCB) Container for non-running thread’s private data (PC, code, SP, stack, registers)
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Thread control block CPU Address Space TCB1 PC SP registers TCB1 PC SP registers TCB2 PC SP registers TCB2 PC SP registers TCB3 PC SP registers TCB3 PC SP registers Code Stack Code Stack Code Stack PC SP registers PC SP registers Thread 1 running Ready queue
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Thread control block CPU Address Space TCB2 PC SP registers TCB2 PC SP registers TCB3 PC SP registers TCB3 PC SP registers Code Stack PC SP registers PC SP registers Thread 1 running Ready queue
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Thread states Running Currently using the CPU Ready Ready to run, but waiting for the CPU Blocked Stuck in lock (), wait () or down ()
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Switching threads What needs to happen to switch threads? 1.Thread returns control to OS For example, via the “yield” call 2.OS chooses next thread to run 3.OS saves state of current thread To its thread control block 4.OS loads context of next thread From its thread control block 5.Run the next thread Project 1: swapcontext
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1. Thread returns control to OS How does the thread system get control? Could wait for thread to give up control (internal events) Thread might block inside lock or wait Thread might call into kernel for service (system call) Thread might call yield Are internal events enough?
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1. Thread returns control to OS External events (events not initiated by the thread) Hardware interrupts Transfer control directly to OS interrupt handlers From 104 CPU checks for interrupts while executing Jumps to OS code with interrupt mask set Interrupts lead to pre-emption (a forced yield) Common interrupt: timer interrupt
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2. Choosing the next thread If no ready threads, just spin Modern CPUs: execute a “halt” instruction Project 1: exit if no ready threads Loop switches to thread if one is ready Many ways to prioritize ready threads Will discuss a little later in the semester
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3. Saving state of current thread What needs to be saved? Registers, PC, SP What makes this tricky? Need registers to save state But you’re trying to save all the registers Saving the PC
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4. OS loads the next thread Where is the thread’s state/context? Thread control block (in memory) How to load the registers? Use load instructions to grab from memory How to load the stack? Stack is already in memory, load SP
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5. OS runs the next thread How to resume thread’s execution? Jump to the saved PC On whose stack are these steps running? or Who is running these steps? The thread that called yield (or was interrupted or called lock/wait) How does this thread run again? Some other thread must switch to it
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Example thread switching Thread 1 print “start thread 1” yield () print “end thread 1” Thread 2 print “start thread 2” yield () print end thread 2” yield () print “start yield (thread %d)” switch to next thread (swapcontext) print “end yield (thread %d)” Thread 1 output Thread 2 output -------------------------------------------- start thread 1 start yield (thread 1) start thread 2 start yield (thread 2) end yield (thread 1) end thread 1 end yield (thread 2) end thread 2 Note: this assumes no pre-emptions. Programmers must assume pre-emptions, so this output is not guaranteed.
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Creating a new thread Also called “forking” a thread Idea: create initial state, put on ready queue 1.Allocate, initialize a new TCB 2.Allocate a new stack 3.Make it look like thread was going to call a function PC points to first instruction in function SP points to new stack Stack contains arguments passed to function Project 1: use makecontext 4.Add thread to ready queue
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Using interrupt disable-enable Disable-enable on a uni-processor Assume atomic (can use atomic load/store) How do threads get switched out? Internal events (yield, I/O request) External events (interrupts, e.g. timers) Easy to prevent internal events Use disable-enable to prevent external events
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Why use locks? If we have disable-enable, why do we need locks? Program could bracket critical sections with disable-enable Might not be able to give control back to thread library Can’t have multiple locks (over-constrains concurrency) Project 1: only disable interrupts in thread library disable interrupts while (1){}
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Disable interrupts, busy-waiting Lock implementation #1 lock () { disable interrupts while (value != FREE) { enable interrupts disable interrupts } value = BUSY enable interrupts } unlock () { disable interrupts value = FREE enable interrupts } Why is it ok for lock code to disable interrupts? It’s in the trusted kernel (we have to trust something).
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Disable interrupts, busy-waiting Lock implementation #1 lock () { disable interrupts while (value != FREE) { enable interrupts disable interrupts } value = BUSY enable interrupts } unlock () { disable interrupts value = FREE enable interrupts } Do we need to disable interrupts in unlock? Only if “value = FREE” is multiple instructions (safer)
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Disable interrupts, busy-waiting Lock implementation #1 lock () { disable interrupts while (value != FREE) { enable interrupts disable interrupts } value = BUSY enable interrupts } unlock () { disable interrupts value = FREE enable interrupts } Why enable-disable in lock loop body? Otherwise, no one else will run (including unlockers)
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Using read-modify-write instructions Disabling interrupts Ok for uni-processor, breaks on multi-processor Why? Could use atomic load-store to make a lock Inefficient, lots of busy-waiting Hardware people to the rescue!
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Test&set, busy-waiting Initially, value = 0 Lock implementation #2 lock () { while (test&set(value) == 1) { } unlock () { value = 0 } What happens if value = 1? What happens if value = 0?
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Locks and busy-waiting All implementations have used busy-waiting Wastes CPU cycles To reduce busy-waiting, integrate Lock implementation Thread dispatcher data structures
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Interrupt disable, no busy-waiting Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts }
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } Who gets the lock after someone calls unlock? This is called a “hand-off” lock.
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } Who might get the lock if it weren’t handed-off directly? (e.g. if value weren’t set BUSY in unlock) This is called a “hand-off” lock.
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } What does this mean? Are we saving the PC? This is called a “hand-off” lock.
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } Why a separate queue for the lock? This is called a “hand-off” lock.
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } Project 1 note: you must guarantee FIFO ordering of lock acquisition. This is called a “hand-off” lock.
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { enable interrupts add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } When and how could this fail?
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock enable interrupts switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } When and how could this fail?
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } Putting lock thread on lock wait queue, switch must be atomic. Must call switch with interrupts off.
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How is switch returned to? Review from last time Think of switch as three phases Save current location (SP, PC) Point processor to another stack (SP’) Jump to another instruction (PC’) Only way to get back to a switch Have another thread call switch
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Lock implementation #3 lock () { disable interrupts if (value == FREE) { value = BUSY // lock acquire } else { add thread to queue of threads waiting for lock switch to next ready thread // don’t add to ready queue } enable interrupts } unlock () { disable interrupts value = FREE if anyone on queue of threads waiting for lock { take waiting thread off queue, put on ready queue value = BUSY } enable interrupts } What is lock() assuming about the state of interrupts after switch returns?
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Interrupts and returning to switch Lock() can assume that switch Is always called with interrupts disabled On return from switch Previous thread must have disabled interrupts Next thread to run Becomes responsible for re-enabling interrupts Invariants: threads promise to Disable interrupts before switch is called Re-enable interrupts after returning from switch
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Thread AThread B yield () { disable interrupts … switch enable interrupts } // exit thread library function lock () { disable interrupts … switch back from switch … enable interrupts } // exit yield unlock () // moves A to ready queue yield () { disable interrupts … switch back from switch … enable interrupts } // exit lock
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