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Lesson 5.3 Trapezoids and Kites

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1 Lesson 5.3 Trapezoids and Kites
Homework: 5.3/1-8,19 QUIZ Wednesday 5.1 – 5.4

2 PROCEDURES for today: 1. OPEN TEXTBOOKS 2. Tools – patty paper(2), protractor, ruler 3. INVESTIGATIONs 1 & 2 – ALL steps 4. Complete the 4 kite conjectures & the 3 trapezoid conjectures

3 Definition Kite – a quadrilateral that has two pairs of consecutive congruent sides, but opposite sides are not congruent.

4 Parts of a Kite Vertex angles: <B & <D Vertex diagonal BD
Non-Vertex diagonal CA Non-Vertex angles: <A & <C

5 Properties of Kites The diagonals of a kite are perpendicular
Non-vertex angles (a)are congruent Vertex diagonal bisects the vertex angles non-vertex diagonal

6 Perpendicular Diagonals of a Kite
If a quadrilateral is a kite, then its diagonals are perpendicular.

7 Non-Vertex Angles of a Kite
If a quadrilateral is a kite, then non- vertex angles are congruent A  C, B  D

8 Vertex diagonals bisect vertex angles
If a quadrilateral is a kite then the vertex diagonal bisects the vertex angles.

9 Vertex diagonal bisects the non-vertex diagonal
If a quadrilateral is a kite then the vertex diagonal bisects the non-vertex diagonal

10 Definition-a quadrilateral with exactly one pair of parallel sides.
Trapezoid Definition-a quadrilateral with exactly one pair of parallel sides. Base A B Leg Leg C D Base

11 Leg Angles are Supplementary
Property of a Trapezoid Leg Angles are Supplementary B A <A + <C = 180 <B + <D = 180 C D

12 Isosceles Trapezoid Definition - A trapezoid with congruent legs.

13 Isosceles Trapezoid - Properties
| | 1) Base Angles Are Congruent 2) Diagonals Are Congruent

14 Example PQRS is an isosceles trapezoid. Find m P, m Q and mR.
m R = 50 since base angles are congruent mP = 130 and mQ = 130 (consecutive angles of parallel lines cut by a transversal are )

15 Find the measures of the angles in trapezoid
48 m< A = 132 m< B = 132 m< D = 48

16 Find BE AC = 17.5, AE = 9.6 E

17 Example Find the side lengths of the kite.

18 Example Continued We can use the Pythagorean Theorem to find the side lengths. = (WX)2 = (WX)2 544 = (WX)2 = (XY)2 = (XY)2 288 = (XY)2

19 Find the lengths of the sides of the kite
W 4 Z X 5 5 8 Y

20 Find the lengths of the sides of kite to the nearest tenth
2 4 7 2

21 Example 3 Find mG and mJ. Since GHJK is a kite G  J
So 2(mG) + 132 + 60 = 360 2(mG) =168 mG = 84 and mJ = 84

22 Try This! RSTU is a kite. Find mR, mS and mT.
x x = 360 2x = 360 2x = 80 x = 40 So mR = 70, mT = 40 and mS = 125

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25 Try These 2. m<C = x +12 and
m<B = 3x – 2, find x and the measures of the 2 angles 1. If <A = 134, find m<D x = 42.5 m<C = 54.5 m<B = 125.5 m<D = 46

26 Using Properties of Trapezoids
When working with a trapezoid, the height may be measured anywhere between the two bases.  Also, beware of "extra" information.  The 35 and 28 are not needed to compute this area. Area of trapezoid = Find the area of this trapezoid. A = ½ * 26 * ( ) A = 806

27 Using Properties of Trapezoids
Example 2 Find the area of a trapezoid with bases of 10 in and 14 in, and a height of 5 in.

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31 Area Kite = one-half product of diagonals
Using Properties of Kites Area Kite = one-half product of diagonals

32 a) Find the lengths of all the sides.
Using Properties of Kites Example 6 ABCD is a Kite. a) Find the lengths of all the sides. 2 4 4 E 4 Find the area of the Kite.

33 Venn Diagram: – Properties of Parallelograms

34 Flow Chart:

35 Homework


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