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Using Right Triangle Trigonometry (trig, for short!) MathScience Innovation Center Betsey Davis
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Geometry SOL 7 The student will solve practical problems using: Pythagorean Theorem Properties of Special Triangles Right Triangle Trigonometry
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 1 Jenny lives 2 blocks down and 5 blocks over from Roger. How far will Jenny need to walk if she takes the short cut? J R Pythagorean Theorem 2^2 +5 ^2 = ? 29 So shortcut is
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 2 Shawna wants to build a triangular deck to fit in the back corner of her house. How many feet of railing will she need across the opening? Special 30-60-90 triangle Hypotenuse is 10 feet She will need 10 feet of railing 5 feet Railing across here
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 3 Rianna wants to find the angle between her closet and bed. We don’t need the pythagorean theorem It is not a special triangle We don’t need trig We just need to know the 3 angles add up to 180 X is 50 100 o x 30 o
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Review Find: Sin A Cos A Tan A 5 12 13 A = 5/13 = 12/13 = 5/12 S = O/H C = A/H T = O/A
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis If you know the angles, the calculator gives you sin, cos, or tan: Check MODE to be sure DEGREE is highlighted (not radian) Press SIN 30 ENTER Press COS 30 ENTER Press TAN 30 ENTER Write down your 3 answers
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis What answers did you get? Sin 30 =.5 Cos 30 =.866 Tan 30 =.577 These ratios are the ratios of the legs and hypotenuse in the right triangle. 8 30 60 ? ? 4 Sin 30 = O/H = 4/8=.5cos 30 = A/H = 6.93/8=.866tan 30 = O/A = 4/6.93=.577
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis If sin, cos, tan can be found on the calculator, we can use them to find missing triangle sides. 20 o 50 ? ?
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis If sin, cos, tan can be found on the calculator, we can use them to find missing triangle sides. 20 o 50 x y Sin 20 = x /50 Cos 20 = y/50 Tan 20 = x /y
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Let’s solve for x and y 20 o 50 x y Sin 20 = x /50 cos 20 = y/50.342 = x/50 17.1 = x.940 = y/50 47 = y
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Do the answers seem reasonable? 20 o 50 17.1 47 No, but the diagram is not reasonable either.
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 4 Pythagorean Theorem does not work without more sides. It is not a “special” triangle. We must use trig ! 50 feet 20 o Jared wants to know the height of the flagpole. He measures 50 feet away from the base of the pole and can see the top at a 20 degree angle. How tall is the pole?
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 4 Which of the 3 choices: sin, cos, tan uses the 50 and the x???? 50 feet 20 o Tan 20 = x/50 Press tan 20 enter So now we know.364 = x/50 Multiply both sides by 50 X = 18.2 feet
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 5 Federal Laws specify that the ramp angle used for a wheelchair ramp must be less than or equal to 8.33 degrees. 3 feet You want to build a ramp to go up 3 feet into a house. What horizontal space will you need? How long must the ramp be?
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 5 3 feet You want to build a ramp to go up 3 feet into a house. What horizontal space will you need? How long must the ramp be? 8.33 o Sin 8.33 = 3/y.145 = 3/y.145y= 3 Y= 3/.145 Y=20.7 feet
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Using Right Triangle Trig 2005 MathScience Innovation Center B. Davis Practical Problem Example 5 3 feet You want to build a ramp to go up 3 feet into a house. What horizontal space will you need? How long must the ramp be? 8.33 o tan 8.33 = 3/x.146 = 3/x.146x= 3 x= 3/.146 x=20.5 feet
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