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Chapter 5 Computer Organization ( 計算機組織 ). Distinguish between the three components of a computer hardware. List the functionality of each component.

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Presentation on theme: "Chapter 5 Computer Organization ( 計算機組織 ). Distinguish between the three components of a computer hardware. List the functionality of each component."— Presentation transcript:

1 Chapter 5 Computer Organization ( 計算機組織 )

2 Distinguish between the three components of a computer hardware. List the functionality of each component. Understand memory addressing and calculate the number of bytes for a specified purpose. After reading this chapter, the reader should be able to: O BJECTIVES Distinguish between different types of memories. Understand how each input/output device works. Continued on the next slide

3 Understand the systems used to connect different components together. Understand the addressing system for input/output devices. Understand the program execution and machine cycles. O BJECTIVES (continued) Distinguish between programmed I/O, interrupt-driven I/O and direct memory access (DMA). Understand the two major architectures used to define the instruction sets of a computer: CISC and RISC.

4 Figure 5-1 Computer hardware (subsystems)

5 CENTRALPROCESSING UNIT (CPU) CENTRALPROCESSING 5.1

6 Figure 5-2 CPU

7 MAIN MEMORY 5.2

8 Table 5.1 Memory units Unit Unit ------------ kilobyte megabyte gigabyte terabyte petabyte exabyte Exact Number of bytes Exact Number of bytes ------------------------ 2 10 bytes 2 20 bytes 2 30 bytes 2 40 bytes 2 50 bytes 2 60 bytes Approximation Approximation ------------ 10 3 bytes 10 6 bytes 10 9 bytes 10 12 bytes 10 15 bytes 10 18 bytes

9 Figure 5-3 Main memory

10 Memory addresses are defined using unsigned binary integers. Note:

11 Example 1 A computer has 32 MB (megabytes) of memory. How many bits are needed to address any single byte in memory? Solution The memory address space is 32 MB, or 2 25 (2 5 x 2 20 ). This means you need log 2 2 25 or 25 bits, to address each byte.

12 Example 2 A computer has 128 MB of memory. Each word in this computer is 8 bytes. How many bits are needed to address any single word in memory? Solution The memory address space is 128 MB, which means 2 27. However, each word is 8 (2 3 ) bytes, which means that you have 2 24 words. This means you need log 2 2 24 or 24 bits, to address each word.

13 Memory Types RAM (Random access memory): –SRAM (Static RAM) (flip-flop gates) –DRAM (Dynamic RAM) ROM (Read only memory) –PROM (programmable) –EPROM (erasable programmable) –EEPROM (electronically erasable programmable)

14 A simple flip-flop circuit Set Reset

15 Setting the output of a flip-flop to 1

16 Setting the output of a flip-flop to 1 (continued)

17 Setting the output of a flip-flop to 1

18 Another way of constructing a flip-flop

19 Figure 5-4 Memory hierarchy

20 Figure 5-5 Cache

21 INPUT / OUTPUT 5.3

22 Figure 5-6 Physical layout of a magnetic disk

23 Figure 5-7 Surface organization of a disk

24 Figure 5-8 Mechanical configuration of a tape

25 Figure 5-9 Surface organization of a tape

26 Figure 5-10 Creation and use of CD-ROM

27 Table 5.2 CD-ROM speeds Speed ------------ 1x 2x 4x 6x 8x 12x 16x 24x 32x 40x Data Rate Data Rate ------------------------ 153,600 bytes per second 307,200 bytes per second 614,400 bytes per second 921,600 bytes per second 1,228,800 bytes per second 1,843,200 bytes per second 2,457,600 bytes per second 3,688,400 bytes per second 4,915,200 bytes per second 6,144,000 bytes per second Approximation Approximation ------------ 150 KB/s 300 KB/s 600 KB/s 900 KB/s 1.2 MB/s 1.8 MB/s 2.4 MB/s 3.6 MB/s 4.8 MB/s 6 MB/s

28 Figure 5-11 CD-ROM format

29 Figure 5-12 Making a CD-R

30 Figure 5-13 Making a CD-RW

31 Table 5.3 DVD capacities Feature Feature --------------------------------- single-sided, single-layer single-sided, dual-layer double-sided, single-layer double-sided, dual-layer Capacity Capacity ------------ 4.7 GB 8.5 GB 9.4 GB 17 GB

32 SUBSYSTEMINTERCONNECTIONSUBSYSTEMINTERCONNECTION 5.4

33 Figure 5-14 Connecting CPU and memory using three buses

34 Figure 5-15 Connecting I/O devices to the buses

35 Figure 5-16 SCSI controller (Small Computer System Interface) Daisy Chain

36 Figure 5-17 FireWire controller (IEEE 1394)

37 Figure 5-18 USB controller (Universal Serial Bus)

38 Figure 5-19 Isolated I/O addressing

39 Figure 5-20 Memory-mapped I/O addressing

40 PROGRAMEXECUTIONPROGRAMEXECUTION 5.5

41 Figure 5-21 Steps of a cycle

42 Figure 5-22 Contents of memory and register before execution

43 Figure 5-23.a Contents of memory and registers after each cycle

44 Figure 5-23.b Contents of memory and registers after each cycle

45 Figure 5-23.c Contents of memory and registers after each cycle

46 Figure 5-23.d Contents of memory and registers after each cycle

47 Figure 5-24 Programmed I/O

48 Figure 5-25 Interrupt-driven I/O

49 Figure 5-26 DMA connection to the general bus

50 Figure 5-27 DMA input/output

51 TWO DIFFERENT ARCHITECTURES ARCHITECTURES 5.6

52 Two different architectures CISC (Complex Instruction Set Computer) –Intel RISC (Reduced Instruction Set Computer) –PowerPC


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