Download presentation
Presentation is loading. Please wait.
1
King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 35
2
Objective Moment of Inertia of a body Parallel Axis Theorem Radius of Gyration Moment of Inertia of Composite Bodies
5
Parallel Axis Theorem The moment of inertia about any axis parallel to and at distance d away from the axis that passes through the centre of mass is: Where –I G = moment of inertia for mass centre G –m = mass of the body –d = perpendicular distance between the parallel axes.
6
Radius of Gyration
7
Mass Center Example
8
Objectives Apply the Equation of Translation motion –Rectilinear Translation –Curvilinear Translation Apply the equation of Rotation motion The roll of the center of mass G Discuss the slipping Vs. Tipping Discuss the slipping Vs. freely rotating Discuss the “wheely” Vs. Non-wheely
9
General Application of the Equations of Motion Summation of moment in FBD = summation of the kinetic moment in K.D
10
Rectilinear Translation
11
Curvilinear Translation
12
Discuss the slipping Vs. Tipping x N If x > 1.5 ft tipping If x < 1.5 ft slipping
13
Slipping Vs. Freely rotating FA=sNAFA=sNA NANA NBNB mg
14
“Wheely” Vs. Non-Wheely N B =0 Wheely : lift the front wheel off the ground
15
Example 17-5
16
Example 17-8 m BD =100kg m AB =m CD = Neglect = 30 o = 6 rad/s T A = ? T B = ? a G =?
17
Problem 17-43 m= 80 kg B =0.8 N A =? N B =? When rear wheel locks for break a =? Deceleration NANA NBNB BNBBNB aGaG
18
Problem 17-43 m= 80 kg B =0.8 N A =? N B =? a =? When traveling at constant velocity and no break was applied NANA NBNB BNBBNB a = 0
19
Problem 17-44 m= 80 kg N A =? N B =? a =? k =? minimum When rider applies the front break and back wheel start to lift off the ground NANA N B =0 kNAkNA
20
Rotation About a Fixed Axis
22
Pin Reaction Horizontal Reaction Vertical Reaction OR Normal Reaction Tangential Reaction OtOt OnOn OyOy OxOx OnOn OtOt
23
Example 17-9 Start from rest =? Number =20rad/s Pine reaction
24
Example 17-10
25
Example 17-11 m=60 kg Radius of gyration k O =0.25 m b =20 kg =? Drum a=?
26
Example 17-12 W=50 Ib k G =0.6 ft = 8 rad/s Pin reaction =?
27
Frictional Rolling Problems - rolls without slipping - slides as it rolls
28
Example 17-14 m = 8 Kg radius of gyration k G =0.3m. =?.
29
W= 50-lb radius of gyration k G =0.70ft. a G =?. Example 17-15
30
Example 17-16 m=100 kg I G =75 kg.m 2 =? The pole at rest
31
Example 17-17
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.