1. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
Simplify:
Note: In the final answer terms should be in alphabetical order.
1. 4x – y – 13x – (− 12)
− 9x – y – (− 12)
− 9x – y
− 9x + 5y + 1
− 9x + 5y + 1
© by S-Squared, Inc. All Rights Reserved.

2. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
Simplify:
Note: In the final answer the terms should be in alphabetical order.
2. − 5(2x – y)
− 10x
+ 30
– 40y
− 10x – 40y
− 10x – 40y
Note: The constant term always goes last.

3. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
Simplify:
Note: Apply the order of operations.
3. − – (− 3)
− ÷ 9
− – (− 3)
− 53 – (− 3)
− ÷ 9
− ÷ 9 −
− 50
− ÷ 9
− ÷ 9
− 50
− 50 = 10 −
− 5

4. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
4. Evaluate: m4 + mn + n2 ; for m = − 3
n = − 1
Note: Apply the order of operations.
Substitute
2(− 3)4 + (− 3)(− 1) + (− 1)2
Exponent
2(81) + (− 3)(− 1) + 1
Multiply
(− 3)(− 1) + 1
Multiply
Add
Add
166

5. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
5. Solve: (m – 2) = − 28
Distribute 7m
– 14
= − 28
Add
+ 14
+ 14
7m = − 14
Divide 7 7
m = − 2

6. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
6. Solve: p – (− 4p) = 24
Combine
p = 24
Subtract
– 6
– 6
6p = 18
Divide 6 6
p = 3

7. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
7. Solve: – (3 – 4a) = 2a – 11
Distribute 8
– 3
+ 4a
= 2a – 11
Combine
a = 2a – 11
Subtract
– 2a
– 2a
a = − 11
Subtract
– 5
– 5
2a = − 16
Divide 2 2
a = − 8

8. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
8. Solve: (f – 3) = − 4(1 – 2f)
Distribute
7f – 21 = − f
Subtract
– 8f
– 8f
− f – 21 = − 4
Add
+ 21
+ 21
− f = 17
Divide
− 1
− 1
f =
− 17

9. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
9. Solve the proportion using the cross-product property:
j + 8 j =
Apply cross product property 15 3 3
(j + 8) = 15
• j
Distribute 3j =
15j
Subtract
– 3j
– 3j 24 =
12j
Divide 12 12 2 = j j = 2

10. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
10. Solve: │4x – 1│ = 7
*The absolute value of a number is the distance it is away
from zero. Two numbers have a distance from zero of 7.
Note: Write the two related equations.
Add
4x – 1 = 7
And x – 1 = − 7
Add
+ 1
+ 1
+ 1
+ 1
Divide
4x = 8
4x = − 6
Divide 4 4 4 4
x = 2
− 6
x =
Reduce 4
− 3
x = 2 and x =
− 3
x = 2 2

11. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
11. How many terms are in the variable expression?
3a – 14ab + 8b – c + 4d
5 terms
12. Simplify:
a) │ − 4 │ 4
* The absolute value of a number is the distance
it is away from zero.
b) − │12│
− 12

12. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
13. Write the numbers in increasing order.
− 1.3
− 1.3, 2,
, 2, 3 1 3 1
, 0, , 2.1
, 0, 5 2 2 5
2.1,
14. Use an inequality symbol to complete the following statement.
<
a) − 2.3 _______ − 4
<
b) _______ 1.4 4 3

13. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
15. Write the inequality for the given graph. 1 2 3 4 5 6 −6 −5 −4 −3 −2 −1 x
x > − 3

14. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
16. a) Solve: p – 7 > − 8 4
+ 7
+ 7
Add
p > − 1
4 •
• 4
Multiply 4
p > − 4
16. b) Graph: 1 2 3 4 5 6 −6 −5 −4 −3 −2 −1

15. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
17. a) Solve the compound inequality:
2x ≤ − 1
Or x – 3 ≥ 21
2x ≤ − 1
Subtract
6x – 3 ≥ 21
Add
− 1
− 1
+ 3
+ 3
2x ≤ − 2
6x ≥ 24
Divide
Divide 2 2 6 6
x ≤ − 1
x ≥ 4 Or
17. b) Graph: 1 2 3 4 5 6 −6 −5 −4 −3 −2 −1

16. Algebra I Concept Test # 2 – Equations, Inequalities and A.V.
Practice Test
18. a) Solve the compound inequality:
Studying is a sign of respect for yourself
− 24 ≤ − 5x ≤ 16
Note: Isolate x in the middle of the inequalities.
− 24 ≤ − 5x ≤ 16
Subtract
− 1
− 1
− 1
− 25 ≤ − 5x ≤ 15
Divide
− 5
− 5
− 5
Note: Change direction of inequality when dividing by a negative number.
5 ≥ x ≥ − 3
− 3 ≤ x ≤ 5
18. b) Graph: 1 2 3 4 5 6 −6 −5 −4 −3 −2 −1