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Comparing Population Parameters (Z-test, t-tests and Chi-Square test) Dr. M. H. Rahbar Professor of Biostatistics Department of Epidemiology Director, Data Coordinating Center College of Human Medicine Michigan State University
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Is there an association between Drinking and Lung Cancer? Suppose a case-control study is conducted to test the above hypothesis?
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QUESTION: Is there a difference between the proportion of drinkers among cases and controls?
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Elements of Testing hypothesis Null Hypothesis Alternative hypothesis Level of significance Test statistics P-value Conclusion
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Case Control Study of Drinking and Lung Cancer Null Hypothesis: There is no association between Drinking and Lung cancer, P1=P2 or P1-P2=0 Alternative Hypothesis: There is some kind of association between Drinking and Lung cancer, P1 P2 or P1-P2 0
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Based on the data in the following contingency table we estimate the proportion of drinkers among those who develop Lung Cancer and those without the disease?
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Test Statistic How many standard deviations has our estimate deviated from the hypothesized value if the null hypothesis was true?
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P-value for a two tailed test P-value= 2 P[Z > 2.003] = 2(.024)=0.048 How does this p-value compared with =0.05? Since p-value=0.048 < =0.05, reject the null hypothesis H0 in favor of the alternative hypothesis Ha. Conclusion: There is an association between drinking and lung cancer. Is this relationship causal?
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Chi-Square Test of Independence (based on a Contingency Table)
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In the following contingency table estimate the proportion of drinkers among those who develop Lung Cancer and those without the disease?
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E11=1700(60)/4000=25.5 E12=34.5 E21=1674.5 E22=2265.5
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How do we calculate P-value? SPSS, Epi-Info statistical packages could be used to calculate the p-value for various tests including the Chi-Square Test If p-value is less than 0.05, then reject the null hypothesis that rows and column variables are independent
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Testing Hypothesis When Two Population Means are Compared H0: 1= 2 Ha: 1 2
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QUESTION: Is there an association between age and Lung Cancer?
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Use Two-sample t-test when both samples are independent H0: 1 = 2 vs Ha: 1 2 H0: 1 - 2 = 0 vs Ha: 1 - 2 0 t= difference in sample means – hypothesized diff. SE of the Difference in Means Statistical packages provide p-values and degrees of freedom Conclusion: If p-value is less than 0.05, then reject the equality of the means
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Paired t-test for Matched case control study H0: 1 = 2 vs Ha: 1 2 H0: 1 - 2 = 0 vs Ha: 1 - 2 0 Paired t-test= Mean of the differences –0 SE of the Differences in Means Statistical packages provide p-values for paired t-test Conclusion: If p-value is less than 0.05, then reject the equality of the means
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