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Chapter 5: Variability and Standard (z) Scores How do we quantify the variability of the scores in a sample? 556065707580859095100105110115 0 1 2 3 4 5 Ice Dancing Score Frequency
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Method 1: range: difference between the highest and lowest scores Ice Dancing, compulsory dance scores, Winter Olympics 111.15 108.55 106.6 103.33 100.06 97.38 96.67 96.12 92.75 89.62 85.36 84.58 83.89 83.12 80.47 80.3 79.31 76.73 74.25 72.01 68.87 63.73 59.64 Example: The range of ice dancing scores is 111.15-59.64 = 51.51 points The range is easy to calculate, but it really only depends on two scores. So it’s not a very informative or reliable measure of variability.
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Method 2: The semi-interquartile range (Q): One half of the distance between P 75 and P 25. Ice Dancing, compulsory dance scores, Winter Olympics Example: ice dancing scores Q 1 = P 25 Q 3 = P 75 Percentile rank 111.1598 108.5593 106.689 103.3385 100.0680 97.3876 96.6772 96.1267 92.7563 89.6259 85.3654 84.5850 83.8946 83.1241 80.4737 80.333 79.3128 76.7324 74.2520 72.0115 68.8711 63.737 59.642 Score
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Method 3: Variance: the mean of the squares of the deviation scores deviation score: The difference between a score and the mean of the scores Formula for variance of a population of scores Formula for variance of a sample of scores Sums of squared deviation scores
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Example: find the variance of this sample of 7 numbers: 5,3,1,6,2,8,3
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Calculating variance this way can be tedious. Fortunately there’s a shortcut for calculating SS x : Sum of squared deviations from the mean Sum of squares Sum squared divided by n
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Example: from this sample of 7 numbers: 5,3,1,6,2,8,3
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Example: calculate the variance of this sample of 10 numbers: 8 6 3 7 1 7 7 8 9 10 XX2X2 864 636 39 749 11 7 7 864 981 10100 10 502 66 4356 435.6 66.4 6.64 n =
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standard deviation: the square root of the variance Formula for standard deviation for a population of scores Formula for standard deviation for a sample of scores The standard deviation has the same units as the original scores (e.g. points, inches, etc.)
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Warning! Point of future confusion! The definition of variance and standard deviation has an (or N) in the denominator. Later when we get in to inferential statistics, we’ll start dividing by n-1: The first definition is the true average of the squared deviance from the mean. But this number a biased estimate of the variance of the population. Divide by ‘n’ when you just want the standard deviation of our sample (or population). Divide by ‘n-1’ when you want to estimate the standard deviation of the population.
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Example: calculate the standard deviation of this sample of 10 numbers: 8 6 3 7 1 7 7 8 9 10 XX2X2 864 636 39 749 11 7 7 864 981 10100 10 502 66 4356 435.6 66.4 6.64 2.58 n =
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Example: calculate the standard deviation of this sample of 20 numbers: 8 6 3 7 1 7 7 8 9 10 3 2 3 4 6 3 2 8 3 1 64 36 9 49 1 64 81 100 9 4 9 16 36 9 4 64 9 1 XX2X2 n = 20 663 101 10201 510.05 152.95 7.65 2.77
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CharacteristicRange Semi- interquartile range Standard deviation Frequency of useSomeVery littleAlmost always Mathematical tractability Very little Great Sampling stabilityWorstOKBest Use with skewed distributions Not so goodOKInterpret with caution Most closely related central tendency NoneMedianMean Use with open ended distributions NoOKNo Affected by sample size YesNo Ease of calculationEasyOK
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Fun facts about the standard deviation: Adding a constant to each number in a sample does not change the standard deviation (or variance) S X+b = S X Multiplying each number in a sample by a constant multiplies the standard deviation by that same constant. S aX = aS X
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How big is a standard deviation? For a normal (bell-shaped) distribution: 68.2% of the values fall within one standard deviation of the mean 95.4% of the values fall within two standard deviations of the mean 99.7% of the values fall within three standard deviations of the mean 1 standard deviation above and below the mean is where the bend of the curve switches (the ‘inflection point’)
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Guess the mean and standard deviation
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Standard Scores (z scores) Sometimes it is useful to compare scores across distributions that have different means and standard deviations. A common way to do this is to convert the scores into standard deviation units, or ‘z scores’. The goal is to modify all of the scores so that the new mean is equal to zero, and the new standard deviation equal to one. To make the new mean zero, we subtract the mean from all scores. Remember this shifts the mean but doesn’t change the standard deviation. To make the new standard deviation equal to 1, we divide all scores by the standard deviation. This would normally change the mean, but since it’s zero, it doesn’t change. Here’s the formula for changing a sample of scores, X to z:
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Example: Convert the following ten scores to z scores XX2X2 n = Step 1, calculate the mean and standard deviation: 23 4 12 42 62 93 7 23 8 54 529 16 144 1764 3844 8649 49 529 64 2916 10 18504 328 107584 10758.40 7745.60 774.56 27.83 32.80
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Example: Convert the following ten scores to z scores X Step 2, for each score, subtract the mean and divide by the standard deviation 23 4 12 42 62 93 7 23 8 54 27.83 32.80 -0.35 -1.03 -0.75 0.33 1.05 2.16 -0.93 -0.35 -0.89 0.76 -9.80 -28.80 -20.80 9.20 29.20 60.20 -25.80 -9.80 -24.80 21.20 Check for yourself that the mean of z is 0, and the standard deviation is 1.
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Z-transforming your scores doesn’t affect the shape of the distribution. 050100150 0 20 40 60 80 100 Score Mean= 80, s.d. = 33.0 -20123 0 20 40 60 80 100 z score Mean= 0, s.d. = 1
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The standard normal distribution The standard normal distribution is a continuous distribution. It has a mean of 0 and a standard deviation of 1 The total area under the curve is equal to 1 -4-3-201234 Relative frequency z score
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-3-20123 area =0.1587 z -3-20123 area =0.3413 z Table A (page 436) gives you the proportion of scores for given ranges in the standard normal Column 2 Area between 0 and z Column 3 Area above z
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