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On Neighbors in Geometric Permutations Shakhar Smorodinsky Tel-Aviv University Joint work with Micha Sharir
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Geometric Permutations n A - a set of disjoint convex bodies in R d n A line transversal l of A induces a geometric permutation of A l2l2 l1l1 1 2 3 l 1 : l 2 :
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3 Example 3 12
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An example of S with 2n-2 geometric permutations (Katchalski, Lewis, Zaks - 1985) 1 2 3 n-2
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Motivation? Trust me ……………. There is some!
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Problem Statement g d (A) = the number of geometric permutations of A g d (n) = max |A|=n {g d (A)} ? < g d (n) < ?
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Known Facts n g 2 (n) = 2n-2 (Edelsbrunner, Sharir 1990) n g d (n) = (n d-1 ) (Katchalski, Lewis, Liu 1992) n g d (n) = O(n 2d-2 ) (Wenger 1990) n Special cases: n n arbitrary balls in R d have at most (n d-1 ) GP’s (Smorodinsky, Mitchell, Sharir 1999) n The (n d-1 ) bound extended to fat objects (Katz, Varadarajan 2001) n n unit balls in R d have at most O(1) GP’s (Zhou, Suri 2001) 4
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8 Overview of our result n Define notion of “Neighbors” n Neighbors Lemma: few neighbors => few permutations n In the plane (d = 2) few neighbors n Conjecture: few neighbors in higher dimensions (d > 2)
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Definition A- a set of convex bodies in R d A pair (b i, b j ) in A are called neighbors If geometric permutation for which bi, bj appear consecutive: bibi bjbj
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10 Neighbors 1 2 3 n-2 Example (2,3) (2,4) ….. (2,n-2)
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11 Neighbors No neighbors !!!
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Neighbors Lemma In R d, if N is the set of neighbor pairs of A, then g d (A)=O(|N| d-1 ). b1b1 b2b2 h b1b1 b2b2. h Unit Sphere S d-1 b 1 is crossed before b 2 Proof : Fix a neighbor pair ( b 1,b 2 ) in N.
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Neighbors Lemma (cont) In R d, if N is the set of neighbor pairs of A, then g d (A)=O(|N| d-1 ). Let P be a set of |N| separating hyperplanes (A hyperplane for each one of the neighbor pairs)
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Consider the arrangement of great circles that correspond to hyperplanes in P. A fixed permutation in C C connected component C => Unique GP Unit Sphere S d-1 # connected component < O(|N| d-1 )
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Conjecture: The # neighbors of n convex bodies in R d is O(n) If true, implies a (n d-1 ) upper bound on g d (n)! Else, Return (to SWAT 2004) ;
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Upper Bound: #neighbors in the plane O(n) upper bound on the # neighbors in the plane Construct a “neighbors graph” 3 1 4 2 5
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Neighbors Graph (cont) 3 1 4 2 5 Connect neighbors as follows: In this drawing rule there may exist crossings
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Neighbors Graph (cont) : n However : there are no three pairwise crossing edges (technical proof) Theorem: [Agarwal et al. 1997] A quasi-planar graph with n vertices has O(n) edges. n A graph that can be drawn in the plane with n no three pairwise crossing edges is called a quasi-planar graph.
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Further research n Prove: O(n) neighbors in any fixed dimension. n In the plane: Is the neighbors graph planar?
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