Presentation is loading. Please wait.

Presentation is loading. Please wait.

Lecture 2 2.1 Sources 2.2 Ohm’s Law 2.4 Kirchhoff’s Laws.

Similar presentations


Presentation on theme: "Lecture 2 2.1 Sources 2.2 Ohm’s Law 2.4 Kirchhoff’s Laws."— Presentation transcript:

1 Lecture 2 2.1 Sources 2.2 Ohm’s Law 2.4 Kirchhoff’s Laws

2 Voltage and Current Sources

3 Independent Sources

4 Characteristics An independent source establishes a voltage or current in a circuit without relying on voltages and currents elsewhere in the circuit. The value of the voltage or current supplied is specified by the value of the independent source alone.

5 Exercise

6 Electrochemistry of a Lemon Battery Zn→Zn 2+ +2e - Cu 2+ +2e - →Cu Add standard reduction potential to obtain the voltage across the terminals. +0.76 V +0.34 V Net: 1.10 V - + e-e-

7 Typical Values 1 Lemon – 0.9 Volts – 300 uA – 270 uW Red LED: – 1.7 V – 500 uA – 850 uW, i.e. 3 lemons in series

8 Ohm’s Law

9 Analogy The height of the water=voltage The volume of flow through the hole per second=current The smallness of the hole = resistance Water wheel hit by the flow from the hole = power

10 Thought Experiment #1 Fixed hole dimension↔ Fixed R Height of water↑ → flow rate↑. V↑ → I↑

11 Thought Experiment #2 Fixed height of water↔ Fixed V Hole dimension↑ → flow rate↑ R↓ → I↑

12 Derivation of Ohm’s Law Three variables: V,I and R. Different Possibilities: – V=IR (1) – I=VR (2) – R=VI (3) Intuition – If R is constant, V↑ → I↑. (3) is not possible. (1) and (2) are possible. – If V is constant, R↓ → I↑. (2) and (3) are not possible

13 Ohm’s Law V=IR Mnemonic: Victory Is Rare V represents the voltage difference between the two terminals of a resistor!

14 Exercise Calculate the value v a Determine the power dissipated in the resistor

15 Exercise ` Current is equal to 50V/25 Ohms=2A The battery provides -100W of power. The resistor uses +100 W of power.

16 My Favorite Quiz Question What is the current through the 25 Ohm resistor? Current =(50V-25V)/25 Ohms=1A

17 Current Flows from a point of High potential to a point of Low potential

18 Problem 2.21 Label the (+) and (-) terminal of the 65 Ω s and 50 Ω given the assumed direction of i 0 and i 1.

19 Kirchhoff’s Laws

20

21 KCL Kirchhoff’s Current law (KCL) – The algebraic sum of all the currents at any node in a circuit equals zero

22 Bipolar Junction Transistor Example I E =I B +I C Bipolar Junction Transistor Electronics I (ES230)

23 A Voltage Adder Using an Operational Amplifier (Application: Noise Cancellation) I R1 I R2 IRFIRF KCL: I R1 +I R2 =I RF Class: ES220

24 KVL Kirchhoff’s Voltage Law – The algebraic sum of all the voltage around any closed path in a circuit equals zero

25 Exercise Sum the voltages around each designated path in the circuit

26 Example 2.8 1.KCL at b 2.KVL around cabc loop 3.Solve for i o and i 1

27 Problem 2.18 1.KCL at the top node 2.KVL around the right loop 3.Find i 1, i 2, v o


Download ppt "Lecture 2 2.1 Sources 2.2 Ohm’s Law 2.4 Kirchhoff’s Laws."

Similar presentations


Ads by Google