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Name:__________ warm-up 4-6 Solve x 2 – 2x + 1 = 9 by using the Square Root Property. Solve 4c 2 + 12c + 9 = 7 by using the Square Root Property. Find.

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Presentation on theme: "Name:__________ warm-up 4-6 Solve x 2 – 2x + 1 = 9 by using the Square Root Property. Solve 4c 2 + 12c + 9 = 7 by using the Square Root Property. Find."— Presentation transcript:

1 Name:__________ warm-up 4-6 Solve x 2 – 2x + 1 = 9 by using the Square Root Property. Solve 4c 2 + 12c + 9 = 7 by using the Square Root Property. Find the value of c that makes the trinomial x 2 + x + c a perfect square. Then write the trinomial as a perfect square. Solve x 2 + 2x + 24 = 0 by completing the square

2 Find the value(s) of k in x 2 + kx + 100 = 0 that would make the left side of the equation a perfect square trinomial.

3 Details of the Day EQ: How do quadratic relations model real-world problems and their solutions? Depending on the situation, why is one method for solving a quadratic equation more beneficial than another? How do transformations help you to graph all functions? Why do we need another number set? I will be able to… Activities: Warm-up Review homework Notes: 4-6 Quadratic Formula and the Discriminant Class work/ HW Vocabulary: Quadratic Formula discriminant. Solve quadratic equations by using the Quadratic Formula. Use the discriminant to determine the number and type of roots of a quadratic equation.

4 SlopeSlopeSlopeSlopeSlopeSlopeSlopeSlope SlopeSlopelopeSloeSlopeSlopeSlopeSlope SlopeSlopeSlopeSlopeSlopeSlopeSlopeSlopeSlope The Discriminant

5 A Quick Review Solve x 2 – 2x + 1 = 9 by using the Square Root Property. Solve 4c 2 + 12c + 9 = 7 by using the Square Root Property. Find the value of c that makes the trinomial x 2 + x + c a perfect square. Then write the trinomial as a perfect square. Solve x 2 + 2x + 24 = 0 by completing the square

6 A Quick Review Find the value(s) of k in x 2 + kx + 100 = 0 that would make the left side of the equation a perfect square trinomial.

7 Notes and examples Solve x 2 – 8x = 33 by using the Quadratic Formula

8 Notes and examples Solve x 2 + 13x = 30 by using the Quadratic Formula Solve x 2 – 34x + 289 = 0 by using the Quadratic Formula.

9 Notes and examples Solve x 2 – 22x + 121 = 0 by using the Quadratic Formula. Solve x 2 – 6x + 2 = 0 by using the Quadratic Formula.

10 Notes and examples Solve x 2 – 5x + 3 = 0 by using the Quadratic Formula. Solve x 2 + 13 = 6x by using the Quadratic Formula. Solve x 2 + 5 = 4x by using the Quadratic Formula.

11 Notes and examples

12 Find the value of the discriminant for x 2 + 3x + 5 = 0. Then describe the number and type of roots for the equation Find the value of the discriminant for x 2 – 11x + 10 = 0. Then describe the number and type of roots for the equation.

13 Notes and examples Find the value of the discriminant for x 2 + 2x + 7 = 0. Describe the number and type of roots for the equation. Find the value of the discriminant for x 2 + 8x + 16 = 0. Describe the number and type of roots for the equation.

14 Notes and examples

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