1. SAT Multiple Choice Question(s)
For the two intersecting lines above, which of the following must be true? I.
II.
III.
I only
II only
I and II only
II and III only
I, II, and III

2. SAT Multiple Choice Question(s)
For the two intersecting lines above, which of the following must be true? I.
II.
III.
I only
II only
I and II only
II and III only
I, II, and III

3. 1. Center: (1,2) vertices: (4,2),(-2,2),(1,4),(1,0)
Answers to HW:
1. Center: (1,2) vertices: (4,2),(-2,2),(1,4),(1,0)
foci: (3.2, 2),(-1.2, 2)
2. Center: (-3,2) vertices: (-7,2),(1,2),(-3,7),(-3,-3)
foci: (-3,-1),(-3,5)
3. Standard Form: (x-5)2/48 + (y-5)2/64 = 1
Center: (5,5) foci: (5,9),(5,1)
vertices: (5,13),(5,-3),(-1.9, 5),(11.9, 5)
4. Standard Form: (x+2)2/64 + (y-1)2/48 = 1
Center: (-2,1) foci: (-6,1),(2,1)
vertices: (-10,1),(6,1),(-2, 7.9),(-2, -5.9)

4. Center: (5, -2) foci: (3.6, -2),(6.4, -2)
Answers to HW (Cont):
5.Standard Form:
Center: (5, -2) foci: (3.6, -2),(6.4, -2)
vertices: (3, -2),(7, -2),(5, -.6),(5, -3.4)
4. Standard Form:
Center: (2, -1) foci: (-.2, -1),(4.2, -1)
vertices: (5,-1),(-1,-1),(2, 1),(2, -3)

5. Unit Question: How do I recognize, write and graph equations of conic sections?
How do I write equations of parabolas and graph all of its pieces and parts?

6. PARABOLAS Standard form
(the distance from the sides of the parabola through the focus)

7. Latus
focus
vertex
directrix

8. Parabolas 2 h=0 k=0 p = 1) x2 – 8y = 0 x is squared x2 = 8y 4p = 8
Vertex: (h,k)
(0, 0)
opens up
Parabolas
Axis of symmetry:
Focus: (h, k+p)
(0, 2)
Directrix: y = k – p
y = -2
Latus:

10. GRAPH x2 = 8y focus: (0, 2 di vertex: (0, 0) rectrix: y = - axis up )
8 units across

11. Graph. k = 2 (x – 1)2 = -4(y – 2) h = 1 p =? -4 = 4p (1, 2) focus:
vertical, down k
= 2
(x – 1)2 = -4(y – 2)
h = 1
p =?
vertex:
-4 = 4p
(1, 2)
focus:
= (1, 1)
p = -1
directrix:
y = 3
latus:

12. Graph.
(x – 1)2 = -4(y – 2)

14. Graph. horizontal, right (y + 2)2 = 8(x – 3) h = 3 k = -2 p =? 8 = 4p
vertex:
(3, -2)
2 = p
focus:
= (5, -2)
directrix:
x = 1
latus:

16. Graph. (y + 2)2 = 8(x – 3) vertex: (3, -2) directrix: x = 1 latus: 8
focus: (5, -2)
semi latus: 4

17. Graph. (x + 1)2 = 12(y + 1) h = -1 k = -1 p =? 12 = 4p (-1, -1) 3 = p
vertical, up
h = -1 k
= -1
p =?
12 = 4p
vertex:
(-1, -1)
3 = p
focus:
= (-1, 2)
directrix:
y = -4
axis:
x = -1
latus:
semi latus: 6

18. Graph. (x + 1)2 = 12(y + 1) vertex: (-1, -1) directrix: y = -4
latus: 12
focus: (-1, 2)
axis: x = -1
semi latus: 6

19. Put in standard form 36 36

20. Find the equation of the parabola with focus (2,3) and directrix x=7.
(y – 3)2 = -2(x – 4.5)