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WIND POWER POWER AVAILABLE FROM THE WIND PERFORMANCE OF A HAWT DESIGN PROCEDURES.

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Presentation on theme: "WIND POWER POWER AVAILABLE FROM THE WIND PERFORMANCE OF A HAWT DESIGN PROCEDURES."— Presentation transcript:

1 WIND POWER POWER AVAILABLE FROM THE WIND PERFORMANCE OF A HAWT DESIGN PROCEDURES

2 ANNUAL WIND ENERGY AVAILABLE AT 50m, IN MWh/m2

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10 LIFTING DEVICE LIKE AN AIRCRAFT WING OR HELIPCOPTER ROTOR. PRESSURE DIFFERENCE PRODUCES A FORCE A COMPONENT OF THE FORCE ACTS TO PRODUCE ROTATION AND THE OTHER COMPONENT ACTS ON THE TOWER.

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14 SIMPLE WIND TURBINE THEORY POWER COMES FROM KE OF WIND THERE IS AN OPTIMUM POWER EXTRACTION RATE CAN ESTIMATE FROM APPLICATION OF CONSERVATION PRINCIPLES FORCE-MOMENTUM & BERNOULLI

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16 CONTROL VOLUME FOR SIMPLE ANALYSIS OF WIND TURBINE PERFORMANCE

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22 ACTUAL PERFORMANCE CANNOT TAKE ALL POWER OUT OF WIND SINCE THIS WOULD SHROUD THE TURBINE IN STILL AIR THEORETICAL MAX POWER IS 59% PRACTICAL VALUE IS 45% eg V = 10m/s, (Force 5) Power = 270 W/m2

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25 EFFECT OF TIP-SPEED RATIO OPTIMUM T/S DEPENDS ON WIDTH & NUMBER OF BLADES – SOLIDITY BLADES NEED TO INTERACT WITH AS MUCH AIR AS POSSIBLE & FILL UP THE SWEPT AREA MANY BLADES – HIGH SOLIDITY – LOW TIP SPEED FEW BLADES – LOW SOLIDITY – HIGH TIP SPEED UPPER LIMIT OF TIP SPEED - COMPRESSIBILTY

26 TIP-SPEED RATIO TOO LOW A SPEED - WIND GETS THROUGH WITH NO CONTACT TOO HIGH A SPEED – BLADES OFFER TOO MUCH RESISTANCE – WIND GOES ROUND THE TURBINE Eg 2 BLADED ROTOR HAS T/S 1/3 rd HIGHER THAN A 3 BLADED ROTOR OPTIMUM T/S BETWEEN 6 & 20

27 BLADES TOO MANY BLADES – INTERFERENCE- SO HIGH SOLIDITY TURBINES LESS EFFICIENT 3 BLADES TEND TO BE BEST GENERATORS RUN AT HIGH SPEED SO NEED A GEARBOX SO LOW SOLIDITY GOOD BECAUSE THEY RUN AT HIGH SPEED

28 RPM MUST BE CONSTANT WHATEVER V DEPENDS ON NUMBER OF POLES IN ELECTROMAGNET N = CONSTANT = 6000/POLES POLES = 6, 8 ETC TURBINE MAY HAVE 2 OPERATING VALUES OF N, DEPENDING ON V

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30 POWER OUTPUT FROM A HAWT SEE “WINDTURB” IN RESOURCE FILE POWER IN WIND VS WINDSPEED WINDSPEED FREQUENCY DISTRIBUTION POWER CURVE OF TURBINE ANNUAL POWER OUTPUT EFFICIENCY VS WINDSPEED

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33 POWER OUTPUT CURVE FOR A TURBINE 6.5 m/s = 15mph = Force 4 A moderate wind

34 RAYLEIGH FREQUENCY DISTBN MEAN WIND SPEED F IS THE FRACTION OF 8760 HOURS WHEN THE WIND IS AT SPEED V. MEAN WIND SPEED IS 5 m/s.

35 EFFECT OF Vm ON RAYLEIGH DISTRBN

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37 EFFICIENCY = POWER OUTPUT/POWER IN WIND

38 FORCES ON TURBINES VERTICAL WIND SHEAR HORIZONTAL WIND SHEAR WIND GUSTS GRAVITY TOWER SHADOW

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48 CONCLUSIONS A DILUTE FORM OF ENERGY NEED TO PROCESS LARGE VOLUMES NOT ECONOMIC UNLESS USE NFFO NOT THE ANSWER TO GROWING ENERGY CRISIS NEEDS ENERGY STORAGE SYSTEM CAN DISPLACE UP TO 10% OF ELECTRICAL SUPPLIES


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