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Estimating Ahmed Elyamany, PhD, AVS
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EARTHWORK AND EXCAVATION bank Earth that is to be excavated is called bank measure. loose Earth that is to be hauled is called loose measure. compact Earth that is to be compacted is called compact measure. Earth after being loosened during excavation and placed in the hauling unit will increase in volume and called swell. When the earth is placed in a fill area and compacted with compaction equipment, it decrease in volume and called shrinkage.
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EARTHWORK AND EXCAVATION The correlation between volume, swell, and shrinkage are shown in the following equations: L = {1 + Sw/100}B C = {1 – Sh/100}B where L = volume of loose soil B = volume of undisturbed soil C = volume of compacted soil Sw = percentage of swell Sh = percentage of shrinkage
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EARTHWORK AND EXCAVATION Range of swell factors for some materials:
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EARTHWORK AND EXCAVATION Example Clay soil with a bank unit weight of 1.7 ton/m3 is excavated, hauled by 17 m3 (loose measure) trucks, and placed in a fill and compacted. The empty weight of the truck is 30.6 ton. The swell factor and shrinkage factor respectively are 30 and 15 percent. Calculate the following: 1. Equivalent bank measure volume and compacted measure volume for the 17 m3 truck load of soil, and 2. The total vertical weight of the hauling unit with the pay load of the soil.
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EARTHWORK AND EXCAVATION Solution Equivalent loose measure volume: L = (1+ Sw/100)B 17 m3= (1 + 30/100)B B = 17/(1 + 0.30) = 22/1.3 = 13.08 m3 bank volume. C = (1 ‐ Sh/100)B = {1 ‐ (15/100)} 13.08 = 15.04 cy compacted volume Weight of soil pay load, L1 = B1/{1+(Sw/100)} = 1.7/{1+(30/100)} = 1.7/1.3 = 1.31 ton/m3 loose weight of soil Soil pay load = 1.31 x 17= 22.23 ton Empty weight of truck = 30.6ton Total weight with pay load = 30.6 + 22.23= 52.83 ton
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Excavating by hand Numerous types and sizes of excavating equipment is generally used in construction except in very small projects where using equipment will be more expensive. Even if the job is big, sometimes there may not be sufficient room to operate the equipment such as for a motor ‐ pump foundation for a unit located in a confined space in a refinery. Also, if numerous underground utilities exist, it may be difficult to use equipment and so, under these circumstances, manual excavation has to be resorted to.
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Excavating by hand Operation Cy/hrHr/cy Excavating Sandy loam 1.0-2.00.5-1.0 Loosing earth with a pick 0.25-0.52.0-4.0 Shoveling loose earth into a truck 0.5-1.01.0-2.0 Shoveling from trenches 0.5-1.01.0-2.0 Backfilling earth into trenches 1.5-2.50.4-0.7 Spreading loose earth 4.0-7.00.15-0.25
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Excavating by hand Example A trench in a confined area in a refinery has to be excavated by hand. The trench is 15 ft long, 3 ft wide and 4 ft deep and the soil is sandy loam. Calculate the cost of excavation. Cost of labor is $15.56/hr.
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Excavating by hand Example …Solution: Quantity of work: Volume of earth = (3 x 4 x 15)/27 = 6.7cy Production rate: Using Table VI.1: Loosening earth with a pick = 6.7 x 2 hrs/cy = 13.4 hrs Shoveling loose earth into a truck = 6.7 x 1 hr/cy= 6.7 hrs Total labor hours = 20.1 hrs Cost: Total cost = 20.1 hrs x $15.56 = $312.756 Cost/cy = $312.756/6.7 = $46.68
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Excavating by machine For larger jobs, the cost of excavation by machine is considerably less than the cost by hand once the machine is transported to the job site. The savings in excavating cost must be sufficient to offset the cost of transporting the machine to the job and back to storage after the job is completed. Otherwise, hand labor is more economical.
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Trenching machines There are two types of trenching machines: (1) Wheel ‐ type and (2) Ladder-type.
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Trenching machines Wheel ‐ type machine Wheel ‐ type machine is frequently used for water mains, gas lines, and oil pipe lines. The wheel rotates at the rear of the machine, which is mounted on crawler tracks. A combination of teeth and buckets attached to the wheel loosens and removes the earth from the trench as the machine advances. The machine can be used to excavate trenches 16-20 in. wide and depths up to 6 ft. Table VI.4 provides data on this type of machines.
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Trenching machines Wheel ‐ type machine Depth of trench (ft) Width of trench (in) Digging speed (ft/hr) 2-4 16, 18, 20150-400 22, 24, 2690-300 28, 3060-180 4-6 16, 18, 2040-120 22, 24, 2625-90 28, 3015-40
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Trenching machines Ladder ‐ type machine Ladder ‐ type machine is used for deeper trenches such as those required for sewer pipes and other utilities. Inclined or vertical booms are mounted at the rear of the machine. Cutter teeth and buckets are attached to endless chains that travel along the boom. The depth of cut is adjusted by raising or lowering the boom. By adding side cutters, the width of the trench can be increased. This machine is used to excavate trenches from 16-36 in. wide and depths up to 12 ft.
