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Published byMyles Parsons Modified over 9 years ago
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Examples of Convolution 3.2
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Graphical Examples Impulse Response of an Integrator circuit due to the unit impulse function Response of an integrator due to a unit step function Response of an Integrator circuit due to the unit ramp input Response of an integrator due to a rectangular pulse
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Impulse Response of an Integrator =δ(t) 0 (τ)(τ) 0 (τ)(τ) interval of integration
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Graphical Examples Impulse Response of an Integrator circuit due to the unit impulse function Response of an integrator due to a unit step function Response of an Integrator circuit due to the unit ramp input Response of an integrator due to a rectangular pulse
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Response of an Integrator Due to a Unit Ramp Function =tu(t) Why is h(t)=u(t) ?
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Response of an Integrator Due to a Unit Step Function =tu(t) Constant!
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Graphical Illustration (t=-1) No area of intersection
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Graphical Illustration (t=1)
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Response of an Integrator Due to a Unit Step Function =tu(t) Unit step function is only 1 when the argument is greater than 0. It does not make sense to integrate all the way to infinity.
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A system with rectangular impulse response δ(t) u(t) u(t-2)
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Example (why not take advatage of linearity ? )
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Focus on x 1 (t) δ(t)→h(t) δ(t+3)→h(t+3)
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Understanding h(t-τ)
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h(t-τ) when t=-1 h(τ) h(-1+τ) h(-1-τ)
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Integration when t<0 h(t-τ) for t<0
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h(t-τ) when t=0.5 h(τ) h(0.5+τ) h(0.5-τ)
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Integration when 0<t<2 h(t-τ) for 0<t<2 (move to the right as t increases )
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h(t-τ) when t=3.5 h(τ) h(3.5+τ)h(3.5-τ) 3.5 3.5-2
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Integration when t>2 t t-2
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