1. Elementary Mechanics of Fluids CE 319 F Daene McKinney Viscosity

2. Some Simple Flows Flow between a fixed and a moving plate Fluid in contact with the plate has the same velocity as the plate u = x-direction component of velocity u=V Moving plate Fixed plate y x V u=0 B Fluid

3. Some Simple Flows Flow through a long, straight pipe Fluid in contact with the pipe wall has the same velocity as the wall u = x-direction component of velocity r x R V Fluid

4. Fluid Deformation Flow between a fixed and a moving plate Force causes plate to move with velocity V and the fluid deforms continuously. u=V Moving plate Fixed plate y x u=0 Fluid t0t0 t1t1 t2t2

5. u=V+  V Moving plate Fixed plate y x u=V Fluid Fluid Deformation t t+tt+t xx yy  LL Shear stress on the plate is proportional to deformation rate of the fluid

6. Shear in Different Fluids Shear-stress relations for different types of fluids Newtonian fluids: linear relationship Slope of line (coefficient of proportionality) is “viscosity”

7. Viscosity Newton’s Law of Viscosity Viscosity Units Water (@ 20 o C) –  = 1x10 -3 N-s/m 2 Air (@ 20 o C) –  = 1.8x10 -5 N-s/m 2 Kinematic viscosity V V+dv

8. Flow between 2 plates u=V Moving plate Fixed plate y x V u=0 B Fluid Force acting ON the plate Thus, slope of velocity profile is constant and velocity profile is a st. line Force is same on top and bottom

9. Flow between 2 plates u=V Moving plate Fixed plate y x V u=0 B Shear stress anywhere between plates   Shear on fluid

10. Flow between 2 plates 2 different coordinate systems r x B V y x

11. Example: Journal Bearing Given –Rotation rate,  = 1500 rpm –d = 6 cm –l = 40 cm –D = 6.02 cm –SG oil = 0.88 – oil = 0.003 m 2 /s Find: Torque and Power required to turn the bearing at the indicated speed.

12. Example: cont. Assume: Linear velocity profile in oil film

13. Example: Rotating Disk Assume linear velocity profile: dV/dy=V/y=  r/y Find shear stress