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King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 35.

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Presentation on theme: "King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 35."— Presentation transcript:

1 King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 35

2 Objective Moment of Inertia of a body Parallel Axis Theorem Radius of Gyration Moment of Inertia of Composite Bodies

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5 Parallel Axis Theorem The moment of inertia about any axis parallel to and at distance d away from the axis that passes through the centre of mass is: Where –I G = moment of inertia for mass centre G –m = mass of the body –d = perpendicular distance between the parallel axes.

6 Radius of Gyration

7 Mass Center Example

8 Objectives Apply the Equation of Translation motion –Rectilinear Translation –Curvilinear Translation Apply the equation of Rotation motion The roll of the center of mass G Discuss the slipping Vs. Tipping Discuss the slipping Vs. freely rotating Discuss the “wheely” Vs. Non-wheely

9 General Application of the Equations of Motion Summation of moment in FBD = summation of the kinetic moment in K.D

10 Rectilinear Translation

11 Curvilinear Translation

12 Discuss the slipping Vs. Tipping x N If x > 1.5 ft tipping If x < 1.5 ft slipping

13 Slipping Vs. Freely rotating FA=sNAFA=sNA NANA NBNB mg

14 “Wheely” Vs. Non-Wheely N B =0 Wheely : lift the front wheel off the ground

15 Example 17-5

16 Example 17-8 m BD =100kg m AB =m CD = Neglect  = 30 o  = 6 rad/s T A = ? T B = ? a G =?

17 Problem 17-43 m= 80 kg  B =0.8 N A =? N B =? When rear wheel locks for break a =? Deceleration NANA NBNB BNBBNB aGaG

18 Problem 17-43 m= 80 kg  B =0.8 N A =? N B =? a =? When traveling at constant velocity and no break was applied NANA NBNB BNBBNB a = 0

19 Problem 17-44 m= 80 kg N A =? N B =? a =?  k =? minimum When rider applies the front break and back wheel start to lift off the ground NANA N B =0 kNAkNA

20 Rotation About a Fixed Axis

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22 Pin Reaction Horizontal Reaction Vertical Reaction OR Normal Reaction Tangential Reaction OtOt OnOn OyOy OxOx OnOn OtOt

23 Example 17-9 Start from rest  =? Number  =20rad/s Pine reaction

24 Example 17-10

25 Example 17-11 m=60 kg Radius of gyration k O =0.25 m b =20 kg  =? Drum a=?

26 Example 17-12 W=50 Ib k G =0.6 ft  = 8 rad/s Pin reaction =?

27 Frictional Rolling Problems - rolls without slipping - slides as it rolls

28 Example 17-14 m = 8 Kg radius of gyration k G =0.3m.  =?.

29 W= 50-lb radius of gyration k G =0.70ft. a G =?. Example 17-15

30 Example 17-16 m=100 kg I G =75 kg.m 2  =? The pole at rest

31 Example 17-17


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