Presentation is loading. Please wait.

Presentation is loading. Please wait.

Statistics for Managers Using Microsoft® Excel 7th Edition

Similar presentations


Presentation on theme: "Statistics for Managers Using Microsoft® Excel 7th Edition"— Presentation transcript:

1 Statistics for Managers Using Microsoft® Excel 7th Edition
Chapter 8 Confidence Interval Estimation Statistics for Managers Using Microsoft Excel, 7e © 2014 Pearson Prentice-Hall, Inc Philip A. Vaccaro , PhD

2 Learning Objectives In this chapter, you will learn:
To construct and interpret confidence interval estimates for the population mean and the population proportion ( μ and π ) . How to determine the sample size necessary to develop a confidence interval for the population mean or population proportion How to use confidence interval estimates in auditing (optional ) .

3 Confidence Interval Estimate
I am 95% confident that the true average income of U.S. appliance factory workers is between $51, and $56,000.00 per year. I am 90% confident that the true proportion of potential voters supporting candidate “B” is between 35% and 38%. EXAMPLES

4 Chapter Outline Confidence Intervals for the Population Mean, μ
when Population Standard Deviation σ is known when Population Standard Deviation σ is unknown Confidence Intervals for the Population Proportion, π Determining the Required Sample Size, n

5 developing the confidence
Point Estimates The starting point for developing the confidence interval for μ or π The value of a single sample statistic: mean or proportion A point estimate is a single number. For the population mean and population standard deviation, a point estimate is the sample mean and sample standard deviation. A confidence interval provides additional information about variability A range of numbers constructed around the point estimate Lower Confidence Limit Upper Confidence Limit Point Estimate Width of confidence interval

6 Confidence Interval Estimates
A confidence interval gives a range estimate of values: Takes into consideration variation in sample statistics from sample to sample Based on all the observations from one sample Gives information about closeness to unknown population parameters Stated in terms of level of confidence Example: 95% confidence, 99% confidence Can never be 100% confident * * Recall that the sample mean will vary from sample to sample

7 Confidence Interval Estimates
The general formula for all confidence intervals is: σ / √ n or s / √ n Sample Mean or Sample Proportion The “z” or “t” Critical Value Point Estimate ± (Critical Value) (Standard Error)

8 Confidence Level Confidence Level
A confidence interval estimate of 100% would be so wide as to be meaningless for practical decision making Confidence Level Confidence in which the interval will contain the unknown population parameter ( μ or π ) A percentage ( less than 100% )

9 Confidence Level Suppose confidence level = 95%
Also written (1 - ) = .95 A relative frequency interpretation: In the long run, 95% of all the confidence intervals that could be constructed will contain the unknown true parameter ( μ , π ) A specific interval either will contain or will not contain the true parameter

10 The Level of Significance (α)
Because we only select one sample, and μ or π are unknown, we never really know whether the confidence interval includes the true population mean or proportion, or not. The level of significance, or “α” risk is the chance we take that the true population parameter is not contained in the confidence interval. Therefore, a 95% confidence interval would have an “α” of 5%

11 The Level of Significance (α)
If α = .05, then each tail has .025 area The critical values of “z” that define the “α” areas are and 95% Confidence Interval z z a = .025 a = .025 .0250 Point Estimate .9750 Z .06 - 1.9 .0250 Z .06 + 1.9 .9750 “ α “ is the proportion in the tails of the sampling distribution that is outside the established confidence interval.

12 distribution corresponds
The ‘z’ Table .0250 of the area under the standardized normal distribution corresponds to z .

13 distribution corresponds
The ‘z’ Table .9750 of the area under the standardized normal distribution corresponds to z .

