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Lesson Menu Five-Minute Check (over Lesson 8–6) CCSS Then/Now New Vocabulary Example 1:Represent Vectors Geometrically Key Concept: Vector Addition Example 2:Find the Resultant of Two Vectors Example 3: Write a Vector in Component Form Example 4: Find the Magnitude and Direction of a Vector Key Concept: Vector Operations Example 5: Operations with Vectors Example 6:Real-World Example: Vector Applications
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Over Lesson 8–6 5-Minute Check 1 A.50.1 B.44.6 C.39.3 D.35.9 Find s if the measures of ΔRST are m R = 63, m S = 38, and r = 52.
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Over Lesson 8–6 5-Minute Check 2 A.21.3 B.24.1 C.29 D.58 Find m R if the measures of ΔRST are m S = 122, s = 10.8, and r = 5.2.
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Over Lesson 8–6 5-Minute Check 3 A.12.7 B.10.8 C.9.62 D.8.77 Use the measures of ΔABC to find c to the nearest tenth.
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Over Lesson 8–6 5-Minute Check 4 A.21° B.19° C.18° D.16° Use the measures of ΔABC to find m B to the nearest degree.
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Over Lesson 8–6 5-Minute Check 5 A.21 mi B.18 mi C.16 mi D.15.5 mi On her delivery route, Gina drives 15 miles west, then makes a 68° turn and drives southeast 14 miles. When she stops, approximately how far from her starting point is she?
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CCSS Content Standards G.GPE.6 Find the point on a directed line segment between two given points that partitions the segment in a given ratio. Mathematical Practices 1 Make sense of problems and persevere in solving them. 4 Model with mathematics.
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Then/Now You used trigonometry to find side lengths and angle measures of right triangles. Perform vector operations geometrically. Perform vector operations on the coordinate plane.
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Vocabulary vector magnitude direction resultant parallelogram method triangle method standard position component form
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Example 1 Represent Vectors Geometrically A. Use a ruler and a protractor to draw each vector. Include a scale on each diagram. = 80 meters at 24° west of north Using a scale of 1 cm : 50 m, draw and label an 80 ÷ 50 or 1.6-centimeter arrow 24º west of the north- south line on the north side. Answer:
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Example 1 Represent Vectors Geometrically B. Use a ruler and a protractor to draw each vector. Include a scale on each diagram. = 16 yards per second at 165° to the horizontal Using a scale of 1 cm : 8 yd/s, draw and label a 16 ÷ 8 or 2-centimeter arrow at a 165º angle to the horizontal. Answer:
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Example 1 Using a ruler and a protractor, draw a vector to represent feet per second 25 east of north. Include a scale on your diagram. A. B. C. D.
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Concept
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Example 2 Find the Resultant of Two Vectors Subtracting a vector is equivalent to adding its opposite. a b Copy the vectors. Then find
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Example 2 Method 1Use the parallelogram method. Find the Resultant of Two Vectors –b a a Step 1, and translate it so that its tail touches the tail of.
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Example 2 Step 2Complete the parallelogram. Then draw the diagonal. Find the Resultant of Two Vectors a – b –b a
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Example 2 Method 2Use the triangle method. Find the Resultant of Two Vectors –b a Step 1, and translate it so that its tail touches the tail of.
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Example 2 Find the Resultant of Two Vectors Step 2Draw the resultant vector from the tail of to the tip of –. Answer: a – b a –b a – b
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Example 2 Copy the vectors. Then find A.B. C.D. a – b ba
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Example 3 Write a Vector in Component Form Write the component form of.
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Example 3 Find the change of x-values and the corresponding change in y-values. Component form of vector Simplify. Write a Vector in Component Form
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Example 3 Write the component form of. A. B. C. D.
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Example 4 Find the Magnitude and Direction of a Vector Step 1Use the Distance Formula to find the vector’s magnitude. Simplify. Use a calculator. Find the magnitude and direction ofDistance Formula (x 1, y 1 ) = (0, 0) and (x 2, y 2 ) = (7, –5)
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Example 4 Find the Magnitude and Direction of a Vector Graph, its horizontal component, and its vertical component. Then use the inverse tangent function to find θ. Step 2Use trigonometry to find the vector’s direction.
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Example 4 Find the Magnitude and Direction of a Vector Definition of inverse tangent Use a calculator.The direction of is the measure of the angle that it makes with the positive x-axis, which is about 360 – 35.5 or 324.5. So, the magnitude of is about 8.6 units and the direction is at an angle of about 324.5º to the horizontal. Answer:
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Example 4 A.4; 45° B.5.7; 45° C.5.7; 225° D.8; 135° Find the magnitude and direction of
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Concept
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Example 5 Operations with Vectors Solve Algebraically Find each of the following for and. Check your answers graphically. A. Check Graphically
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Example 5 Operations with Vectors Solve Algebraically Find each of the following for and. Check your answers graphically. B. Check Graphically
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Example 5 Operations with Vectors Solve Algebraically Find each of the following for and. Check your answers graphically. C. Check Graphically
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Example 5 A. B. C. D.
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Example 6 Vector Applications CANOEING Suppose a person is canoeing due east across a river at 4 miles per hour. If the river is flowing south at 3 miles per hour, what is the resultant speed and direction of the canoe? Draw a diagram. Let represent the resultant vector.
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Example 6 Vector Applications The component form of the vector representing the velocity of the canoe is 4, 0 , and the component form of the vector representing the velocity of the river is 0, –3 . The resultant vector is 4, 0 + 0, –3 or 4, –3 , which represents the resultant velocity of the canoe. Its magnitude represents the resultant speed.
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Example 6 Use the Distance Formula to find the resultant speed. Distance Formula (x 1, y 1 ) = (0, 0) and (x 2, y 2 ) = (4, –3) The resultant speed of the canoe is 5 miles per hour. Vector Applications
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Example 6 Use trigonometry to find the resultant direction. Use a calculator. Vector Applications Definition of inverse tangent The resultant direction of the canoe is about 36.9° south of due east. Answer: Therefore, the resultant speed of the canoe is 5 mile per hour at an angle of about 90° – 36.9° or 53.1° east of south.
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Example 6 A.Direction is about 60.3° south of due east with a velocity of about 8.1 miles per hour. B.Direction is about 60.3° south of due east with a velocity of about 11 miles per hour. C.Direction is about 29.7° south of due east with a velocity of about 8.1 miles per hour. D.Direction is about 29.7° south of due east with a velocity of about 11 miles per hour. KAYAKING Suppose a person is kayaking due east across a lake at 7 miles per hour. If the lake is flowing south at 4 miles an hour, what is the resultant direction and speed of the canoe?
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End of the Lesson
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