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THIS LECTURE single From single to coupled oscillators.

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Presentation on theme: "THIS LECTURE single From single to coupled oscillators."— Presentation transcript:

1 THIS LECTURE single From single to coupled oscillators

2 Coupled pendula

3 Propagation of energy in space

4 Two thin rods connected by a pivot “Chaotic” motion Coupled pendula

5 Coupled oscillators Normal modes Modes of vibration in which each oscillator vibrates with same frequency Coupled motion implies energy exchange

6 Two coupled oscillators Newton equations k’ k k x1x1 x2x2 A 1, A 2,  1 and  2 are constants that depend on initial conditions

7 Two coupled oscillators Newton equations k’ k k x1x1 x2x2 A 1, A 2,  1 and  2 are constants that depend on initial conditions

8 Two coupled oscillators Newton equations k’ k k x1x1 x2x2 A 1, A 2,  1 and  2 are constants that depend on initial conditions

9 NORMAL MODES Each mass vibrates with the same frequency NORMAL MODE 1 Masses are in phase and vibrate with frequency Masses are in antiphase and vibrate with frequency NORMAL MODE 2

10 Problem At t =0, one mass is moved a distance 2a, but the second mass is held fixed. Find the time-dependence of x 1 and x 2. T2T2 T1T1

11 Two coupled oscillators: general case Newton equations k2k2 k1k1 k3k3 x1x1 x2x2 M m To find the normal modes, we assume that x 1 and x 2 are harmonic functions with same frequency . Normal modes

12 Two coupled oscillators: general case Newton equations k2k2 k1k1 k3k3 x1x1 x2x2 M m To find the normal modes, we assume that x 1 and x 2 are harmonic functions with same frequency . Normal modes Newton equations

13 Two coupled oscillators: general case Newton equations k2k2 k1k1 k3k3 x1x1 x2x2 M m This system of equations has solution if the determinant of its coefficients vanishes This is a quadratic equation in the variable . It has two solutions,  1 and  2, corresponding to two normal modes.

14  1 and  2 corresponding to two normal modes NORMAL MODE 1NORMAL MODE 2 The most general solution is the superposition of the two modes. Two coupled oscillators: general case k2k2 k1k1 k3k3 x1x1 x2x2 M m

15 Crystals Coupled oscillators

16 N coupled oscillators z y x Method to describe the motion Consider separate motion along x, y, z Write down Newton equations for the displacement of each mass along a given direction, for example x. Displacements are called x 1, x 2, x 3 …x N. Normal modes Determine the normal modes for each variable x 1, x 2 …x N to obtain equations that describe harmonic motion


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