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Atóm / frumeind: Kjarni: p, + n, 0 rafeind: e - 0.1 nm 0.1 10 -9 m 10 -10 m ?

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Presentation on theme: "Atóm / frumeind: Kjarni: p, + n, 0 rafeind: e - 0.1 nm 0.1 10 -9 m 10 -10 m ?"— Presentation transcript:

1 Atóm / frumeind: Kjarni: p, + n, 0 rafeind: e - 0.1 nm 0.1 10 -9 m 10 -10 m ?

2 ?   ? Engin bylgja(?) Engin rafeind(?)

3 ?   Standandi bylgja Rafeind á “braut”

4

5

6 Energy n=1 n=2 n=3 n  : 0 - En, 3 þrívídd ?

7  2 (r) r

8 Þ.e. líkindasvæði   2 (x,y,z)

9 n....... n+1.......n+2........ n S - svigrúm

10  2 (r,  ) r 

11 Svigrúm er fyrir 2 e - per Líkindasvæði (Svigrúm) - með andstæðar innbyrðis spunastefnu:

12 E n = 1 n = 2 n = 3 : n = 4 l = 0/sl = 1/pl = 2/dl = 3/f :::: :::: ::::. 1x e - H. H: 1s 1 ; grunnorka H*: > 1s 1 ; orkuríkt

13    R 2 r Na: 1s 2 2s 2 2p 6 3s Na + : 1s 2 2s 2 2p 6 Skermun: 3s Na*: 1s 2 2s 2 2p 6 3p 3p Na**: 1s 2 2s 2 2p 6 3d 3d

14 E n = 1 n = 2 n = 3 : n = 4 l = 0/sl = 1/pl = 2/dl = 3/f :::: :::: ::::. A > H. t.d. C (6e - ) C: 1s 2,2s 2,2p 2 C*, t.d. : 1s 2,2s 2,2p 1 3s 1

15 E n = 1 n = 2 n = 3 : n = 4 l = 0/sl = 1/pl = 2/dl = 3/f :::: :::: ::::. A > H. t.d. C (6e - )


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