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6-2 properties of parallelograms

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1 6-2 properties of parallelograms
Chapter 6 6-2 properties of parallelograms

2 Objectives Prove and apply properties of parallelograms. Use properties of parallelograms to solve problems.

3 Parallelograms Any polygon with four sides is a quadrilateral. However, some quadrilaterals have special properties. These special quadrilaterals are given their own names.

4 Parallelograms A quadrilateral with two pairs of parallel sides is a parallelogram. To write the name of a parallelogram, you use the symbol

5 Properties of parallelograms

6 Properties of parallograms

7 Example#1 Properties of parallelogram
In CDEF, DE = 74 mm, DG = 31 mm, and m FCD = 42°. Find CF. CF = DE CF = 74 mm

8 Example#2 In CDEF, DE = 74 mm, DG = 31 mm, and mFCD = 42°. Find mEFC. mEFC + mFCD = 180° mEFC + 42 = 180 mEFC = 138°

9 Example#3 In CDEF, DE = 74 mm, DG = 31 mm, and mFCD = 42°. Find DF.
DF = 2DG DF = 2(31) DF = 62

10 Example 2A: Using Properties of Parallelograms to Find Measures
WXYZ is a parallelogram. Find YZ. YZ = 8a – 4 = 8(7) – 4 = 52 YZ = XW 8a – 4 = 6a + 10 2a = 14 a = 7

11 Example WXYZ is a parallelogram. Find mZ . mZ + mW = 180°
(9b + 2) + (18b – 11) = 180 27b – 9 = 180 27b = 189 b = 7 mZ = (9b + 2)° = [9(7) + 2]° = 65°

12 Example 3: Parallelograms in the Coordinate Plane
Three vertices of JKLM are J(3, –8), K(–2, 2), and L(2, 6). Find the coordinates of vertex M. Since JKLM is a parallelogram, both pairs of opposite sides must be parallel.

13 solution Step 1 Graph the given points. J K L

14 solution Step 2 Find the slope of by counting the units from K to L.
The rise from 2 to 6 is 4. The run of –2 to 2 is 4. Step 3 Start at J and count the same number of units. A rise of 4 from –8 is –4. A run of 4 from 3 is 7. Label (7, –4) as vertex M.

15 solution J K L M The coordinates of vertex M are (7, –4).

16 Example 4A: Using Properties of Parallelograms in a Proof
Write a two-column proof. Given: ABCD is a parallelogram. Prove: ∆AEB  ∆CED

17 Continue Proof: Statements Reasons 3.  diags. bisect each other
1. ABCD is a parallelogram 1. Given  opp. sides  4. SSS Steps 2, 3

18 Example Write a two-column proof.
Given: GHJN and JKLM are parallelograms. H and M are collinear. N and K are collinear. Prove: H M

19 solution Statements Reasons 1. GHJN and JKLM are parallelograms.
1. Given 2. H and HJN are supp. M and MJK are supp.  cons. s supp. 3. HJN  MJK 3. Vert. s Thm. 4. H  M 4.  Supps. Thm.

20 Example Write a two-column proof.
Given: GHJN and JKLM are parallelograms. H and M are collinear. N and K are collinear.

21 solution Statements Reasons 1. RSTU is a parallelogram. 1. Given
2. N and HJN are supp. K and MJK are supp.  cons. s supp. 3. HJN  MJK 3. Vert. s Thm. 4. N  K 4.  Supps. Thm.

22 Student guided Practice
Do even problems from 2-14 in your book page 407

23 Homework Do even problems in your book page 407

24 Closure Today we learned about properties of parallelograms

25 Have a great day


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