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Introduction to Nanomechanics (Spring 2012) Martino Poggio
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Introduction to Nanomechanics228.03.2012 L = 120 m w = 3 m t = 100 nm E Si = 169 GPa k = 73 m x rms = 9 Å for T = 4.2 K
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Introduction to Nanomechanics3 120 µm k = 60 N/mf = 3 kHzQ = 50,000 at 4K 100 nm thick shaft 1 µm thick mass loading Fabricated by B. Chui - IBM Ultrasensitive Cantilevers 28.03.2012
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Introduction to Nanomechanics4 350037504000 Frequency (Hz) 4250 1000 100 10 1 0.1 0.01 1E-3 1E-4 1E-5 Sprectral density (Å 2 /Hz) 28.03.2012
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Real-time detection of nuclear spin polarization 1 0 2 -2 1 0 2 -2 0102030 time (s) 405060 Natural spin fluctuations Thermal cantilever noise s X = 0.30±0.08 Å 2 2 s Y = 0.056±0.008 Å 2 2 m = 3.5 s Cantilever amplitude (Angstrom) Experiment with N ~ 10 6 spins ( 19 F in Calcium fluoride) Introduction to Nanomechanics528.03.2012
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25552560 Frequency (Hz) 255025652570 Spectral density (Å 2 /Hz) 1 0.1 100 10 1000 0.01 Cantilever thermal noise Statistically polarized spin signal from 19 F nuclei in calcium fluoride Power Spectral Density of Nuclear Spin Polarization Introduction to Nanomechanics628.03.2012
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Introduction to Nanomechanics728.03.2012
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Introduction to Nanomechanics828.03.2012
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Introduction to Nanomechanics9 What causes dissipation? 28.03.2012
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Introduction to Nanomechanics10 What causes dissipation? 28.03.2012
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How to measure dissipation? Ring-down Drive Frequency Sweep Measuring thermal noise spectrum Introduction to Nanomechanics1128.03.2012
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Introduction to Nanomechanics19 Improving cantilever dissipation 28.03.2012
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Introduction to Nanomechanics2028.03.2012
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Introduction to Nanomechanics2128.03.2012
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