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Trenching machines Ladder ‐ type machine Table VI.5 provides data on this type of machines. Depth of trench (ft) Width of trench (in) Digging speed (ft/hr) 4-6 16, 20, 22100-300 24, 26, 2875-200 30, 32, 3640-125 6-8 16, 20, 2240-125 24, 26, 2830-60 30, 32, 3625-50 8-12 18, 24, 3030-75 32, 24, 3014-40
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Trenching machines Example: Estimate the total cost and cost/linear foot for excavating 2,940 ft of trench in common earth using a ladder ‐ type trenching machine. The trench will be 30 in. wide and the average depth will be 7 ft. The machine will work for 45 min. in an hour. A machine operator, a laborer and a foreman will be employed on the job with a pickup truck. The rate for trenching machine is $87.50/hr. The machine operator is paid at $21.67/hr, the laborer is paid at $25.56/hr and the foreman is paid at $25.00/hr. The rate for pickup truck is $12.00/hr. In addition, transporting the machine to and from the job cost a lump sum of $1,500.00
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Trenching machines Example….. Solution: From Table the digging speed is found to vary between 25 and 50 ft/hr for a width of 30 in and depth of 7 ft. Use the average digging speed of 37.5 ft/hr. Time for digging trench = 2,940/37.5 = 78.4 hrs Adjusting for 45 min/hr, time required = 78.4 x (60/45) = 104.5 hrs
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Trenching machines Example….. Solution: Cost: Trenching machine : 104.5 hrs @ $87.50/hr = $9,143.75 Machine operator 104.5 hrs @ $21.67 = 2,264.50 Laborer 104.5 hrs @ $15.56 = 1,626.02 Foreman 104.5 hrs @ $25.00 = 2,612.50 Pickup truck 104.5 hrs @ $12.00 = 1,254.00 Transporting machine to and from job = 1,500.00 Total cost = $18,400.77 Cost/linear foot = $18,400.77/2,940 = $6.26
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FOUNDATIONS Foundations that support structures include footings, piles, and drilled shafts. Footings are shallow while piles and drilled shafts are deep. Footings are placed at shallow depths, usually less than 5ft. Footings may be isolated or continuous. Isolated footings are placed at one location to support a column. Continuous footing provides support for a wall of a building.
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FOUNDATIONS Construction of a footing includes excavating the soil to the required depth, erecting formwork, setting reinforcing steel, placing concrete, removing formwork, and backfilling soil above the footing to the surface of the ground. A trench is excavated into the soil to construct a continuous footing. If the sides of the excavated soil are stable enough to support itself without caving in, there is no need for providing formwork.
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FOUNDATIONS If the soil is unstable, it will be necessary to install a system of shores, braces, and solid sheeting along the excavated walls to hold the earth in position. Sheeting is typically constructed with 2,3 or 4 ‐ in thick lumber, placed side by side or overlapping along the whole length of the trench. Wales consisting of 4 x 6 ‐ in thick lumber can be placed in a horizontal direction to provide additional support for the sheeting. Depending upon the stability of the earth, it may be necessary to install braces at suitable intervals.
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FOUNDATIONS Example Estimate the cost of installing and removing solid sheeting and bracing for a trench 100 ft long and 7 ft deep. The sheeting will be 2 x 12 ‐ in lumber, 8 ft long. Two horizontal rows of 4 x 6 ‐ in wales will be placed on each side of the trench for the full length of the trench. Trench braces is placed 4 ft apart along each row of wales. The sheeting will be driven one plank at a time by using an air compressor and a pneumatic hammer. bf : board-foot is a specialized unit of measure for the volume of lumber in USA
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FOUNDATIONS Example Two laborers combined will install the sheeting at 4/hr and wales and braces at 3/hr. The following material cost will apply: sheeting $0.73/bf, wales $0.92/bf, braces $3.50 each. The following equipment cost will apply: air compressor $8.75/hr air hammer $1.75/hr. Labor costs are $21.67/hr for driving sheet piles and $18.17 for installing wales and braces. Estimate the cost of installing and removing solid sheeting and bracing
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FOUNDATIONS Example …. Solution: Quantity of materials: Sheeting, using actual dimension of 2 x 12 lumber as 1.5 in x 11.25 in Number of pieces for two sides= 100/(11.25/12) x 2 = 214 pieces. Quantity of sheeting = 214 x 2 x (12/12) x 8 = 3,424 bf
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FOUNDATIONS Example …. Solution: Quantity of materials: Wales: Number of pieces for one row = 100/8=12.5, use 13 pieces = Quantity of lumber = (13x2x2) x 4 x (6/12) x 8 = 832 bf Trench braces = (100/4) x 2= 50 Time to perform the job: 2 laborers installing sheeting = 214/4 = 53.5 hrs 2 laborers installing wales and braces = (50 + 13)/3 = 21 hrs
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FOUNDATIONS Example…..Solution: Labor cost: Laborers driving piles 53.5 hrs x 2 x $21.67 = $2,318.69 Laborers installing wales and braces = 21hrs x 2 x $18.17 = $763.14 Total labor cost = $3,081.83
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FOUNDATIONS Example…..Solution: Material cost: Sheeting 3,424 bf @ $0.73 = $2,499.52 Wales 832 bf @ $0.92 = 765.44 Braces 50 @ $3.50 = 175.00 Total material cost = $3,439.96
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FOUNDATIONS Example…..Solution: Equipment cost: Air compressor 53.5 hrs x $8.75 = $468.13 Air hammer, hose etc 53.5 hrs x $1.75 = 93.63 Total equipment cost = $561.76
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FOUNDATIONS Example…..Solution: Summary of costs: Labor = 3,081.83 Material = 3,439.96 Equipment = 561.76 Total cost = $7,083.55 Cost/linear foot of trench = $7,083.55/100 = $70.84 Cost/sf of sheeting = $7,083.55/(100 x 7 x 2) = $5.06
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