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Solutions Chapter 12 Modern Chemistry
Sections 1-3 Types of Mixtures The Solution Process Concentrations of Solution Chapter 12 Section 3 Concentration of Solutions p
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Concentration of Solutions
Section 12.3 Concentration of Solutions Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Vocabulary Concentration Concentrated Dilute Molarity Molality Dilution Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
CONCENTRATED DILUTE CONCENTRATION MOLARITY MOLALITY DILUTIONS Concept Map 12.3 Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Concentration is a measure of the amount of solute in a given amount of solvent or solution. Dilute means that there is a small amount of solute. Concentration means that there is a large amount of solute. There are many ways to quantify concentration. Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Concentration Units Chapter 12 Section 3 Concentration of Solns p
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Concentration & Molarity
Chapter 12 Section 3 Concentration of Solns p p. xx
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Molarity The number of moles of solute in one liter of solution. moles of solute M = liters of solution M = mol L Chapter 12 Section 3 Concentration of Solns p
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Making a Molar Solution
Chapter 12 Section 3 Concentration of Solns p p. 419
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Making a Molar Solution
Insert Holt Disc 2 Chapter 12 Section 3 Concentration of Solns p p. xx
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Molarity Sample Problems
You have 3.50 L of solution that contains 90.0 g of sodium chloride, NaCl. What is the molarity of that solution? You have 0.8 L of a 0.5 M HCl solution. How many moles of HCl does this solution contain? To produce 40.0 g of silver chromate, you will need at least 23.4 g of potassium chromate in solution as a reactant. All you have on hand is 5 L of a 6.0 M K2CrO4 solution. What volume of the solution is needed to give you the 23.4 g K2CrO4 needed for the reaction? M NaCl p mol HCl L K2CrO4 Chapter 12 Section 3 Concentration of Solns p
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Molarity Practice Problems
What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved in enough water to make L of solution? How many moles of H2SO4 are present in L of a M H2SO4 solution? What volume of 3.00 M NaCl is needed for a reaction that requires g of NaCl? M KI p. 421 mol L Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Molarity vs. Molality Chapter 12 Section 3 Concentration of Solns p p. xx
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Molality The number of moles of solute per kilogram of solvent. moles of solute m = kilograms of solvent m = mol Kg The density of water is 1 g / mL. So, 1 g = 1 mL and 1kg = 1 L Chapter 12 Section 3 Concentration of Solns p
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Making a Molal Solution
Chapter 12 Section 3 Concentration of Solns p p. 422
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Molality Sample Problems
A solution was prepared by dissolving 17.1 g of sucrose (table sugar, C12H22O11) in 125 g of water. Find the molal concentration of this solution. A solution of iodine, I2, in carbon tetrachloride, CCl4, is used when iodine is needed for certain chemical tests. How much iodine must be added to prepare a m solution of iodine in CCl4 if g of CCl4 is used? m C12H22O11 p g I2 Chapter 12 Section 3 Concentration of Solns p
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Molality Practice Problems
What is the molality of acetone in a solution composed of 255 g of acetone, (CH3)2CO, dissolved in 200. g of water? What quantity, in grams, of methanol, CH3OH, is required to prepare a m solution in 400. g of water? m acetone p. 424 g CH3OH Chapter 12 Section 3 Concentration of Solns p
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M1 V1 = M2 V2 Diluting a Solution
How much of an original solution is needed to make a less concentrated solution by adding water? M1 V1 = M2 V2 Volume of New Solution Wanted Original Molarity Volume of Original Solution Needed New Molarity Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Diluting a Solution Insert Holt Disc 2 Chapter 12 Section 3 Concentration of Solns p p. xx
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Dilution Problems P. 902 # What is the molarity of a solution of ammonium chloride prepared by diluting mL of a 3.79 M NH4Cl solution to 2.00 L? P. 903 #370. To what volume should 1.19 mL of an 8.00 M acetic acid solution be diluted in order to obtain a final solution that is M? M 6.35 mL Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Dilution Problems P. 903 # What volume of a 5.75 M formic acid solution should be used to prepare 2.00 L of a 1.00 M formic acid solution? P. 903 #372. A mL sample of ammonium nitrate solution produces a M solution when diluted with mL of water. What is the molarity of the stock solution? 348 mL 0.558 M Chapter 12 Section 3 Concentration of Solns p
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Chapter 12 Section 3 Concentration of Solns p. 418-424
Ch 12 Sec 3 Homework Molarity, Molality, Dilution Problem Bank Page # , , 375 Chapter 12 Section 3 Concentration of Solns p
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