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Frequency domain Image Processing Comp344 Tutorial Kai Zhang
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Outline Complex Number Multiplication Histogram equalizarion How to understand digital frequency High Pass Filters
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Question: given a FFT transform F(u), is the following true? Proof (exercise)
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Histogram Equalization Problem Given one random variables, x, with known probability distribution p x (x). Another variable has the relation y = T(x) What is the pdf of random variable y, p y (y) ? Basic theorem in statistics: Let x = T -1 (y); Then we have: p y (y) = p x (T -1 (y))|dT -1 (y)/dy|.
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Example Suppose x is uniformly distributed as Let y = 2x, T(x) = 2x Then we have: The domain of the new pdf can be obtained by 0<0.5y<1, i.e., 0<y<2.
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Example(histeq) Now, suppose the transform function is Then what will be the resultant pdf for y? First, note that Then we have
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Digital frequency
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Signal 1 [1 1 -1 -1 1 1 -1 -1 …..] 1024 points Signal 2 [1 -1 1 -1 1 -1…..] 1024 points
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Observations Given a signal of length M The highest possible frequency is the signal that ``vibrates’’ M/2 times. So such signal has the highest digital frequency M/2 This is why for a signal with length M, the frequency domain has two symmetric part each with upper bound M/2. In case the signal is associated with its own time stamp, the the frequency component by FFT can also be transferred properly to reflect the actual frequency in iterms of Hz.
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High Parss Filters Examples High pass filter: H_hp(u,v) = 1 – H_lp(u,v) Ideal high pass filter Bartworth high pass filter Gaussian high pass filter
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