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Free Particle (x) = A cos(kx) or (x) = A sin(kx) (x)= A e ikx = A cos(kx) + i A sin(kx) (x)= B e -ikx = B cos(kx) - i B sin(kx)
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Free Particle (x)= A e ikx +B e -ikx is a solution A and B are constants hence (x,t)= (x)e -i t = A e i(kx- t) +B e -i(kx+ t) Travelling wave to right Travelling wave to left
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Free Particle (x,t)= A e i(kx- t) is matter wave travelling to the right(along the positive x-axis) *(x,t)= A* e -i(kx- t) | (x,t)| 2 = (x,t) *(x,t)= AA* =|A| 2 intensity of wave is constant! Probability is the same everywhere a free particle is equally likely to be found anywhere
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P(x,t)= | (x,t)| 2 is probability of finding a particle at position x at time t total probability of finding it somewhere is Free Particle consider a classical point particle moving back and forth with constant speed between two walls located at x=0 and x=8cm particle spends same amount of time everywhere P(x)=P 0 if 0< x < 8 cm P(x)=0 if x 8cm
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Free Particle Since hence P 0 = (1/8) cm -1 ===> probability/unit length is 1/8 probability of finding particle in length dx is (1/8)dx probability of finding it at x=2cm is zero! (dx=0) Probability of finding it in some range 1.9 to 2.1 is (1/8) x = (1/8)(2.1-1.9)=.025
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Free Particle Probability of finding it between x=0 and x=8cm is (1/8)(8-0) = 1 intensity of wave is constant! Probability is the same everywhere a free particle is equally likely to be found anywhere free particle has definite energy E=(1/2)mv 2 and momentum p=mv but uncertain position
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R+T=1 Barrier Tunneling consider a barrier E < U 0 U0U0
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Schrodinger Solution Consider the three regions : left of barrier, right of barrier and in the barrier left: right: inside: U0U0
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Barrier Tunneling Solution inside barrier has form since P(x) is smaller as U 0 increases Tunneling
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Transmission coefficient T ~ e -2kL k={8 2 m(U 0 -E)/h 2 } 1/2 Note: E < U 0 if T=.02 then for every 1000 electrons hitting the barrier, about 20 will tunnel extremely sensitive to L and k width and height of barrier
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