14 Confidence Interval for μ ( when σ is Known )
Assumptions Population standard deviation σ is known Population is normally distributed If population is not normal, use large sample ( n > 30 ) Confidence interval estimate: (where Z is the standardized normal distribution critical value for a probability of α/2 in each tail)

15 Finding the Critical Value, Z
Consider a 95% confidence interval: The value of ‘z’ is needed for constructing the confidence interval z z Z= -1.96 Z= 1.96 Z units: Lower Confidence Limit Upper Confidence Limit X units: Point Estimate

16 Finding the Critical Value, Z
Consider a 99% confidence interval: The value of ‘z’ is needed for constructing the confidence interval 1 - α = .99 Z .08 + 2.5 .9951 Z .08 - 2.5 .0049 .005 .005 z z Z units: Z= Z= X units: Lower Confidence Limit Upper Confidence Limit Point Estimate

17 Finding the Critical Value, Z
Confidence Level Confidence Coefficient ‘z’ Value ‘a’ / 2 Value 80% .80 1.28 .1000 90% .90 1.645 .0500 95% .95 1.96 .0250 98% .98 2.33 .0100 99% .99 2.58 .0050 99.8% .998 3.08 .0010 99.9% .999 3.27 .0005 Commonly used confidence levels are 90%, 95%, and 99%

18 Intervals and Level of Confidence
Means vary from sample to sample Accordingly, confidence intervals of the same percentage will have different lower and upper limits The true population mean may not be in them at all ! Sampling Distribution of the Mean x Intervals extend from to x1 ( 1- ) x 100% of intervals constructed contain μ; (  ) x 100% do not. x2 Confidence Intervals

19 Confidence Interval for μ ( σ Known ) Example
A sample of 11 circuits from a large normal population has a mean resistance of 2.20 ohms. We know from past testing that the population standard deviation is .35 ohms. Determine a 95% confidence interval for the true mean resistance of the population.

20 Confidence Interval for μ ( σ Known ) Example
Detailed Computations / (.35 / ) / (.10553) / = = We are 95% confident that the true mean resistance is between and ohms Although the true mean may or may not be in this interval, 95% of intervals formed in this manner will contain the true mean

21 Confidence Interval for μ ( σ Unknown )
If the population standard deviation σ is unknown, we can substitute the sample standard deviation: (s) . This introduces extra uncertainty, since ‘s’ is variable from sample to sample So we use the ‘t’ distribution instead of the normal distribution “S” is variable from sample to sample, and even more so, in very small samples

22 Confidence Interval for μ ( σ Unknown )
Actually, we rarely know the true population standard deviation. We must instead develop a confidence interval using the sample standard deviation Assumptions Population standard deviation is unknown Population is normally distributed If population is not normal, use large sample ( n > 30 ) Use Student’s ‘t’ Distribution The Confidence Interval Estimate: (where t is the critical value of the t distribution with ‘n-1’ degrees of freedom and an area of α/2 in each tail) Sample Standard Deviation Degrees of Freedom

23 Student ‘ t ‘ Distribution
it is bell-shaped has fatter tails has flatter center ( peak or “kurtosis” ) the sampling distributions of small samples follow the ‘t ’ distribution the smaller the sample size taken, the more variable the ‘t ’ distribution

24 Student’s ‘ t ‘ Distribution
d.f. = n - 1 Sample size The ‘ t ’ value depends on degrees of freedom ( d.f. ) The number of observations in the sample that are free to vary after the sample mean has been calculated. The ‘ t ’ distribution changes as the number of degrees of freedom changes. small samples have greater variability and the ‘ t ’ reflects that variability when we are finding areas under the sam- pling distribution curve.

25 Student’s t Distribution
Peaks rise as d..f. increase df = 1 df = 2 df = 5 df =10 df = ∞ William S. Gosset of the Guiness Brewery who published under the pen name “student” (1913) Tails flatten as d.f. increase

26 Degrees of Freedom Concept: The number of observations that are free to vary after the sample mean has been calculated Example: Suppose the mean of 3 numbers is 8.0 Let X1 = 7 Let X2 = 8 What is X3? If the mean of these three values is 8.0, then X3 must be 9 (i.e., X3 is not free to vary) 2 values can be any numbers, that is, free to vary, but the third is not free to vary for a given mean

