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Additional Practice problem Solutions

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Presentation on theme: "Additional Practice problem Solutions"— Presentation transcript:

1 Additional Practice problem Solutions
From chemistry class 3/30

2 Additional Practice Problems
How many moles are equal to 9.03 x 1024 atoms of mercury? How many atoms are in 1.00 mole of sucrose, C12H22O11? How many atoms of O are in 3.65 moles of C12H22O11?

3 Answers to Practice Problems
x 1024 atoms x mole x 1023 atoms = moles mole x x 1023 mlcs x atoms mole mlc = 2.71 x 1025 atoms mol x x 1023 mlcs x atoms of O mole mlc C12H22O11 = x 1025 atoms O

4 Additional Practice Problems
1. What is the mass, in grams, of 1.72 mol CaCl2? 2. Determine the mass of one mole of each of the following compounds and give their names. (Fill in the chart)

5 Answers to Practice Problems
mol x g mol = g

6 Answers to Practice Problems
Compound Mass in One Mole Name a. CO2 44.01 g carbon dioxide b. SO3 80.07 g sulfur trioxide c. NaOH 40.01 g sodium hydroxide d. Al2(SO4)3 g aluminum sulfate e. Ba(NO3)2 g barium nitrate

7 Additional Practice Problems
Calculate the mass in grams for mol of each of the following compounds: sucrose (C12H22O11) sodium chloride potassium permanganate

8 Answers to Practice Problems
Calculate the mass in grams for mol of each of the following compounds: sucrose (C12H22O11) 0.250 mol x g = g C12H22O11 mol sodium chloride 0.250 mol x g = g NaCl potassium permanganate 0.250 mol x g = g KMnO4 mol


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