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Published byAlisha Eaton Modified over 9 years ago
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m -m Signal Phasor: Noise Phasor: s(t)s(t) Phase Deviation due to noise: n (t) Noise Performance for Phase Modulation For sinusoidal modulation, let a(t) = sin( m t) Then s (t) = m[sin( m t)] Coherent Phase Detector k p s (t) + n (t) v out k p s (t) + k p n (t) Signal Noise hmmm… RMS Noise Radius
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The Noise Phasor Random Amplitudes When n is “small”
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FM/PM SNR Improvement 20 log(m) SNR(in) SNR(out) 10 dB Power SNR to noise ratio is equal to voltage SNR 2, so Power SNR improvement ratio is equal to m 2. Since occupied bandwidth increases in proportion to m, so does kTB noise power, so overall system power SNR improvement ratio is just m.
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Pre-emphasis/De-Emphasis V m (t) Phase Demodulator Differentiator Low Pass Filter v PM (t) v FM (t) v D (t) The RMS noise amplitude is independent of frequency, therefore its demodulated spectrum is flat. Let the noise voltage at some frequency n be: The output of the differentiator will be: The noise amplitude for FM is proportional to frequency: The noise spectrum exiting the low pass filter will be: The Low Pass Filter De-emphasizes the high frequency content, resulting in a flat noise spectrum above c.
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Pre-emphasis In order to reproduce the source spectrum accurately, the source information must have its high frequencies “pre-emphasized “ by a pre-emphasis filter having time constant equal to 1/ c. The filter flattens out at some frequency h, above the normal audio range. 20 log(m) cc hh For fixed deviation FM, m = / m, so modulation index decreases as m increases. Pre-emphasis increases the deviation for high frequencies to keep m fairly constant above c. Pre-emphasis/de-emphasis filters are characterized by = 1/ c
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