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Taylor Walsh Shiv Patel Emily Penn Philip Adejumo Chapter 17-4.

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Presentation on theme: "Taylor Walsh Shiv Patel Emily Penn Philip Adejumo Chapter 17-4."— Presentation transcript:

1 Taylor Walsh Shiv Patel Emily Penn Philip Adejumo Chapter 17-4

2  Be able to read a titration curve  Understand how titrations work  Perform titration calculations

3  Equivalence point- the point at which stoichiometrically equivalent quantities of acids and bases have been brought together http://www.chemguide.co.uk/physical/ac idbaseeqia/phcurves.html

4  Titration- when a solution containing a known concentration of base is slowly added to an acid (or vice versa)  Titration enables us to find the equivalence point of the acid-base solution http://www.dartmouth.edu/~chemla b/techniques/graphics/titration/titr ation6.gif

5  A titration curve is a graph of the pH as a function of the volume of the added acid or base  There are 3 types of titrations with distinct titration curves:  Strong acid-strong base  Weak acid-strong base  Polyprotic acid-strong base

6 Equivalence Point Rapid Rise Portion Initial pH Final pH http://www.files.chem.vt.edu/chem- ed/titration/graphics/titration-strong-acid-35ml.gif

7 1. The initial pH a. The initial pH is a purely acidic solution 2. Between the initial pH and the equivalence point  pH slowly rises at first, then more Rapidly when it gets close to the Equivalence point 3. The equivalence point 4. After the equivalence point Ex..100 M NaOH added to 50.0 mL of.100 M HCl 1 2 3 4 http://0.tqn.com/d/chemistry/1/0/f/g/s atitration.JPG

8 1. First determine how many moles of H + were originally present and how many moles of OH - were added 2. Subtract the two values (moles) to calculate moles of H + There are more moles of H + than moles of OH -, so the resulting value will be moles of H + Ex. Calculate the pH when the following quantities of 0.100 M NaOH solution have been added to 50.0 mL of 0.100 M HCl solution

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10 1. The initial pH  pH of the acid 2. Between the initial pH and the Equivalence point 3. The equivalence point 4. After the equivalence point 1 2 3 4

11  The solution of the weak acid has a higher initial pH than a solution of a strong acid of the same concentration  The pH change at the rapid-rise portion of the curve is smaller for the weak acid than it is for the strong acid  The pH at the equivalence point is above 7.00 for the weak acid-strong base titration  Equivalence point for strong acid-strong base is always at 7.00 pH

12  Calculate [HX] and [X - ] after reaction  Use [HX], [X - ], and K a to calculate  Use [H + ] to calculate pH Ex: Calculate the pH of the solution formed when 45.0 mL of 0.100 M NaOH is added to 50.0 mL of 0.100 M HC2H3O2, (Ka = 1.8 x 10 -5 )

13 Before rxn0.0 mol HC 2 H 3 O 2 (aq) + OH - C 2 H 3 O 2 - (aq) After rxn0.0 mol

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15  Calculate the pH at the equivalence point in the titration of 50.0 mL of 0.100 M HC2H3O2 with 0.100 M NaOH

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17 Calculate the pH at the equivalence point in the titration of 50.0 mL of 0.100 M HC2H3O2 with 0.100 M NaOH

18  When weak acids contain more than one ionizable H atom (H 3 PO 3 )  Neutralization occurs in a series of steps H 3 PO 3 H 2 PO 3 - HPO 3 -2 http://www.files.chem.vt.edu/RVGS/APChem/lab/Exp eriments/images/titration_curve.jpg


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