27 Student’s t Distribution
Note: ‘t’ approaches ‘Z’ as ‘n’ increases As n and d.f. increase, ‘s’ becomes a better estimate of the population standard deviation, and the sampling distribution eventually becomes the standardized normal distribution when n = 120 ! Standard Normal (t with df = ∞) t (df = 13) t-distributions are bell-shaped and symmetric, but have ‘fatter’ tails than the normal t (df = 5) t

28 The body of the table contains t values, not probabilities !
Student’s t Table It’s set up for the upper tail area only ! Upper Tail Area Let: n = df = n - 1 =  = /2 =.05 For 90% Confidence Interval df .25 .10 .05 1 1.000 3.078 6.314 2 0.817 1.886 2.920 /2 = .05 3 0.765 1.638 2.353 90% Confidence The body of the table contains t values, not probabilities ! t 2.920 ( INFERRED )

29 Confidence Interval for μ (σ Unknown) Example
_ A random sample of n = 25 has X = 50 and S = 8. Form a 95% confidence interval for μ d.f. = n – 1 = 24, so The confidence interval is Detailed Calculations 50 + / - (2.0639)( 8/5) 50 + / - (2.0639)(1.6) 50 + / = = ( , ) d.f. α = .025 24 2.0639

30 Confidence Intervals for the Population Proportion, π
An confidence interval estimate for the population proportion ( π ) can be calculated. p p p ‘p’ is the sample proportion Recall, that if np => 5 and if n ( 1 - p ) => 5, that is, if the sample size is large enough, we can approximate the proportion’s binomial distribution with a normally distributed sampling distribution.

31 Confidence Intervals for the Population Proportion, π
Again, recall that the distribution of the sample proportion is approximately normal if the sample size is large, with standard deviation: We will estimate this with sample data: Estimated σp ( ‘p’ is the sample proportion )

32 Confidence Intervals for the Population Proportion, π
Upper and lower confidence limits for the population proportion are calculated with the formula: where Z is the standardized normal value for the level of confidence desired p is the sample proportion n is the sample size Alternately, p +/- Z ( estimated σp )

33 Confidence Intervals for the Population Proportion: Example
A random sample of 100 people shows that 25 have opened IRA’s this year. Form a 95% confidence interval for the true proportion of the population who have opened IRA’s. Detailed Computations .25 +/ √ / 100 .25 +/ √ .25 +/ (.0433) .25 +/ = .3349 = .1651 alternately, =< π =< .3349

34 Confidence Intervals for the Population Proportion: Example
We are 95% confident that the true percentage of IRA openers in the population is between 16.51% and 33.49%. Although the interval from to may or may not contain the true proportion, 95% of intervals formed from samples of size 100 in this manner will contain the true proportion.

35 Determining Sample Size
The required sample size can be found to reach a desired margin of error (e) with a specified level of confidence (1 - ) The margin of error is also called sampling error or tolerated or allowable error. the amount of imprecision in the estimate of the population parameter the amount added and subtracted to the point estimate to form the confidence interval We can determine sample size for the mean and the proportion

36 Determining Sample Size
To determine the required sample size for the mean, you must know: The desired level of confidence (1 - ), which determines the critical ‘Z’ value The acceptable sampling error (margin of error), ‘e’ The standard deviation, ‘σ’ Now solve for n to get

37 Determining Sample Size
If  = 45, what sample size is needed to estimate the mean within ± 5 with 90% confidence? interpolated Z value So the required sample size is n = 220 We always round up to the meet or exceed the requirements for the confidence interval and the margin of error.

38 Determining Sample Size
( ) ( 2025 ) n = 25 n = = 25 Detailed Computations

39 There is no ‘z’ value for ‘.9500’ We need to interpolate:
The ‘z’ Table There is no ‘z’ value for ‘.9500’ in the table. We need to interpolate: Z .04 1.6 .9495 Z .05 1.6 .9505 Z becomes 1.645

40 Finding the Critical Value, Z
Consider a 90% confidence interval: The value of ‘z’ is needed for constructing the confidence interval 1 - α = .90 Z .05 + 1.6 .9505 Z .04 + 1.6 .9495 .05 .05 z z Z= Z= Z units: Lower Confidence Limit Upper Confidence Limit X units: Point Estimate

