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Weak Acids Acidity and Behavior, the Vinegar Example
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Two forms of the acid exist in solution Free AcidConjugate Base Acetic AcidAcetate Ion Crosses membranes easilyDoes not cross membranes VolatileNon-volatile SmellsLess Smell
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Weak Acids Dissociate Poorly as Seen by Their Dissociation Constants, Ka In other words, only one in a hundred protons dissociates!
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And Its -log 10, pK a pKa = -log 10 K a K a for acetic acid is 1.76 x 10 -5 M, pK a = -log 1.76 x 10 -5 = ? pKa for formic acid is 3.75, K a = 10 -pKa = 10 -3.75 = ?
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Table 1. Titration of 5% Acetic Acid With 1 M NaOH μL Base AddedpH 02.5 1004.0 2004.5 3004.5 4005.0 5005.0 6005.5 7006.0 8008.0 90011.0
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Figure 1. Titration of 5% Acetic Acid With 1 M NaOH
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Which Form Will Be Present? Free acid form occurs at low pH Conjugate base occurs at high pH At some point amount of acid equals amount of base
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Henderson-Hasselbalch Equation
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Predicts the Ratio of Acid and Base, What is the ratio of Ac - to HAc at pH 2.8? (See example on the right) Practice: What is the ratio of Ac - to HAc at pH 6.8?
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but Not the pH pK a is the pH where there are equal amounts of free acid and conjugate base pH is dependent on the concentration of acid as well as its pKa pKa ≠ pH of a solution, pH is usually <pKa The above formula is derived from the equilibrium constant equation assuming [H + ] = [Ac - ], and [HAc] >> [Ac - ] The lower the pKa, the less valid the last assumption is.
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What’s going on at pKa? Or When does [HAc] = [Ac - ]? When pH = pKa you can simplify the notation by representing the ratio with r, replace it in the equation, and solve its value. The ratio is 1 only when
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Landmarks on the titration curve pKa [HAc] = [Ac - ] Mostly HAc Present Mostly Ac - Present
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Behavior of Vinegar pH of solution barely changes when base added Strong smell, crosses membranes Does not smell, can’t cross membranes
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