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Published byEustace Pitts Modified over 9 years ago
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A Fourier series can be defined for any function over the interval 0 x 2L where Often easiest to treat n=0 cases separately
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Compute the Fourier series of the SQUARE WAVE function f given by 22 Note: f(x) is an odd function ( i.e. f(-x) = -f(x) ) so f(x) cos nx will be as well, while f(x) sin nx will be even.
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change of variables: x x' = x- periodicity: cos ( X+n ) = (-1) n cosX for n = 1, 3, 5,…
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for n = 2, 4, 6,… change of variables: x x' = nx IF f(x) is odd, all a n vanish!
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periodicity: sin ( X±n ) = (-1) n sinX for n = 1, 3, 5,… and vanishing for n = 2, 4, 6,… change of variables: x x new = x old -
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for n = 1, 3, 5,… for n = 2, 4, 6,… change of variables: x x' = nx for odd n for n = 1, 3, 5,…
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1 22 x y N = 1 N= 5
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http://www.jhu.edu/~signals/fourier2/ http://www.phy.ntnu.edu.tw/java/sound/sound.html http://mathforum.org/key/nucalc/fourier.html http://www.falstad.com/fourier/ Leads you through a qualitative argument in building a square wave Add terms one by one (or as many as you want) to build fourier series approximation to a selection of periodic functions Build Fourier series approximation to assorted periodic functions and listen to an audio playing the wave forms Customize your own sound synthesizer
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Fourier transforms of one another
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Two waves of slightly different wavelength and frequency produce beats. x x x 1k1k k = 2 NOTE: The spatial distribution depends on the particular frequencies involved
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Many waves of slightly different wavelength can produce “wave packets.”
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Adding together many frequencies that are bunched closely together …better yet… integrating over a range of frequencies forms a tightly defined, concentrated “wave packet” http://phys.educ.ksu.edu/vqm/html/wpe.html A staccato blast from a whistle cannot be formed by a single pure frequency but a composite of many frequencies close to the average (note) you recognize You can try building wave packets at
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The broader the spectrum of frequencies (or wave number) …the shorter the wave packet! The narrower the spectrum of frequencies (or wave number) …the longer the wave packet!
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Fourier Transforms Generalization of ordinary “Fourier expansion” or “Fourier series” Note how this pairs “canonically conjugate” variables and t. Whose product must be dimensionless (otherwise e i t makes no sense!)
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Conjugate variables time & frequency: t, What about coordinate position & ???? r or x inverse distance?? wave number, In fact through the deBroglie relation, you can write:
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x0 x0 For a well-localized particle (i.e., one with a precisely known position at x = x 0 ) we could write: Dirac -function a near discontinuous spike at x=x 0, (essentially zero everywhere except x=x 0 ) x0 x0 with such that f(x)≈ f(x 0 ), ≈constant over x x, x+ x xx 1x1x
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For a well-localized particle (i.e., one with a precisely known position at x = x 0 ) we could write: In Quantum Mechanics we learn that the spatial wave function ( x ) can be complemented by the momentum spectrum of the state, found through the Fourier transform: Here that’s Notice that the probability of measuring any single momentum value, p, is: What’s THAT mean? The probability is CONSTANT – equal for ALL momenta! All momenta equally likely! The isolated, perfectly localized single packet must be comprised of an infinite range of momenta!
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(k)(k) (x)(x) k0k0 (x)(x) (k)(k) k0k0 Remember: …and, recall, even the most general whether confined by some potential OR free actually has some spatial spread within some range of boundaries!
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Fourier transforms do allow an explicit “closed” analytic form for the Dirac delta function
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Area within 1 68.26% 1.28 80.00% 1.64 90.00% 1.96 95.00% 2 95.44% 2.58 99.00% 3 99.46% 4 99.99% -2 -1 +1 +2 Let’s assume a wave packet tailored to be something like a Gaussian (or “Normal”) distribution A single “damped” pulse bounded tightly within a few of its mean postion, μ.
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For well-behaved (continuous) functions (bounded at infiinity) like f(x)=e -x 2 /2 2 Starting from: f(x)f(x) g'(x)g'(x)g(x)= e +ikx ikik f(x) is bounded oscillates in the complex plane over-all amplitude is damped at ± we can integrate this “by parts”
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Similarly, starting from:
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And so, specifically for a normal distribution: f(x)=e x 2 /2 2 differentiating: from the relation just derived: Let’s Fourier transform THIS statement i.e., apply:on both sides! 1 2 F'(k)e -ikx dk ~ ~ ~ e i(k-k)x dx ~ 1 2 (k – k) ~
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e i(k-k)x dx ~ 1 2 (k – k) ~ selecting out k=k ~ rewriting as: 0 k 0 k dk' ' ' '
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Fourier transforms of one another Gaussian distribution about the origin Now, since: we expect: Both are of the form of a Gaussian! x k 1/
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x k 1 or giving physical interpretation to the new variable x p x h
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