41 Determining Sample Size
If unknown, σ can be estimated when using the required sample size formula : Use a value for σ that is expected to be at least as large as the true σ Select a pilot sample and estimate σ with the sample standard deviation, s Also consider Rg ( data range ) divided by ‘6’

42 Determining Sample Size for the Proportion
To determine the required sample size for the proportion, you must know 3 factors: The desired level of confidence (1 - ), which determines the critical Z value The acceptable sampling error (margin of error), e The true proportion of “successes”, π π can be estimated with a pilot sample, if necessary (or conservatively use π = .50) Now solve for n to get

43 Determining Sample Size for the Proportion
Ironically, π is actually the population parameter that we are trying to estimate ! 1. Consider using an “educated” guess for π . 2. Consider using π = 0.50 which will generate the maximum sample size needed. 3. Be aware the the maximum sample size results in the highest sampling costs. 4. That said, there is then increased precision in estimating π, because the confidence interval is narrowed !

44 Determining Sample Size
How large a sample would be necessary to estimate the true proportion defective in a large population within ± 3%, with 95% confidence ? (Assume a pilot sample yields p = .12)

45 Determining Sample Size
Solution: For 95% confidence, use Z = 1.96 e = .03 p = .12, so use this to estimate π Z .06 + 1.9 .9750 Z .06 - 1.9 .0250 So use n = 451 Detailed Computations ( ) ( .12 ) ( .88 ) / = / = ≈ 451

46 Determining Sample Size
Solution: For 95% confidence, use Z = 1.96 e = .03 p = .50, if using this to estimate π (max ‘n’) Z .06 + 1.9 .9750 Z .06 - 1.9 .0250 (.50)( ) 1,067 Detailed Computations ( ) ( .50 ) ( .50 ) / = (3.8416) (.25) / = / = 1, ≈ 1,067 So use n = 1,067

47 Applications in Auditing
Six advantages of statistical sampling in auditing : Sample result is objective and defensible ( based on demonstrable statistical principles ) Provides sample size estimation in advance on an objective basis Provides an estimate of the sampling error

48 Applications in Auditing
Can provide more accurate conclusions on the population Examination of the population can be time consuming and subject to more nonsampling error Samples can be combined and evaluated by different auditors Samples are based on scientific approach Samples can be treated as if they have been done by a single auditor Objective evaluation of the results is possible Based on known sampling error

49 Population Total Amount
Point estimate: Confidence interval estimate: This is sampling without replacement, so use the finite population correction in the confidence interval formula

50 Population Total Amount
A firm has a population of 1000 accounts and wishes to estimate the total population value. A sample of 80 accounts is selected with average balance of $87.6 and standard deviation of $22.3. Find the 95% confidence interval estimate of the total balance.

51 Population Total Amount
The 95% confidence interval for the population total balance is $82, to $92,362.48

52 Confidence Interval for Total Difference
Point estimate: Where the mean difference is:

53 Confidence Interval for Total Difference
Confidence interval estimate: where:

54 One Sided Confidence Intervals
Application: find the upper bound for the proportion of items that do not conform with internal controls where Z is the standardized normal value for the level of confidence desired p is the sample proportion of items that do not conform n is the sample size N is the population size

55 Ethical Issues A confidence interval (reflecting sampling error) should always be reported along with a point estimate The level of confidence should always be reported The sample size should be reported An interpretation of the confidence interval estimate should also be provided

56 Chapter Summary In this chapter, we have
Introduced the concept of confidence intervals Discussed point estimates Developed confidence interval estimates Created confidence interval estimates for the mean (σ known) Determined confidence interval estimates for the mean (σ unknown) Created confidence interval estimates for the proportion

57 Chapter Summary In this chapter, we have
Determined required sample size for mean and proportion settings Developed applications of confidence interval estimation in auditing Confidence interval estimation for population total Confidence interval estimation for total difference in the population One sided confidence intervals Addressed confidence interval estimation and ethical issues


Download ppt "Statistics for Managers Using Microsoft® Excel 7th Edition"

Similar presentations


Ads by Google