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Published byDominic Manning Modified over 9 years ago
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Free Streamline Theory Separated Flows Wakes and Cavities
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Flow approximation Viscosity is necessary to provoke separation, but if we introduce the separation "by hand", viscosity is not relevant anymore. Solves the D'Alambert Paradoxe : Drag on bodies with zero viscosity
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3.1 Flow over a plate The pressure (and then the velocity modulus) is constant along the separation streamline = The separation streamline is a free streamline is the cavity parameter
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3.1 Flow over a plate
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Separation has to be smooth otherwise U=0 at separation is not consistent with the velocity on the free stream line Form of the potential near separation
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3.1 Flow over a plate Cases study with k
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3.1 Flow over a plate Villat condition U S =U : the cavity pressure is the lowest Subcritical flow Supercritical flow 1. Separation angle deduced from Villat condition (k= 0 at separation) 2. Pressure cavity is prescribed to p
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3.1 Flow over a plate Subcritical flow Supercritical flow 1. Separation angle is prescribed and k>0 2. Pressure cavity is prescribed to p
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3.1 Flow over a plate
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Flow boundaries in the z-plane (physical space) Represent the flow in the -plane and then apply the SC theorem (W=0)
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3.1 Flow over a plate Show that +1
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3.1 Flow over a plate Represent the flow in the W-plane and then in the W 1/2 plane (W=0)
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3.1 Flow over a plate Show that : +1
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3.1 Flow over a plate Correspondance between two half planes gives : Extract and show that :
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3.1 Flow over a plate Compute z 0 and k = d/(4+ ) and the shape of the free streamline
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3.1 Flow over a plate From the pressure distribution around the plate, the drag is: In experiments, C D 2
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Similar problem with circular cylinder : C D0 =0.5 while in experiments C D 1.2 The pressure in the cavity is not p , but lower !
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1. Separation angle is prescribed and k>0 2. Pressure cavity is prescribed to p b It is a fit of the experimental data ! Improvment of the theory
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3.1 Flow over a plate Work only if the separation position is similar to that of the theory at p c =p ( i.e. C =0, is called the Helmholtz flow that gives C D0 )
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3.1 Flow over a plate A cavity cannot close freely in the fluid (if no gravity effect) Closure models L/d ~ (-C pb ) -n
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Limiting of the stationary NS solution as Re ∞ Academic case L ~ d Re Imagine the flow stays stationary as Re ∞ free streamline theory solution (b) and (c) Stationary simulation of NS (a) Theoretical sketch A candidate solution of NS as Re ∞ ? Cpb 0 Cx 0.5 L = O(Re) : infinite length Kirchoff helmholtz flow :
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Limiting stationary solution as Re ∞ Academic case Cpb>0 !!! C D 0 ? Numerical simulation
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Limiting stationary solution as Re ∞ Academic case (b) and (c) Stationary simulation of NS (a) Theoretical sketch A possibility :Non uniqueness of the Solution as Re
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Super cavitating wakes Kirchoff helmholtz flow ? : vapor liquid
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Super cavitating wakes
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