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Slide 1UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE 4-Hybrid Thermal Test System Status 3 June Sam Burke UCSB HEP Group.

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Presentation on theme: "Slide 1UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE 4-Hybrid Thermal Test System Status 3 June Sam Burke UCSB HEP Group."— Presentation transcript:

1 Slide 1UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE 4-Hybrid Thermal Test System Status 3 June Sam Burke UCSB HEP Group

2 Slide 2UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE Progress LabView 6.1 Installed on PC in HEP Lab CERN Hybrid Test Code loaded à Binary files runs ok à Source file generates IEEE488 errors Air Manifold Designed à Pelton wheel sensor ordered (40-200 mL/min) 5v à Solenoid valve ordered 120vac à Flowmeter ordered (0.4-5.0 L/min) adjustable

3 Slide 3UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE Progress Water Manafold Design à Manual flow meter ordered (4-40 G/hr) Adjustable à Solenoid valve ordered 120vac à Pelton wheel flow sensor ordered (0.1-2.0 L/min) 5v System Interconnect Design Work Solid state relays purchased for valve controller à Optical isolation 5v control 120 vac load

4 Slide 4UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE Current Needs Plumb for chilled water loop in clean room à 400 watts @ 1L/min Plumb dry air to test system in clean room à Purge rate @ 3 L/min à Normal rate @ 0.3 L/min NIM Crate (pulse gen, nim-ttl-nim, nim or)

5 Slide 5UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE Future Plans Complete Tests on Coolie Box à trouble shoot bad relay control board à install new power transformer à wire up new high current connectors Create drawing for Air/Water Manafold à Shop to fab into 19” rack enclosure

6 Slide 6UCSB CMS Weekly Status MeetingCMS 4-Hybrid Test System Sam Burke EE Hybrid Test Chamber Heat Transfer Calculation à Q=mcΔT à Q= heat = P*t=400 watts*Time = 400 J/s*1 s à m=mass of water = 1.0 L/min*σ /60 s/min –= 1/60£*1000cc/£*1g/cc=16 g à c=Specific Heat of water = 4190 J/kgK à ΔT=[Tout-Tin] deg C à ΔT=Q/mc=400J/(4190J/kgK*.016kg)=5.9 deg C rise


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