1. Binomial
Probability
Distribution

2. Permutations
Number of possible arrangements

3. Combinations
Number of sets or groups

4. Binomial Theorem

5. Binomial Distribution
The binomial distribution is the probability distribution that results from sampling a binomial population. Binomial samples have the following properties:
1. Fixed number of trials, represented as n.
2. Each trial has two possible outcomes, a “success” and a “failure”.
3. P(success)=p (and thus: P(failure)=1–p), for all trials.
4. The trials are independent, which means that the outcome of one trial does not affect the outcomes of any other trials. May be population is large enough that sampling without replacement does not change values.

6. Success and Failure…
…are just labels for a binomial experiment, there is no value judgment implied.
For example a coin flip will result in either heads or tails. If we define “heads” as success then necessarily “tails” is considered a failure (in as much as we attempting to have the coin lands heads up).
Other binomial experiment notions:
An election candidate wins or loses
An employee is male or female

7. Example
Pat Statsdud is a (not good) student taking a statistics course. Pat’s exam strategy is to rely on luck for the next quiz. The quiz consists of 10 multiple-choice questions. Each question has five possible answers, only one of which is correct. Pat plans to guess the answer to each question.
What is the probability that Pat gets no answers correct?
What is the probability that Pat gets two answers correct?

8. Pat Statsdud… Algebraically then: n=10, and P(success)= 1/5 = .20
Pat plans to guess the answer to each question.
Is this a binomial experiment? Check the conditions:
There is a fixed finite number of trials (n=10).
An answer can be either correct or incorrect.
The probability of a correct answer (P(success)=.20) does not change from question to question.
 Each answer is independent of the others.

9. Pat Statsdud… n=10, and P(success) = .20
a. What is the probability that Pat gets no answers correct?
i.e. # success, x, = 0; hence we want to know P(x=0)
Pat has about an 11% chance of getting no answers correct
using the guessing strategy.

10. Pat Statsdud… n=10, and P(success) = .20
b. What is the probability that Pat gets two answers correct?
I.e. # success, x, = 2; hence we want to know P(x=2)
Pat has about a 30% chance of getting exactly two answers
correct using the guessing strategy.

11. The binomial distribution with n trials and success probability p has:
Binomial Probability Distribution
The binomial distribution with n trials and success probability p has:
Mean =
Variance =
Standard deviation =

12. Cumulative Probability…
Thus far, we have been using the binomial probability distribution to find probabilities for individual values of x. To answer the question: (Example 10)
“Find the probability that Pat fails the quiz”
requires a cumulative probability, that is, P(X ≤ x)
If a grade on the quiz is less than 50% (i.e. 5 questions out of 10), that’s considered a failed quiz.
Thus, we want to know what is: P(X ≤ 4) to answer

13. Pat Statsdud P(X ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)
We already know P(0) = and P(2) = Using the binomial formula to calculate the others:
P(1) = , P(3) = .2013, and P(4) = .0881
We have P(X ≤ 4) = … = .9672
Thus, its about 97% probable that Pat will fail the test using the luck strategy and guessing at answers…

14. BinomialPDF & …CDF

15. Pat Statsdud Has Been Cloned
Suppose that a professor has a class full of students like Pat. What is the mean?
What is the standard deviation?
The mean = μ = np = 10(0.2) = 2
The standard deviation is
σ = √ np ( 1 – p ) = √ 10( .2)( )
= 1.26

16. Sampling Distribution of the Sample Proportion
Lock Section 6.1
Sampling Distribution of the Sample Proportion
The situation in this section is that we are interested in the proportion of the population that has a certain characteristic.

17. Binomial Population Two Choices: Success Failure Fixed Probability
Independence

18. Sampling Distribution

19. P-Hat
This proportion is the population parameter of interest, denoted by symbol p.
We estimate this parameter with the statistic p-hat – the number in the sample with the characteristic divided by the sample size n.

20. P-Hat Definition
P-hat is the number of “successes” / sample size

21. Properties of p-hat
When sample sizes are fairly large, the shape of the p-hat distribution will be normal.
The mean of the distribution is the value of the population parameter p.
The standard deviation of this distribution is the square root of p(1-p)/n.

22. Sampling Distribution of p-hat
For the sampling distribution to be normal, you must have:

23. Calculate Probabilities
Because the shape of the distribution is normal, we can standardize the variable p-hat to a Z standard normal distribution. Use Z-transform:

25. Confidence Intervals for Population Proportions
Lock Section 6.2
Confidence Intervals for Population Proportions
AP Statistics

26. Confidence Intervals Confidence Intervals Population Mean Population
Proportion
σ Known
σ Unknown
AP Statistics

27. Confidence Intervals for the Population Proportion, p
Recall that the distribution of the sample proportion is approximately normal if the sample size is large, with standard deviation
We will estimate this with sample data:
AP Statistics

28. How Big????
Rule of Thumb 1: Formula for standard deviation of p-hat only when the population, N, is at least 10 times the sample size: N ≥ 10 n
Rule of Thumb 2: The sampling distribution of p-hat is approximately Normal when
np ≥ 10 and n(1-p) ≥ 10

29. Confidence interval endpoints
Upper and lower confidence limits for the population proportion are calculated with the formula
where
z is the standard normal value for the level of confidence desired
p is the sample proportion
n is the sample size
AP Statistics

30. Example A random sample of 100 people shows that 25 are left-handed.
Form a 95% confidence interval for the true proportion of left-handers
AP Statistics

31. Example
(continued)
A random sample of 100 people shows that 25 are left-handed. Form a 95% confidence interval for the true proportion of left-handers. 1. 2. 3.
AP Statistics

32. 1-PropZInterval

33. Interpretation
We are 95% confident that the true percentage of left-handers in the population is between
16.51% and 33.49%.
Although this range may or may not contain the true proportion, 95% of intervals formed from samples of size 100 in this manner will contain the true proportion.
AP Statistics

34. Changing the sample size
Increases in the sample size reduce the width of the confidence interval.
Example:
If the sample size in the above example is doubled to 200, and if 50 are left-handed in the sample, then the interval is still centered at .25, but the width shrinks to
.19 …… .31
AP Statistics

35. Example 2
A random sample of 400 graduates showed 32 went to grad school. Set up a 95% confidence interval estimate for p. 82

36. Example 2
A random sample of 400 graduates showed 32 went to grad school. Set up a 95% confidence interval estimate for p. 81

37. Thinking Challenge
You’re a production manager for a newspaper. You want to find the % defective. Of 200 newspapers, 35 had defects. What is the 90% confidence interval estimate of the population proportion defective?

38. Confidence Interval Solution84

39. Required Sample Size Define the margin of error: Solve for n:
p can be estimated with a pilot sample, if necessary (or conservatively use p = .50)
AP Statistics

40. What sample size...?
How large a sample would be necessary to estimate the true proportion defective in a large population within 3%, with 95% confidence?
(Assume a pilot sample yields p-hat = .12)
AP Statistics

41. What sample size...? Solution: For 95% confidence, use Z = 1.96
(continued)
Solution:
For 95% confidence, use Z = 1.96
E = .03
P-hat = .12, so use this to estimate p
So use n = 451
AP Statistics

43. Hypothesis Tests For Single Proportions
Lock Section 6.3
Hypothesis Tests For Single Proportions

44. Test of Proportions
Old drug cures 80 percent of the time. New drug for heartworm disease in dogs cures 90 percent of n=1000 dogs, so p-hat=.9.
What is the probability that this results occurred by random chance?

45. Proportion Test