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1 III. Nuclear Reaction Rates Nuclear reactions generate energy create new isotopes and elements Notation for stellar rates: p 12 C 13 N 12 C(p, ) 13 N The heavier “target” nucleus (Lab: target) the lighter “incoming projectile” (Lab: beam) the lighter “outgoing particle” (Lab: residual of beam) the heavier “residual” nucleus (Lab: residual of target) (adapted from traditional laboratory experiments with a target and a beam)
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2 Example for a sequence of reactions in stars: the CN cycle 3456789 neutron number C(6) N(7) O(8) F(9) Ne(10) 12 C(p, ) 13 N ( + ) 13 C (p, ) 14 N (p, ) 15 O( + ) 15 N (p, ) 12 C Net effect: 4p -> + 2e + + 2v e But requires C or N as catalysts (second and later generation star) Need reaction rates to: establish existence of cycle determine total rate of cycle
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3 Sun pp reaction chain:
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4 The 4 CNO cycles
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5 Competition between the p-p chain and the CNO Cycle To understand this (and else):
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6 1. cross section bombard target nuclei with projectiles: relative velocity v Definition of cross section: # of reactions = . # of incoming projectiles per second and target nucleus per second and cm 2 or in symbols: = j with j as particle number current density. Of course j = n v with particle number density n) Units for cross section: 1 barn = 10 -24 cm 2 ( = 100 fm 2 or about half the size (cross sectional area) of a uranium nucleus)
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7 2. Reaction rate in the laboratory beam of particles hits target at rest thickness d area A j,v assume thin target (unattenuated beam intensity throughout target) Reaction rate (per target nucleus): Total reaction rate (reactions per second) with n T : number density of target nuclei I =jA : beam number current (number of particles per second hitting the target) note: dn T is number of target nuclei per cm 2. Often the target thickness is specified in these terms.
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8 3. Reaction rate in stellar environment Mix of (fully ionized) projectiles and target nuclei at a temperature T 3.1. For a given relative velocity v in volume V with projectile number density n p reaction rate per second and cm 3 so for reaction rate per second and cm 3 : This is proportional to the number of p-T pairs in the volume. If projectile and target are identical, one has to divide by 2 to avoid double counting
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9 3.2. at temperature T Maxwell-Bolzmann for most practical applications (for example in stars) projectile and target nuclei are always in thermal equilibrium and follow a Maxwell-Bolzmann velocity distribution: then the probability (v) to find a particle with a velocity between v and v+dv is with example: in terms of energy E=1/2 m v 2 max at E=kT
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10 Temperature in Stars The horizontal axis is the velocity in cm/sec and the vertical axis is proportional to the probability that a particle in the gas has that velocity.
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11 Boltzmann distribution Boltzmann distribution = probability that any one molecule will be found with energy E: distributionof velocity If this distribution is applied to one direction of velocity for a molecule in an ideal gas, it becomes probability inin three dimensions: Converting this relationship to probability in terms of speed in three dimensions: Maxwell-Boltzmann distribution
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12 Details of calculation:
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13 relative one can show (Clayton Pg 294-295) that the relative velocities between two particles are distributed the same way: reduced mass with the mass m replaced by the reduced mass of the 2 particle system the stellar reaction rates has to be averaged over the distribution (v) or short hand: typical strong velocity dependence! typical strong velocity dependence !
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14 expressed in terms abundances reactions per s and cm 3 reactions per s and target nucleus stellar reaction rate this is usually referred to as the stellar reaction rate of a specific reaction units of stellar reaction rate N A : usually cm 3 /s/mole, though in fact cm 3 /s/g would be better (and is needed to verify dimensions of equations)
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15 4. Abundance changes, lifetimes Lets assume the only reaction that involves nuclei A and B is destruction (production) of A (B) by A capturing the projectile a: A + a -> B random process same laws as radioactive decay: Again the reaction is a random process with const probability (as long as the conditions are unchanged) and therefore governed by the same laws as radioactive decay: consequently:
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16 Example: AB and of course same abundance level Y 0A time abundance after some time, nucleus A is entirely converted to nucleus B Lifetime of A (against destruction via the reaction A+a) : (of course half-life of A T 1/2 =ln2/ Y 0A Y 0A /e
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17 5. Energy generation through a specific reaction: Again, consider the reaction A+a->B Reaction Q-value: Reaction Q-value: Energy generated (if >0) by a single reaction in general, for any reaction (sequence) with nuclear masses m: Energy generation Energy generated per g and second by a reaction: 6. Reaction flow: abundance of nuclei converted in time T from species A to B via a specific reaction
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18 7. Multiple reactions destroying a nuclide example: in the CNO cycle, 13 N can either capture a proton or decay. each destructive reaction i has a rate i the total destruction rate for the nucleus is then its total lifetime 7.1. Total lifetime 7.2. Branching the reaction flow branching into reaction i, b i is the fraction of destructive flow through reaction i. (or the fraction of nuclei destroyed via reaction i) 13 N 14 O 13 C (p, ) (+)(+)
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19 8. Determining nuclear reaction rates - Introduction cross section Needed is the cross section as a function of energy (velocity) The stellar reaction rate can then be calculated by integrating over the Maxwell Boltzmann distribution. The cross section depends sensitively on the reaction mechanism and the properties of the nuclei involved. It can vary by many (tens) orders of magnitude Both are difficult. It can either be measured experimentally or calculated. Both are difficult. Experiments are complicated by extremely small cross sections that prevent direct measurements of the cross sections at the relevant astrophysical energies (with a some exceptions) no nuclear theory accurately enough. There is no nuclear theory that can predict the relevant properties of nuclei accurately enough. In practice, a combination of experiments and theory is needed. Typical energies for astrophysical reactions are of the order of kT Sun Sun T ~ 10 Mio K Si burning Si burning in a massive star: T ~ 1 Bio K
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20 Nuclear properties that are relevant for reaction rates: Excitation energy ground state 0 Nucleons in the nucleus can only have discrete energies. Therefore, the nucleus as a whole can be excited into discrete energy levels (excited states) 1st excited state 2nd excited state 3rd excited state 0 2.13 4.45 5.03 3/2 1/2 5/2 3/2 Excitation energy (MeV) Spin Parity (+ or - )
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21 Each state is characterized by: energy energy (mass) spin parity lifetimes lifetimes against ,p,n, and emission lifetime The lifetime is usually given as a width as it corresponds to a width in the excitation energy of the state according to Heisenberg: therefore, a lifetime corresponds to a width : partial widths the lifetime against the individual “channels” for ,p,n, and emission are usually given as partial widths p n and with
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22 A Real Example
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23 Basic reaction mechanisms involving strong or electromagnetic interaction: Direct reactions I. Direct reactions (for example, direct capture) Example: neutron capture A + n -> B + A+n B EnEn SnSn direct transition into bound states Resonant reactions II. Resonant reactions (for example, resonant capture) A+n B EnEn SnSn Step 1: Coumpound nucleus formation (in an unbound state) B Step 2: Coumpound nucleus decay
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24 or a resonant A(n, )B reaction: B+ C EnEn SS Step 1: Compound nucleus formation (in an unbound state) B Step 2: Compound nucleus decay C A+n SnSn For resonant reactions, E n has to “match” an excited state (but all excited states have a width and there is always some cross section through tails) But enhanced cross section for E n ~ E x - S n more later …
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