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Lecture 5 Current/Voltage Measurement Resistance Measurement Wheatone Circuit.

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Presentation on theme: "Lecture 5 Current/Voltage Measurement Resistance Measurement Wheatone Circuit."— Presentation transcript:

1 Lecture 5 Current/Voltage Measurement Resistance Measurement Wheatone Circuit

2 Current/Voltage Measurement

3 Circuit Model for ideal ammeter/voltmeter An ideal ammeter has an equivalent resistance of 0 Ohm. An ideal voltmeter has an infinite equivalent resistance.

4 d’Arsonval meter When current flows in the coil, it creates a torque on the coil, causing it to rotate and move a pointer across a calibrated scale. The deflection of the pointer is proportional to the current

5 Commercial Rating Rating: 50 mV and 1mA Interpretation: When the coil is carry 1 mA, the voltage drop across the coil is 50 mV and the pointer is deflected to its full-scale position.

6 A DC Ammeter Circuit R A is added limits the amount of current in the coil.

7 Example 3.5 (a) A 50 mV, 1 mA d’Arsoval movement is to be used in an ammeter with a full- scale reading of 10 mA. Determine R A. (10 mA) (1 mA, 50 mV) Current through RA?

8 Example 3.5 (c) How much resistance is added to the circuit when the 10 mA ammeter is inserted to measure current? (1 mA, 50 mV) (10 mA) 50 mV/1mA=50 Ohms 50 Ohms in parallel with RA (which is 50/9 Ohms) gives 5 Ohm. RmRm

9 Example 3.5 (b) A 50 mV, 1 mA d’Arsoval movement is to be used in an ammeter with a full- scale reading of 1 A. Determine R A. (1 A) (1 mA, 50 mV) Current through RA?

10 Example 3.5 (b) How much resistance is added to the circuit when the 1 A ammeter is inserted to measure current? (1 mA, 50 mV) (1 A) 50 mV/1mA=50 Ohms 50 Ohms in parallel with RA (which is 50/999 Ohms) gives 50 mOhm. RmRm

11 A DC Voltmeter Circuit R V is added limits the voltage drop across the meter’s coil.

12 Example 3.6 A 50 mV, 1 mA d’Arsoval movement is to be used in a voltmeter in which the full-scale reading is 150 V. Determine R V. 1 mA + - 50 mV + - (150 V) Needle resistance: 50 mV/1mA=50 Ohms

13 Example 3.6 (c) How much resistance does the 150 V meter insert into the circuit? 1 mA + - 50 mV + - (150 V) Rv=149,950 Ohms, Rm=Rv+50mV/1mA=150,000 KOhms RmRm

14 Accuracy of Multimeter Analog multimeters: 3% Portable Digital Multimeter: 0.5 % Wheatstone: 0.1 %

15 Resistance Measurement R 1,R 2, and R 3 are known resistors R x is the unknown resistor Adjust R 3 until there is no current in the meter Wheastone Bridge Used to measure Resistance between 1 Ohms and 1 MOhms

16 Determine R x Adjust the variable resistor R 3 until there is no current in the galvanometer. Calculate the unknown resistor from the simple expression: – R x =(R 2 /R 1 )R 3

17 Derivation No current from a to b i 1 =i 3 I 2 =i x Relationship: VR1=VR2 VR3=VRx

18 Possible Range of Rx R x =(R 2 /R 1 )R 3 – Change R2/R1 in order to measure a wide range of Rx – Implement R2 and R1 using precision R1, R2 that can be switched into the bridge circuit. Possible values: 1,10, 100, 1000 Ohms – Range of R2/R1: 0.001 to 1000 – Range of R3 usually from 1 to 10 Kohms – Measurable Rx is from1 Ohm to 1 MOhm

19 Meter Resistance Included What do you do with this resistive network? Can you simplify it?

20 Δ to Y Equivalent Circuit


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